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(a)
Interpretation:
The mechanism of the given reaction should be proposed.
Concept introduction:
In the presence of acid catalyst, this reaction takes place through partial
Epoxides are reactive, methoxide ion attacks epoxides in a less sterically hindered position which forms the alkoxide ion, and then it gets proton from alcohol which form the product.
(b)
Interpretation:
The structure of all products that formed in the given reaction should be drawn.
Concept introduction:
In the presence of acid catalyst, this reaction takes place through partial
Epoxides are reactive, methoxide ion attacks epoxides in a less sterically hindered position which forms the alkoxide ion, and then it gets proton from alcohol which form the product.
(c)
Interpretation:
The reason should be explained for the formation of six member ring compound in the given reaction.
Concept introduction:
In the presence of acid catalyst, this reaction takes place through partial
Epoxides are reactive, methoxide ion attacks epoxides in a less sterically hindered position which forms the alkoxide ion, and then it gets proton from alcohol which form the product.
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Chapter 11 Solutions
Organic Chemistry
- Nonearrow_forwardNonearrow_forwardman Campus Depa (a) Draw the three products (constitutional isomers) obtained when 2-methyl-3-hexene reacts with water and a trace of H2SO4. Hint: one product forms as the result of a 1,2-hydride shift. (1.5 pts) This is the acid-catalyzed alkene hydration reaction.arrow_forward
- (6 pts - 2 pts each part) Although we focused our discussion on hydrogen light emission, all elements have distinctive emission spectra. Sodium (Na) is famous for its spectrum being dominated by two yellow emission lines at 589.0 and 589.6 nm, respectively. These lines result from electrons relaxing to the 3s subshell. a. What is the photon energy (in J) for one of these emission lines? Show your work. b. To what electronic transition in hydrogen is this photon energy closest to? Justify your answer-you shouldn't need to do numerical calculations. c. Consider the 3s subshell energy for Na - use 0 eV as the reference point for n=∞. What is the energy of the subshell that the electron relaxes from? Choose the same emission line that you did for part (a) and show your work.arrow_forwardNonearrow_forward(9 Pts) In one of the two Rare Earth element rows of the periodic table, identify an exception to the general ionization energy (IE) trend. For the two elements involved, answer the following questions. Be sure to cite sources for all physical data that you use. a. (2 pts) Identify the two elements and write their electronic configurations. b. (2 pts) Based on their configurations, propose a reason for the IE trend exception. c. (5 pts) Calculate effective nuclear charges for the last electron in each element and the Allred-Rochow electronegativity values for the two elements. Can any of these values explain the IE trend exception? Explain how (not) - include a description of how IE relates to electronegativity.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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