Chapter 11.1, Problem 2CYU

To determine

To calculate: The perimeter and area of the given parallelogram.

Answer to Problem 2CYU

The perimeter is $P=76ft$ and the area of the given parallelogram is $A=288f{t}^2$ .

Explanation of Solution

Given information: From the given figure it can be observed that in the parallelogram $l=20ft,b=18ft,h=16ft$ .

Formula used:

The Perimeter and area of a parallelogram is given by

  $\begin{array}{l}P=2\left(l+b\right)\\ A=b\times h\\ b\text{is}\text{the}\text{base}\text{of}\text{the}\text{parallelogram}\text{.}\\ l\text{is}\text{the}\text{side}\text{adjacent}\text{to}\text{the}\text{base}\left(b\right)\text{of}\text{the}\text{parallelogram}\text{.}\\ h\text{is}\text{the}\text{height}\text{of}\text{the}\text{parallelogram}\text{.}\end{array}$

Calculation:

The given information is

  $l=20ft,b=18ft,h=16ft$

Then the perimeter of the parallelogram is

  $\begin{array}{c}P=2\times (l+b)\\ P=2\times (20+18)\\ =2\times (38)\\ P=76ft\end{array}$

And the area of the parallelogram is

  $\begin{array}{c}A=b\times h\\ \text{=18×16}\\ A=288f{t}^2\end{array}$

Therefore the perimeter is $P=76ft$ and the area of the given parallelogram is $A=288f{t}^2$ .