Interpretation Introduction To determine: The volume of methane at 298 K and 1.00 atm . Explanation Given: The heat of combustion of CH 4 is 890.4 kJ / mol . The heat capacity of H 2 O ( l ) is 75 .2 J / ( mol .K) . The volume of water ( V ) is 1 L = 1000 mL . The pressure of the gas ( P ) is 1 atm . The initial temperature ( T i ) is 298 K . The final temperature ( T f ) is 373 K . The ideal gas constant ( R ) is 0.0821 L atm / ( mol . K) . Explanation: The density of water ( d ) is 1 g / m L . First calculate the mass of water ( m ) as follows: The mass of water is equal to the product of density and volume of water. m = d × V Substitute 1 g / m L for d and 1000 mL for V as follows: m = 1 g / m L × 1000 mL = 1000 g So, the mass of water is 1000 g . One kilogram is equal to thousand grams. Therefore, the mass of water is 1 kg . Now, calculate the number of moles of water ( n ) as follows: The molar mass of water ( M ) is 18.01 g / mol . The number of moles of water is the ratio of the mass of water and its molar mass. n = m M Substitute 18.01 g / mol for MM and 1000 g for m as follows: n = 1000 g 18.01 g / mol = 55.525 mol So, the moles of water is 55.525 mol . The process of conversion of water to water vapor involves two sequential steps. First is the conversion of water from 298 K to water at 373 K . The amount of heat is given as follows: q water ( 1 ) = n C p Δ T Δ T = T f − T i where q water is the amount of heat required, m is the mass of water, C p is the molar heat capacity at constant pressure, Δ T is the change in temperature, T i is the initial temperature of water, and T f is the final temperature of water. Substitute 75 .2 J / ( mol K) for C p , 55.525 mol for n , 373 K for T f and 298 K for T i as follows: q water ( 1 ) = 55

Principles Of Chemistry: A Molecular Approach, Loose-leaf Edition (4th Edition)

4th Edition

ISBN: 9780134989099

Author: Nivaldo J. Tro

Publisher: PEARSON

See similar textbooks

Concept explainers

States of Matter

The substance that constitutes everything in the universe is known as matter. Matter comprises atoms which in turn are composed of electrons, protons, and neutrons. Different atoms combine together to give rise to molecules that act as a foundation for a…

Chemical Reactions and Equations

When a chemical species is transformed into another chemical species it is said to have undergone a chemical reaction. It consists of breaking existing bonds and forming new bonds by changing the position of electrons. These reactions are best explained …

Videos

Question

Chapter 11, Problem 99E

Interpretation Introduction

To determine: The volume of methane at 298 K and 1.00 atm.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 11, Problem 98E

Chapter 11, Problem 100E

Students have asked these similar questions

13.84. Chlorine atoms react with methane, forming HCI and CH3. The rate constant for the reaction is 6.0 × 107 M¹ s¹ at 298 K. When the experiment was run at three other temperatures, the following data were collected: T (K) k (M-1 s-1) 303 6.5 × 107 308 7.0 × 107 313 7.5 x 107 a. Calculate the values of the activation energy and the frequency factor for the reaction. b. What is the value of the rate constant in the lower stratosphere, where T = 218 K?

My Organic Chemistry textbook says about the formation of cyclic hemiacetals, "Such intramolecular reactions to form five- and six-membered rings are faster than the corresponding intermolecular reactions. The two reacting functional groups, in this case OH and C=O, are held in close proximity, increasing the probability of reaction."According to the book, the formation of cyclic hemiacetals occurs in acidic conditions. So my question is whether the carbonyl group in this reaction reacts first with the end alcohol on the same molecule or with the ethylene glycol. And, given the explanation in the book, if it reacts first with ethylene glycol before its own end alcohol, why would it? I don't need to know the final answer. I need to know WHY it would not undergo an intermolecular reaction prior to reacting with the ethylene glycol if that is the case. Please do not use an AI answer.

Don't used hand raiting and don't used Ai solution

Chapter 11 Solutions

Principles Of Chemistry: A Molecular Approach, Loose-leaf Edition (4th Edition)

Ch. 11 - Prob. 1SAQ Ch. 11 - Q2. Liquid nitrogen boils at 77 K. The image shown...Ch. 11 - Q3. Based on the expected intermolecular forces,...Ch. 11 - Q4. Which substance experiences dipole–dipole...Ch. 11 - Q5. One of these substances is a liquid at room...Ch. 11 - Prob. 6SAQ Ch. 11 - Q7. Determine the amount of heat (in kJ) required...Ch. 11 - Prob. 8SAQ Ch. 11 - Prob. 9SAQ Ch. 11 - Prob. 10SAQ

