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Physics: Principles and Applications -- Pearson e Text Instant Access (Pearson+)
7th Edition
ISBN: 9780137679065
Author: Douglas Giancoli
Publisher: PEARSON+
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Chapter 11, Problem 27Q
To determine
Explain why AM radio signals can usually be heard behind a hill, but FM often cannot.
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Chapter 11 Solutions
Physics: Principles and Applications -- Pearson e Text Instant Access (Pearson+)
Ch. 11 - Prob. 1OQCh. 11 - Prob. 2OQCh. 11 - 1. Is the acceleration of a simple harmonic...Ch. 11 - Prob. 2QCh. 11 - How could you double the maximum speed of a simple...Ch. 11 - 4.If a pendulum clock isaccurate at sea level,...Ch. 11 - Prob. 5QCh. 11 - For a simple harmonic oscillator, when (if ever)...Ch. 11 - Two equal masses are attached to separate...Ch. 11 - S. What is the approximate period of your walking...
Ch. 11 - What happens to the period of a playground swing...Ch. 11 - Why can you make water slosh back and forth in a...Ch. 11 - Is the frequency of a simple periodic wave equal...Ch. 11 - Prob. 12QCh. 11 - What kind of waves do you think will travel along...Ch. 11 - Since the density of air decreases with an...Ch. 11 - Prob. 15QCh. 11 - How did geophysicists determine that part of the...Ch. 11 - Prob. 17QCh. 11 - Prob. 18QCh. 11 - Prob. 19QCh. 11 - Prob. 20QCh. 11 - Prob. 21QCh. 11 - Prob. 22QCh. 11 - Why do the strings used for the lowest-frequency...Ch. 11 - Prob. 24QCh. 11 - Prob. 25QCh. 11 - Prob. 26QCh. 11 - Prob. 27QCh. 11 - Prob. 1MCQCh. 11 - 2. An object oscillates back and forth on the end...Ch. 11 - Prob. 3MCQCh. 11 - Prob. 4MCQCh. 11 - Prob. 5MCQCh. 11 - Prob. 6MCQCh. 11 - At a playground, two young children are on...Ch. 11 - Prob. 8MCQCh. 11 - Prob. 9MCQCh. 11 - Prob. 10MCQCh. 11 - Prob. 11MCQCh. 11 - Prob. 12MCQCh. 11 - Prob. 13MCQCh. 11 - A student attaches one end of a Slinky to the top...Ch. 11 - Prob. 15MCQCh. 11 - If a particle undergoes SHM with amplitude 0.21 m,...Ch. 11 - 2. (I) The springs of a 1700-kg car compress 5.0...Ch. 11 - An elastic cord is 61 cm long when a weight of 75...Ch. 11 - 4 (II) Estimate the stiffness of the spring in a...Ch. 11 - A fisherman's scale stretches 3.6 cm when a 2.4-kg...Ch. 11 - Prob. 6PCh. 11 - A mass mat the end of a spring oscillates with a...Ch. 11 - Prob. 8PCh. 11 - Figure 11-51 |O shows two examples of SHM, labeled...Ch. 11 - Prob. 10PCh. 11 - Prob. 11PCh. 11 - Prob. 12PCh. 11 - A 1.65-kg mass stretches a vertical spring 0.215...Ch. 11 - A 1 15-kg mass oscillates according to the...Ch. 11 - A 0.25-kg mass at the end of a spring oscillates...Ch. 11 - It takes a force of 91.0 N to compress the spring...Ch. 11 - Prob. 17PCh. 11 - Prob. 18PCh. 11 - A mass resting on a horizontal, frictionless...Ch. 11 - Prob. 20PCh. 11 - Prob. 21PCh. 11 - Prob. 22PCh. 11 - Prob. 23PCh. 11 - Prob. 24PCh. 11 - 25 (III) A 1.60-kg object oscillates at the end of...Ch. 11 - 26. (Ill) Consider two objects, A and B, both...Ch. 11 - A pendulum has a period of 1.85 s on Earth. Whatis...Ch. 11 - How long must a simple pendulum be if it is to...Ch. 11 - A pendulum makes 28 oscillations in exactly 50 