a)
To find: Draw the graph of the function for x in the specified interval and to verify that the function is non-negative in that interval.
The graph of the function f(x)=x2 in the interval [0,4] is,
Given information:
f(x)=x2 in the interval [0,4]
Calculation:
Plotting the graph
b)
To find: Draw and shade the approximating rectangles for the RRAM and to find the area.
The approximating rectangles for the RRAM and the area is,
A≈30
Given information:
f(x)=x2 in the interval [0,4]
Calculation:
The four sub-intervals are [0,1],[1,2],[2,3],[3,4]
For RRAM the upper right corners of the rectangles touch the graph of the function
Each rectangles has a base of 1 while the heights are function value at the right-hand endpoint.
A≈1+4+9=14
Subintervals | Base | Height | Area |
[0,1] | 1 | f(1)=12=1 | (1)(1)=1 |
[1,2] | 1 | f(2)=22=4 | (1)(4)=4 |
[2,3] | 1 | f(3)=32=9 | (1)(9)=9 |
[3,4] | 1 | f(4)=42=16 | (1)(16)=16 |
c)
To find: Draw and shade the approximating rectangles for the LRAM and to find the area.
The approximating rectangles for the LRAM and the area is
A≈14
Given information:
f(x)=x2 in the interval [0,4]
Calculation:
For LRAM there is no rectangle in the interval [0.1]
A≈1+4+9=14
Subintervals | Base | Height | Area |
[1,2] | 11 | f(1)=12=1 | (1)(1)=1 |
[2,3] | 1 | f(2)=22=4 | (1)(4)=4 |
[3,4] | 1 | f(3)=32=9 | (1)(9)=9 |
d)
To find: Average area of RRAM and.LRAM.
Average area of RRAM and.LRAM is 22
Given information:
f(x)=x2 in the interval [0,4]
Calculation:
Using RRAM the area is 30 and using LRAM the are is 14 the average estimate of the area is
30+142=22
Chapter 11 Solutions
PRECALCULUS:GRAPHICAL,...-NASTA ED.
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