Chapter 11, Problem 20PT

To determine

To calculate: The pan comes closest in area to the one that the recipe suggests.

Answer to Problem 20PT

The square pan has side $8inch$ comes closest in area to the one that the recipe suggests.

Explanation of Solution

Given Information: The receipe calls for $9inch$ diameter round pan. But todd has only square pans of sides $8,9,10$ inch.

The receipe calls for $9inch$ diameter round pan. But todd has only square pans of sides $8,9,10$ inch.

Radius of round pan $=\frac{9}{2}=4.5\mathrm{inch}$ .

Area of round pan:

  $\begin{array}{l}=\pi r^2\\ =3.14\times 4.5\times 4.5\\ =63.59inc{h}^2\end{array}$

Area of first square pan $=8\times 8=64inc{h}^2$

Area of second square pan $=9\times 9=81inc{h}^2$

Area of third square pan $=10\times 10=100inc{h}^2$

Thus, the square pan has side $8inch$ comes closest in area to the one that the recipe suggests.