Explanation Given info : The angle of incidence ( θ i ) is 38°. Both rocks have the same young elastic modulus ( E ). The specific gravity changes from S G 1 =3.6 to S G 2 =2.5. Formula used : From the law of refraction: sin ( θ r ) sin ( θ i ) = v 2 v 1 (1) Where, θ r is the angle of refraction θ i is the incident angle v 2 is the speed of the wave in the second medium (second rock) v 1 is the speed of the wave in the first medium (first rock) For a longitudinal wave between rocks the speed ( v ) is defined as v = E ρ (2) Where E is the elastic modulus ρ is the density of the material Therefore, the speed of the wave at the first rock v 1 is v 1 = E ρ 1 (3) Similarly, for the second rock the wave speed v 2 is v 2 = E ρ 2 (4) Calculation: Replacing (3) and (4) into equation (1) sin ( θ r ) sin ( θ i ) = ρ 2 ρ 1 <

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Chapter 11, Problem 60P

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The angle of refraction θr .

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Physics: Principles and Applications -- Pearson e Text Instant Access (Pearson+)

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