a) The oxygen atom in dimethyl ether, CH 3 -O-CH 3 Interpretation: The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether is to be identified. Further its expected geometry is to be stated. Concept introduction: The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry. To determine: The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether and its expected geometry.

Question

Please correct answer and don't used hand raiting and don't used Ai solution

Answer 1

Question

Chapter 1.10, Problem 14P

Interpretation Introduction

a) The oxygen atom in dimethyl ether, CH₃-O-CH₃

Interpretation:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether and its expected geometry.

Interpretation Introduction

b) The nitrogen atom in trimethylamine, CH₃-N- [CH₃]₂

Interpretation:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine, is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine and its expected geometry.

Interpretation Introduction

c) The phosphorus atom in phosphine, PH₃

Interpretation:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine is to be identified. Further the expected geometry of phosphorus atom in phosphine is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the geometry of the molecule will be pyramidal.
To determine:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine and its expected geometry.

Answer:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the geometry will be pyramid.

Explanation:
Phosphorus atom has five electrons in its valence shell. It has formed three single bonds with three hydrogen atoms in phosphine. Therefore one lone pair of electrons remains on phosphorus atom. In phosphine the phosphorus atom is in sp³ hybridized state. Three of the sp³ hybrid orbitals containing single electron are utilized for forming three P-H sigma bonds. The fourth sp³ hybrid orbital accommodates the lone pair of electrons and it occupy as much space as a P-H bond does. The H-P-H bond angles deviate slightly from the normal tetrahedral angle. Hence the shape is pyramidal.

Conclusion:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the structure will be pyramidal.

Interpretation Introduction

d) The sulfur atom in the amino acid methionine

Interpretation:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine is to be identified and to state its expected geometry.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle.
To determine:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine and its expected geometry.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

Please correct answer and don't used hand raiting and don't used Ai solution

Please correct answer and don't used hand raiting

Consider the following Figure 2 and two atoms that are initially an infinite distance apart, x =00, at which point the potential energy of the system is U = 0. If they are brought together to x = x, the potential energy is related to the total force P by dU dx = P Given this, qualitatively sketch the variation of U with x. What happens at x=x? What is the significance of x = x, in terms of the potential energy? 0 P, Force 19 Attraction Total Repulsion x, Distance Figure 2. Variation with distance of the attractive, repulsive, and total forces between atoms. The slope dP/dx at the equilibrium spacing xe is proportional to the elastic modulus E; the stress σb, corresponding to the peak in total force, is the theoretical cohesive strength.

Answer 2

Question

Chapter 1.10, Problem 14P

Interpretation Introduction

a) The oxygen atom in dimethyl ether, CH₃-O-CH₃

Interpretation:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether and its expected geometry.

Interpretation Introduction

b) The nitrogen atom in trimethylamine, CH₃-N- [CH₃]₂

Interpretation:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine, is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine and its expected geometry.

Interpretation Introduction

c) The phosphorus atom in phosphine, PH₃

Interpretation:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine is to be identified. Further the expected geometry of phosphorus atom in phosphine is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the geometry of the molecule will be pyramidal.
To determine:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine and its expected geometry.

Answer:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the geometry will be pyramid.

Explanation:
Phosphorus atom has five electrons in its valence shell. It has formed three single bonds with three hydrogen atoms in phosphine. Therefore one lone pair of electrons remains on phosphorus atom. In phosphine the phosphorus atom is in sp³ hybridized state. Three of the sp³ hybrid orbitals containing single electron are utilized for forming three P-H sigma bonds. The fourth sp³ hybrid orbital accommodates the lone pair of electrons and it occupy as much space as a P-H bond does. The H-P-H bond angles deviate slightly from the normal tetrahedral angle. Hence the shape is pyramidal.

Conclusion:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the structure will be pyramidal.

Interpretation Introduction

d) The sulfur atom in the amino acid methionine

Interpretation:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine is to be identified and to state its expected geometry.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle.
To determine:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine and its expected geometry.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 3

Question

Chapter 1.10, Problem 14P

Interpretation Introduction

a) The oxygen atom in dimethyl ether, CH₃-O-CH₃

Interpretation:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether and its expected geometry.

Interpretation Introduction

b) The nitrogen atom in trimethylamine, CH₃-N- [CH₃]₂

Interpretation:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine, is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine and its expected geometry.

