Chapter 11, Problem 64QP

Interpretation Introduction

Interpretation:

The number of moles of sucrose $\left({\text{C}}_{12}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\right)$ present in $50\text{g}$ of $0.85\text{m}$ solution is to be calculated.

Concept Introduction:

${\text{C}}_{12}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is a polar molecule having many hydroxyl groups and water is a polar solvent. Thus, ${\text{C}}_{12}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ is easily soluble in water by hydrogen bonding. Molality is the ratio of the moles of solute and the mass of the solvent in kilograms. The unit of molality is expressed in ${\text{mol kg}}^{-1}$ .