Ch. 11 - Prob. 1E Ch. 11 - 2. Why are intermolecular forces important? Ch. 11 - 3. What are the main properties of liquids (in...Ch. 11 - 4. What are the main properties of solids (in...Ch. 11 - Prob. 5E Ch. 11 - Prob. 6E Ch. 11 - Prob. 7E Ch. 11 - Prob. 8E Ch. 11 - Prob. 9E Ch. 11 - Prob. 10E Ch. 11 - Prob. 11E Ch. 11 - Prob. 12E Ch. 11 - 13. What is hydrogen bonding? How can you predict...Ch. 11 - Prob. 14E Ch. 11 - Prob. 15E Ch. 11 - Prob. 16E Ch. 11 - Prob. 17E Ch. 11 - Prob. 18E Ch. 11 - 19. Why is vaporization endothermic? Why is...Ch. 11 - 20. How is the volatility of a substance related...Ch. 11 - 21. What is the heat of vaporization for a liquid...Ch. 11 - 22. Explain the process of dynamic equilibrium....Ch. 11 - Prob. 23E Ch. 11 - Prob. 24E Ch. 11 - Prob. 25E Ch. 11 - 26. What is the Clausius–Clapeyron equation and...Ch. 11 - Prob. 27E Ch. 11 - Prob. 28E Ch. 11 - Prob. 29E Ch. 11 - Prob. 30E Ch. 11 - 31. Examine the heating curve for water in Section...Ch. 11 - Prob. 32E Ch. 11 - Prob. 33E Ch. 11 - Prob. 34E Ch. 11 - Prob. 35E Ch. 11 - Prob. 36E Ch. 11 - Prob. 37E Ch. 11 - Prob. 38E Ch. 11 - 39. Arrange these compounds in order of increasing...Ch. 11 - Prob. 40E Ch. 11 - Prob. 41E Ch. 11 - Prob. 42E Ch. 11 - Prob. 43E Ch. 11 - Prob. 44E Ch. 11 - Prob. 45E Ch. 11 - Prob. 46E Ch. 11 - Prob. 47E Ch. 11 - Prob. 48E Ch. 11 - Prob. 49E Ch. 11 - 50. Explain why the viscosity of multigrade motor...Ch. 11 - 51. Water in a glass tube that contains grease or...Ch. 11 - Prob. 52E Ch. 11 - Prob. 53E Ch. 11 - Prob. 54E Ch. 11 - Prob. 55E Ch. 11 - Prob. 56E Ch. 11 - 57. The human body obtains 915 kJ of energy from a...Ch. 11 - Prob. 58E Ch. 11 - Prob. 59E Ch. 11 - Prob. 60E Ch. 11 - Prob. 61E Ch. 11 - Prob. 62E Ch. 11 - Prob. 63E Ch. 11 - Prob. 64E Ch. 11 - Prob. 65E Ch. 11 - Prob. 66E Ch. 11 - Prob. 67E Ch. 11 - Prob. 68E Ch. 11 - Prob. 69E Ch. 11 - Prob. 70E Ch. 11 - Prob. 71E Ch. 11 - 72. How much heat (in kJ) is evolved in converting...Ch. 11 - Prob. 73E Ch. 11 - 74. Consider the phase diagram for iodine shown...Ch. 11 - Prob. 75E Ch. 11 - Prob. 76E Ch. 11 - Prob. 77E Ch. 11 - Prob. 78E Ch. 11 - Prob. 79E Ch. 11 - Prob. 80E Ch. 11 - Prob. 81E Ch. 11 - 82. How is the density of solid water compared to...Ch. 11 - Prob. 83E Ch. 11 - Prob. 84E Ch. 11 - Prob. 85E Ch. 11 - Prob. 86E Ch. 11 - Prob. 87E Ch. 11 - Prob. 88E Ch. 11 - Prob. 89E Ch. 11 - 90. A sample of steam with a mass of 0.552 g and...Ch. 11 - Prob. 91E Ch. 11 - Prob. 92E Ch. 11 - Prob. 93E Ch. 11 - 94. A sealed flask contains 0.55 g of water at 28...Ch. 11 - Prob. 95E Ch. 11 - 96. Consider a planet where the pressure of the...Ch. 11 - Prob. 97E Ch. 11 - 98. Given that the heat of fusion of water is...Ch. 11 - 99. The heat of combustion of CH4 is 890.4 kJ/mol,...Ch. 11 - Prob. 100E Ch. 11 - Prob. 101E Ch. 11 - 102. Butane (C4H10) has a heat of vaporization of...Ch. 11 - Prob. 103E Ch. 11 - 104. One prediction of global warming is the...Ch. 11 - Prob. 105E Ch. 11 - Prob. 106E Ch. 11 - Prob. 107E Ch. 11 - Prob. 108E Ch. 11 - Prob. 109E Ch. 11 - Prob. 110E Ch. 11 - Prob. 111E Ch. 11 - Prob. 112E Ch. 11 - Prob. 113QGW Ch. 11 - Prob. 114QGW Ch. 11 - Prob. 115QGW Ch. 11 - Prob. 116QGW Ch. 11 - 117. Students in a chemistry laboratory course are...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.