EXCURSIONS IN MOD.MATH W/ACCESS >BI<
9th Edition
ISBN: 9781323788721
Author: Tannenbaum
Publisher: PEARSON C
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Chapter 11, Problem 75E
To determine
To list:
All the symmetries of the given wallpaper pattern.
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ind
Original: 100-200 = 20,000
200400=20,000 80
602=3600 694761
=4
4x1.3225-6.29
4761/3600 = 1-3225 5.29-1058msy
6). The dose to the body was 200 mSv. Find
the dose to the lung in mrem?
W 200ms
20
2.15
and
8) A technique of 20 mAs, 40 kV produces a
f4 Sy Find the dose to the Thyroid in
Chapter 11 Solutions
EXCURSIONS IN MOD.MATH W/ACCESS >BI<
Ch. 11 - In Fig.1135_, indicate which point is the image of...Ch. 11 - Prob. 2ECh. 11 - Prob. 3ECh. 11 - In Fig. 11-38, P is the image of P under a...Ch. 11 - In Fig.11-39, l is the axis of reflection. a.Find...Ch. 11 - In Fig. 11-40, l is the axis of reflection. a....Ch. 11 - Prob. 7ECh. 11 - In Fig 11-42, P is the image of P under a...Ch. 11 - In Fig. 11-43, P is image of P under a reflection....Ch. 11 - Prob. 10E
Ch. 11 - In Fig. 11-45, A and B are fixed points of a...Ch. 11 - Prob. 12ECh. 11 - In Fig. 11-47, indicate which point is a. the...Ch. 11 - Prob. 14ECh. 11 - In each case, give an answer between 0 and 360. 1....Ch. 11 - Prob. 16ECh. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 - Prob. 19ECh. 11 - Prob. 20ECh. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - In Fig. 11-54, indicate which point is the image...Ch. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - In Fig. 11-57, Q is the image of Q under a...Ch. 11 - In Fig. 11-58, D is the image of D under a...Ch. 11 - Prob. 28ECh. 11 - Prob. 29ECh. 11 - Prob. 30ECh. 11 - Prob. 31ECh. 11 - In Fig 11-63, P is the image of P under a glide...Ch. 11 - In Fig.11-64, B is the image of B and D is the...Ch. 11 - Prob. 34ECh. 11 - Prob. 35ECh. 11 - Prob. 36ECh. 11 - In Fig 11-68, D is the image of D and C is the...Ch. 11 - In Fig11-69, A is the image of A and D is the...Ch. 11 - Prob. 39ECh. 11 - Prob. 40ECh. 11 - Prob. 41ECh. 11 - Prob. 42ECh. 11 - Prob. 43ECh. 11 - Prob. 44ECh. 11 - Prob. 45ECh. 11 - Prob. 46ECh. 11 - Find the symmetry type for each of the following...Ch. 11 - Prob. 48ECh. 11 - Prob. 49ECh. 11 - Prob. 50ECh. 11 - Prob. 51ECh. 11 - Prob. 52ECh. 11 - Prob. 53ECh. 11 - Prob. 54ECh. 11 - Prob. 55ECh. 11 - Prob. 56ECh. 11 - Prob. 57ECh. 11 - Prob. 58ECh. 11 - Prob. 59ECh. 11 - Prob. 60ECh. 11 - Prob. 61ECh. 11 - Prob. 62ECh. 11 - Prob. 63ECh. 11 - Prob. 64ECh. 11 - Suppose that a rigid motion M is the product of a...Ch. 11 - Prob. 66ECh. 11 - Prob. 67ECh. 11 - Prob. 68ECh. 11 - Prob. 69ECh. 11 - Prob. 70ECh. 11 - Prob. 71ECh. 11 - Prob. 72ECh. 11 - Prob. 73ECh. 11 - Prob. 74ECh. 11 - Prob. 75ECh. 11 - Prob. 76ECh. 11 - Prob. 77ECh. 11 - Prob. 78ECh. 11 - Prob. 79ECh. 11 - Prob. 80E
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- original ssD 400x (100) 2 400 x (14)=100 34 10or (2)² = 100 × (0-85) = 100 x = 72.25 100x 40 72.25 =36.13 500 36.13 13.84 O. 7225 12x13.84≈ 166.08mAs 10) The dose of a radiograph was 100 mSv with a technique of: 10 mAs, 180 kV at 200 cm and tabletop. If the technique is changed to: 20 mAs, 153 kV at 100 cm using a 5:1 grid then find the new dose in rem to the Lungs. 11) A radiographic technique produces an exposure index of EI= 300 and TEI=600 at a source- to-image receptor distance (SID) of 200 cm, 100 kV, 5:1 grid using 10 mAs. If the technique is changed to 100 cm and 85 kV and 5 mAs with table top find the new exposure index? What is the value of DI? 10arrow_forwardexam review please help!arrow_forward0. 75 and 34 KV arved fromise to 75 halfed NAME Genesis Ward 0 mAs is 40 #2). A technique involves 150 mAs, 40 kV and produces an intensity of 2 R. are gone down KV C15%! In = 200% Find the new intensity in mGya, using 300 mAs and 46 kV? =100 206a 150mAS 40KV 2R kv 150 is so divide 00 mA, 200 alue of 100. Boomts 46KY 4). A technique is taken with 100 mA, 200 ms, 60 kV and produces 200 mSv.arrow_forward
- Fi is 2 O 2 ms, #3). A technique is taken with 100 mA, 200 60 kV and produces an EI value of 100. Find the EI value when this technique is changed to 200 mA, 100 ms, 69 kV? 4) m 2arrow_forward11) A radiographic technique produces an exposure index of EI= 300 and TEI=600 at a source- to-image receptor distance (SID) of 200 cm, 100 kV, 5:1 grid using 10 mAs. If the technique is changed to 100 cm and 85 kV and 5 mAs with table top find the new exposure index? What is the value of DI?arrow_forwardexam review please help!arrow_forward
- 5). The dose to the breast was 120 mGy find the entire body dose represented in rad?arrow_forward1000 x= 800mGy to body X= = rad 7). If EI=300, TEI=500 with mAs = 20 and you want to decrease the kV by 15% then 0.8 Gy what is the new mAs value to set DI=0? =0% 100-00 Dorad 8) A te dose of rem w kV? 2 tom i sv 4sv 48rem to thyr. KV+ I formula K In = Fox2 kV (1979) (48 rem = 8.2 = 16. SVx 100 160oren-body 1600.0.03=X I M M Earrow_forwardCan you solve question 3,4,5 and 6 numerical method use all data i given to you and teach mearrow_forward
- 8 If f(x + y) = f(x)f(y) and Σ f (x) = 2, x, y = N, x=1 where N is the set of all natural number, then the f(4) value of is. f(2)arrow_forward- Consider the following system of linear equations in the variables a,b,c,d: 5a-3b 7c - 2d = 2 2ab 2c+ 5d = -3 → (*) 4a 3b 5d = 3 6a b+2c+ 7d = −7 (a) Solve the system (*) by using Gauss elimination method. (b) Solve the system (*) by using Cramer's rule method.arrow_forwardSolve for a 25 55 30 a=?arrow_forward
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