Chapter 11.2, Problem 27E

To determine

To find: The magnitude of the vector.

Answer to Problem 27E

The magnitude of the vector is $\sqrt{21}\text{unit}$ .

Explanation of Solution

Given information:

The given vector is $v=\langle 1,-2,4\rangle$ .

The magnitude of the vector is calculated as,

  $\begin{array}{c}\Vert v\Vert =\sqrt{{\left(1\right)}^2+{\left(-2\right)}^2+{\left(4\right)}^2}\\ =\sqrt{21}\text{unit}\end{array}$

Therefore, the magnitude of the vector is $\sqrt{21}\text{unit}$ .