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Statistics, Books a la Carte Edition Plus MyLab Statistics with Pearson eText -- Access Card Package (4th Edition)
4th Edition
ISBN: 9780134435855
Author: Alan Agresti, Christine A. Franklin, Bernhard Klingenberg
Publisher: PEARSON
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Textbook Question
Chapter 11, Problem 82CP
Multiple response variables Each subject in a sample of 100 men and 100 women is asked to indicate which of the following factors (one or more) are responsible for increases in crime committed by teenagers: A–the increasing gap in income between the rich and poor, B–the increase in the percentage of single-parent families, C–insufficient time that parents spend with their children. To analyze whether responses differ by gender of respondent, we cross-classify the responses by gender, as the table shows.
- a. Is it valid to apply the chi-squared test of independence to these data? Explain.
- b. Explain how this table actually provides information needed to cross-classify gender with each of three variables. Construct the
contingency table relating gender to opinion about whether factor A is responsible for increases in teenage crime.
Expert Solution & Answer
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Students have asked these similar questions
29% of all college students major in STEM (Science, Technology, Engineering, and Math). If 46 college students are randomly selected, find the probability thata. Exactly 11 of them major in STEM. b. At most 12 of them major in STEM. c. At least 11 of them major in STEM. d. Between 11 and 15 (including 11 and 15) of them major in STEM.
Please solving problem2
Problem1
We consider a two-period binomial model with the following properties: each period lastsone (1) year and the current stock price is S0 = 4. On each period, the stock price doubleswhen it moves up and is reduced by half when it moves down. The annual interest rateon the money market is 25%. (This model is the same as in Prob. 1 of HW#2).We consider four options on this market: A European call option with maturity T = 2 years and strike price K = 5; A European put option with maturity T = 2 years and strike price K = 5; An American call option with maturity T = 2 years and strike price K = 5; An American put option with maturity T = 2 years and strike price K = 5.(a) Find the price at time 0 of both European options.(b) Find the price at time 0 of both American options. Compare your results with (a)and comment.(c) For each of the American options, describe the optimal exercising strategy.
Problem 1.We consider a two-period binomial model with the following properties: each period lastsone (1) year and the current stock price is S0 = 4. On each period, the stock price doubleswhen it moves up and is reduced by half when it moves down. The annual interest rateon the money market is 25%.
We consider four options on this market: A European call option with maturity T = 2 years and strike price K = 5; A European put option with maturity T = 2 years and strike price K = 5; An American call option with maturity T = 2 years and strike price K = 5; An American put option with maturity T = 2 years and strike price K = 5.(a) Find the price at time 0 of both European options.(b) Find the price at time 0 of both American options. Compare your results with (a)and comment.(c) For each of the American options, describe the optimal exercising strategy.(d) We assume that you sell the American put to a market participant A for the pricefound in (b). Explain how you act on the market…
Chapter 11 Solutions
Statistics, Books a la Carte Edition Plus MyLab Statistics with Pearson eText -- Access Card Package (4th Edition)
Ch. 11.1 - Gender gap in politics? In the United States, is...Ch. 11.1 - Prob. 2PBCh. 11.1 - Williams College admission Data from 2013 posted...Ch. 11.1 - Prob. 4PBCh. 11.1 - Marital happiness and income In the GSS, subjects...Ch. 11.1 - What is independent of happiness? Which one of the...Ch. 11.1 - Sample evidence about independence Refer to the...Ch. 11.2 - Life after death and gender In the 2012 GSS, 605...Ch. 11.2 - Happiness and gender For the 2 3 table on gender...Ch. 11.2 - Prob. 10PB
Ch. 11.2 - Marital happiness and income In Exercise 11.5 when...Ch. 11.2 - First and second free throw independent? In pro...Ch. 11.2 - Cigarettes and marijuana The table on the...Ch. 11.2 - Prob. 14PBCh. 11.2 - Help the environment In 2010 the GSS asked whether...Ch. 11.2 - Prob. 16PBCh. 11.2 - Aspirin and heart attacks A Swedish study used...Ch. 11.2 - z test for heart attack study Refer to the...Ch. 11.2 - Severity of fever after flu shot The study...Ch. 11.2 - Prob. 20PBCh. 11.2 - Testing a genetic theory In an experiment on...Ch. 11.2 - Birthdays by quarters Based on a random sample of...Ch. 11.2 - Checking a roulette wheel Karl Pearson devised the...Ch. 11.3 - Democrat, race, and gender The two tables show...Ch. 11.3 - Death penalty associations Table 11.10, summarized...Ch. 11.3 - Smoking and alcohol The table refers to a survey...Ch. 11.3 - Sex of victim and offender For murders in the...Ch. 11.3 - Smelling and mortality A recent study (Pinto et...Ch. 11.3 - Vioxx In September 2004, the pharmaceutical...Ch. 11.3 - Egg and cell derived vaccine When comparing the...Ch. 11.3 - Risk of dying for teenagers According to...Ch. 11.3 - Marital happiness The table shows 2012 GSS data on...Ch. 11.3 - Party ID and gender The table shows the 2012 GSS...Ch. 11.3 - Chi-squared versus measuring association For the...Ch. 11.4 - Standardized residuals for happiness and income...Ch. 11.4 - Prob. 36PBCh. 11.4 - Prob. 37PBCh. 11.4 - Prob. 38PBCh. 11.4 - Prob. 39PBCh. 11.4 - Prob. 40PBCh. 11.5 - Keeping old dogs mentally sharp In an experiment...Ch. 11.5 - Prob. 43PBCh. 11.5 - Prob. 44PBCh. 11.5 - Prob. 46PBCh. 11 - Female for president? When recent General Social...Ch. 11 - Prob. 48CPCh. 11 - Down and chi-squared For the data in the previous...Ch. 11 - Prob. 50CPCh. 11 - Prob. 51CPCh. 11 - Prob. 52CPCh. 11 - Prob. 53CPCh. 11 - Prob. 54CPCh. 11 - Prob. 55CPCh. 11 - Prob. 56CPCh. 11 - Seat belt helps? The table refers to passengers in...Ch. 11 - Prob. 58CPCh. 11 - Prob. 59CPCh. 11 - Prob. 60CPCh. 11 - Prob. 61CPCh. 11 - Prob. 62CPCh. 11 - Prob. 63CPCh. 11 - Prob. 64CPCh. 11 - Clarity of diamonds Does the clarity of a diamond...Ch. 11 - Benfords Law When looking at a collection of...Ch. 11 - Prob. 67CPCh. 11 - Prob. 68CPCh. 11 - Prob. 70CPCh. 11 - Prob. 71CPCh. 11 - Prob. 72CPCh. 11 - Prob. 73CPCh. 11 - Prob. 74CPCh. 11 - Prob. 75CPCh. 11 - Prob. 76CPCh. 11 - Prob. 77CPCh. 11 - Prob. 78CPCh. 11 - Prob. 79CPCh. 11 - Statistical versus practical significance In any...Ch. 11 - Prob. 81CPCh. 11 - Multiple response variables Each subject in a...Ch. 11 - Standardized residuals for 2 2 tables The table...Ch. 11 - Prob. 84CPCh. 11 - Prob. 85CPCh. 11 - Prob. 86CPCh. 11 - Prob. 87CPCh. 11 - Prob. 88CPCh. 11 - Voting with 16 A recent survey of Austrian high...
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