Chapter 11, Problem 28SGR

To determine

To find: The area of the figure.

Answer to Problem 28SGR

The area of the figure is $434{\mathrm{cm}}^2$ .

Explanation of Solution

Given Information: In figure a rectangle and semicircle are given.

Calculation: In figure a rectangle and semicircle are given.

Area of figure:

  $\begin{array}{l}=areaof\mathrm{semicircle}+areaof\mathrm{rectangle}\\ $ =\frac{22}{7}{(7)}^2+20\times 14$=22(7)+280\\ =154+280\\ =434{\mathrm{cm}}^2\end{array}$

Thus, the area of the figure is $434{\mathrm{cm}}^2$ .