Interpretation Introduction

c) The phosphorus atom in phosphine, PH₃

Interpretation:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine is to be identified. Further the expected geometry of phosphorus atom in phosphine is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the geometry of the molecule will be pyramidal.
To determine:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine and its expected geometry.

Answer:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the geometry will be pyramid.

Explanation:
Phosphorus atom has five electrons in its valence shell. It has formed three single bonds with three hydrogen atoms in phosphine. Therefore one lone pair of electrons remains on phosphorus atom. In phosphine the phosphorus atom is in sp³ hybridized state. Three of the sp³ hybrid orbitals containing single electron are utilized for forming three P-H sigma bonds. The fourth sp³ hybrid orbital accommodates the lone pair of electrons and it occupy as much space as a P-H bond does. The H-P-H bond angles deviate slightly from the normal tetrahedral angle. Hence the shape is pyramidal.

Conclusion:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the structure will be pyramidal.

Interpretation Introduction

d) The sulfur atom in the amino acid methionine

Interpretation:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine is to be identified and to state its expected geometry.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle.
To determine:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine and its expected geometry.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 4

Question

Chapter 1.10, Problem 14P

Interpretation Introduction

a) The oxygen atom in dimethyl ether, CH₃-O-CH₃

Interpretation:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether and its expected geometry.

Interpretation Introduction

b) The nitrogen atom in trimethylamine, CH₃-N- [CH₃]₂

Interpretation:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine, is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine and its expected geometry.

Interpretation Introduction

c) The phosphorus atom in phosphine, PH₃

Interpretation:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine is to be identified. Further the expected geometry of phosphorus atom in phosphine is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the geometry of the molecule will be pyramidal.
To determine:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine and its expected geometry.

Answer:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the geometry will be pyramid.

Explanation:
Phosphorus atom has five electrons in its valence shell. It has formed three single bonds with three hydrogen atoms in phosphine. Therefore one lone pair of electrons remains on phosphorus atom. In phosphine the phosphorus atom is in sp³ hybridized state. Three of the sp³ hybrid orbitals containing single electron are utilized for forming three P-H sigma bonds. The fourth sp³ hybrid orbital accommodates the lone pair of electrons and it occupy as much space as a P-H bond does. The H-P-H bond angles deviate slightly from the normal tetrahedral angle. Hence the shape is pyramidal.

Conclusion:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the structure will be pyramidal.

Interpretation Introduction

d) The sulfur atom in the amino acid methionine

Interpretation:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine is to be identified and to state its expected geometry.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle.
To determine:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine and its expected geometry.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 5

Chapter 1.10, Problem 14P

Interpretation Introduction

a) The oxygen atom in dimethyl ether, CH₃-O-CH₃

Interpretation:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether and its expected geometry.

Interpretation Introduction

b) The nitrogen atom in trimethylamine, CH₃-N- [CH₃]₂

Interpretation:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine, is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine and its expected geometry.

Interpretation Introduction

c) The phosphorus atom in phosphine, PH₃

Interpretation:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine is to be identified. Further the expected geometry of phosphorus atom in phosphine is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the geometry of the molecule will be pyramidal.
To determine:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine and its expected geometry.

Answer:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the geometry will be pyramid.

Explanation:
Phosphorus atom has five electrons in its valence shell. It has formed three single bonds with three hydrogen atoms in phosphine. Therefore one lone pair of electrons remains on phosphorus atom. In phosphine the phosphorus atom is in sp³ hybridized state. Three of the sp³ hybrid orbitals containing single electron are utilized for forming three P-H sigma bonds. The fourth sp³ hybrid orbital accommodates the lone pair of electrons and it occupy as much space as a P-H bond does. The H-P-H bond angles deviate slightly from the normal tetrahedral angle. Hence the shape is pyramidal.

Conclusion:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the structure will be pyramidal.

Interpretation Introduction

d) The sulfur atom in the amino acid methionine

Interpretation:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine is to be identified and to state its expected geometry.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle.
To determine:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine and its expected geometry.

Answer 6

Chapter 1.10, Problem 14P

Interpretation Introduction

a) The oxygen atom in dimethyl ether, CH₃-O-CH₃

Interpretation:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether and its expected geometry.

Answer 7

Chapter 1.10, Problem 14P

Interpretation Introduction

a) The oxygen atom in dimethyl ether, CH₃-O-CH₃

Interpretation:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on oxygen atom in dimethyl ether and its expected geometry.

Answer 8

Interpretation Introduction

b) The nitrogen atom in trimethylamine, CH₃-N- [CH₃]₂

Interpretation:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine, is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine and its expected geometry.

