Explanation Express coefficient of performance. COP = T H T H − T L (I) Here, temperature of low source is T L and temperature of high source is T H . Express the amount of heat added to the cycle. q H = h f g (II) Here, specific enthalpy of evaporation is h f g . Express the net work input for the cycle. W net = q H COP (III) Conclusion: Refer Table A-12, “saturated refrigerant-134a-pressure table”, and write the specific enthalpy of evaporation corresponding to pressure at state 1 of 800 kPa . h f g = 171.82 kJ / kg Refer Table A-12, “saturated refrigerant-134a-pressure table”, and write the saturated temperature corresponding to initial pressure of 800 kPa . T sat = T H = 31.31 °C Refer Table A-12, “saturated refrigerant-134a-pressure table”, and write the saturated temperature corresponding to final pressure of 140 kPa . T sat = T L = − 18.77 °C Substitute 31 .31°C for T H and − 18.77 °C for T L in Equation (I). COP = 31

CONNECT FOR THERMODYNAMICS: AN ENGINEERI

9th Edition

ISBN: 9781260048636

Author: CENGEL

Publisher: MCG

See similar textbooks

Videos

Question

Chapter 11.10, Problem 136FEP

To determine

The net work input for the cycle from the following option:

(a) 28 kJ/kg

(b) 34 kJ/kg

(c) 49 kJ/kg

(d) 144 kJ/kg

(e) 275 kJ/kg

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 11.10, Problem 135FEP

Chapter 11.10, Problem 137FEP

Students have asked these similar questions

P₂ 7+1 * P₁ ART 2 P (P₁ - P₂- Zgp) 21 / Prove that :- m² a cda A₂ == * Cde actual mip Solution

Q1/ Show that (actual 02/ A simple iet == Cda Cdf х Af 2/Y - Y+1/Y 2P(P1-P2-zxgxpr)

5. Determine the transfer function of G(s) = 01(s)/T₁(s) and 02(s)/T₁ for the mechanical system shown in Figure Q5. (Hints: assume zero initial condition) T₁(t) 01(t) 102(1) Ол N1 D1 D2 No. 1790220000 N2 Figure Q5 K2

Chapter 11 Solutions

CONNECT FOR THERMODYNAMICS: AN ENGINEERI

Ch. 11.10 - Why do we study the reversed Carnot cycle even...Ch. 11.10 - Why is the reversed Carnot cycle executed within...Ch. 11.10 - A steady-flow Carnot refrigeration cycle uses...Ch. 11.10 - Refrigerant-134a enters the condenser of a...Ch. 11.10 - Does the ideal vapor-compression refrigeration...Ch. 11.10 - Why is the throttling valve not replaced by an...Ch. 11.10 - In a refrigeration system, would you recommend...Ch. 11.10 - Does the area enclosed by the cycle on a T-s...Ch. 11.10 - Consider two vapor-compression refrigeration...Ch. 11.10 - It is proposed to use water instead of...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The net work input for the cycle from the following option: (a) 28 kJ / kg (b) 34 kJ / kg (c) 49 kJ / kg (d) 144 kJ / kg (e) 275 kJ / kg

Solution Summary: The author explains the net work input for the cycle from the following options.

Videos

The net work input for the cycle from the following option:

(a) 28 kJ/kg

(b) 34 kJ/kg

(c) 49 kJ/kg

(d) 144 kJ/kg

(e) 275 kJ/kg

Want to see the full answer?

Chapter 11 Solutions

The net work input for the cycle from the following option: (a) 28 kJ / kg (b) 34 kJ / kg (c) 49 kJ / kg (d) 144 kJ / kg (e) 275 kJ / kg

Solution Summary: The author explains the net work input for the cycle from the following options.

Videos

The net work input for the cycle from the following option: (a) 28 kJ/kg (b) 34 kJ/kg (c) 49 kJ/kg (d) 144 kJ/kg (e) 275 kJ/kg

Want to see the full answer?

Chapter 11 Solutions

The net work input for the cycle from the following option:

(a) 28 kJ/kg

(b) 34 kJ/kg

(c) 49 kJ/kg

(d) 144 kJ/kg

(e) 275 kJ/kg