(a)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central nitrogen atom in NH3
(b)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central oxygen atom in H3O+
(c)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central boron atom in BH4−
(d)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central boron atom in BCl3
(e)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central boron atom in BCl4−
(f)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central carbon atom in CCl4
(g)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central carbon atom in CHCl3
(h)
Interpretation: The geometry of the central atoms has to be predicted for the given set of compounds.
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the central atom has sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the central atom has sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the central atom has sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: The geometry for the central carbon atom in CH2Cl2
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Chapter 1 Solutions
ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT
- Part C IN H N. Br₂ (2 equiv.) AlBr3 Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and + e (×) H± 12D T EXP. L CONT. דarrow_forward9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer appropriately in the box. Only the answer in the box will be graded. (3) points) OH OH بر بد بدید 2 3arrow_forwardThere is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…arrow_forward
- A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ Marrow_forwardWhat units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?arrow_forwardProvide the structure, circle or draw, of the monomeric unit found in the biological polymeric materials given below. HO OH amylose OH OH 행 3 HO cellulose OH OH OH Ho HOarrow_forward
- OA. For the structure shown, rank the bond lengths (labeled a, b and c) from shortest to longest. Place your answer in the box. Only the answer in the box will be graded. (2 points) H -CH3 THe b Нarrow_forwardDon't used hand raitingarrow_forwardQuizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forward
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