Answer 9

Interpretation Introduction

b) The nitrogen atom in trimethylamine, CH₃-N- [CH₃]₂

Interpretation:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine, is to be identified. Further its expected geometry is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the molecule will not have a regular geometry.
To determine:
The number of nonbonding lone pair of electrons present on nitrogen atom in trimethylamine and its expected geometry.

Answer 10

Interpretation Introduction

c) The phosphorus atom in phosphine, PH₃

Interpretation:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine is to be identified. Further the expected geometry of phosphorus atom in phosphine is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the geometry of the molecule will be pyramidal.
To determine:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine and its expected geometry.

Answer:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the geometry will be pyramid.

Explanation:
Phosphorus atom has five electrons in its valence shell. It has formed three single bonds with three hydrogen atoms in phosphine. Therefore one lone pair of electrons remains on phosphorus atom. In phosphine the phosphorus atom is in sp³ hybridized state. Three of the sp³ hybrid orbitals containing single electron are utilized for forming three P-H sigma bonds. The fourth sp³ hybrid orbital accommodates the lone pair of electrons and it occupy as much space as a P-H bond does. The H-P-H bond angles deviate slightly from the normal tetrahedral angle. Hence the shape is pyramidal.

Conclusion:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the structure will be pyramidal.

Answer 11

Interpretation Introduction

c) The phosphorus atom in phosphine, PH₃

Interpretation:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine is to be identified. Further the expected geometry of phosphorus atom in phosphine is to be stated.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle and hence the geometry of the molecule will be pyramidal.
To determine:
The number of nonbonding lone pair of electrons present on phosphorus atom in phosphine and its expected geometry.

Answer:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the geometry will be pyramid.

Explanation:
Phosphorus atom has five electrons in its valence shell. It has formed three single bonds with three hydrogen atoms in phosphine. Therefore one lone pair of electrons remains on phosphorus atom. In phosphine the phosphorus atom is in sp³ hybridized state. Three of the sp³ hybrid orbitals containing single electron are utilized for forming three P-H sigma bonds. The fourth sp³ hybrid orbital accommodates the lone pair of electrons and it occupy as much space as a P-H bond does. The H-P-H bond angles deviate slightly from the normal tetrahedral angle. Hence the shape is pyramidal.

Conclusion:
The phosphorus atom in phosphine has one lone pair of electrons. The phosphorus atom is in sp³ hybridized state with one orbital occupied by lone pairs of electrons. Hence the structure will be pyramidal.

Answer 12

Interpretation Introduction

d) The sulfur atom in the amino acid methionine

Interpretation:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine is to be identified and to state its expected geometry.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle.
To determine:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine and its expected geometry.

Answer 13

Interpretation Introduction

d) The sulfur atom in the amino acid methionine

Interpretation:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine is to be identified and to state its expected geometry.
Concept introduction:
The electrons present in the valence shell of an atom that are not involved in bonding with other atoms are called nonbonding or lone pair of electrons. In a molecule, if an atom has only single electrons in all hybridized orbitals then the bonds formed by these orbitals will be equivalent in all respects. The molecule will thus have a regular structure. But if the atom contains single electron as well as unshared pairs of electrons in the hybridized orbitals, the orbitals with unshared pair of electrons will tend to occupy as much space as those orbitals involved in bonding. The bond angles will be slightly different from the expected bond angle.
To determine:
The number of nonbonding lone pair of electrons present on sulfur atom in the amino acid methionine and its expected geometry.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 17

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 18

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 19

Trending nowThis is a popular solution!

Answer 20

Trending nowThis is a popular solution!

Answer 21

Trending nowThis is a popular solution!

Answer 22

Trending now

Answer 23

This is a popular solution!

Answer 24

See solution

Check out sample textbook solution

Answer 25

Ch. 1.3 - Give the ground-state electron configuration for...Ch. 1.3 - How many electrons does each of the following...Ch. 1.4 - Prob. 3P Ch. 1.4 - Convert the following representation of ethane,...Ch. 1.4 - What are likely formulas for the following...Ch. 1.4 - Prob. 6P Ch. 1.4 - Prob. 7P Ch. 1.7 - Draw a line-bond structure for propane, CH3CH2CH3....Ch. 1.7 - Convert the following molecular model of hexane, a...Ch. 1.8 - Draw a line-bond structure for propene, CH3CH=CH2....

Chapter 1 Solutions