s....Ch. 11 - Prob. 30PCh. 11 - Your grandfather clock's pendulum has a length of...Ch. 11 - Prob. 32PCh. 11 - Prob. 33PCh. 11 - 34 (III) A clock pendulum oscillates at a...Ch. 11 - A fisherman notices that wave crests pass the bow...Ch. 11 - A sound wave in air has a frequency of 282 Hz and...Ch. 11 - Prob. 37PCh. 11 - AM radio signals have frequencies between 550 kHz...Ch. 11 - Prob. 39PCh. 11 - A cord of mass 0.65 kg is stretched between two...Ch. 11 - A 0.40-kg cord is stretched between two supports,...Ch. 11 - Prob. 42PCh. 11 - Prob. 43PCh. 11 - Prob. 44PCh. 11 - 45 (II) The intensity of an earthquake wave...Ch. 11 - Prob. 46PCh. 11 - Prob. 47PCh. 11 - Prob. 48PCh. 11 - Prob. 49PCh. 11 - Prob. 50PCh. 11 - Prob. 51PCh. 11 - Prob. 52PCh. 11 - Prob. 53PCh. 11 - A guitar string is 92 cm long and has a mass of...Ch. 11 - One end of a horizontal string is attached to a...Ch. 11 - Prob. 56PCh. 11 - Prob. 57PCh. 11 - Prob. 58PCh. 11 - Prob. 59PCh. 11 - Prob. 60PCh. 11 - 61. What frequency of sound would have a...Ch. 11 - Prob. 62GPCh. 11 - An energy-absorbing car bumper has a spring...Ch. 11 - Prob. 64GPCh. 11 - A block of mass mis suspended from a ceiling by a...Ch. 11 - 66. A block with mass m =6.0 kg rests on a...Ch. 11 - Prob. 67GPCh. 11 - Prob. 68GPCh. 11 - Prob. 69GPCh. 11 - Prob. 70GPCh. 11 - A 320-kg wooden raft floats on a lake. When a...Ch. 11 - Prob. 72GPCh. 11 - Prob. 73GPCh. 11 - Prob. 74GPCh. 11 - Carbon dioxide is a linear molecule The...Ch. 11 - Prob. 76GPCh. 11 - Prob. 77GPCh. 11 - Prob. 78GPCh. 11 - Prob. 79GPCh. 11 - Prob. 80GPCh. 11 - Prob. 81GPCh. 11 - Prob. 82GPCh. 11 - The ripples in certain groove 10.2 cm from the...Ch. 11 - Prob. 84GPCh. 11 - Prob. 85GPCh. 11 - Prob. 86GPCh. 11 - Prob. 87GP
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- 1. The average KE and temperature in Kelvin of the molecules of a gas are related by the equation KE = 3/2 KT where k is the Boltzmann constant 1.38 x 10 m² kg s². The diagram shows the energy levels for a Hydrogen atom. Energy/eV 0.00 -1.51 3.39 13.58 Use this information to show that Hydrogen at room temperature will not emit light. 2. When hydrogen burns in oxygen 241.8 kJ of energy are released per mole. Show that this reaction can produce light.arrow_forward3. By using the fact that around any closed loop the sum of the EMFS = the sum of the PDs. Write equations for the two loops shown in the cct below. 40 ΔΩ I₂ 4V (loop1 20 (loop2) 2v I+12 Use these equations to show that the current flowing through the 20 resistor is 0.75Aarrow_forward5. A potential divider circuit is made by stretching a 1 m long wire with a resistance of 0.1 per cm from A to B as shown. 8V A 100cm B sliding contact 5Ω A varying PD is achieved across the 5 Q resistor by moving the slider along the resistance wire. Calculate the distance from A when the PD across the 5 Q resistor is 6 V.arrow_forward
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- 1. At 0°C a steel cable is 1km long and 1cm diameter when it is heated it expands and its resistivity increases. Calculate the change in resistance of the cable as it is heated from 0-20°C The temperature coefficient of resistance a, gives the fractional increase in resistance per °C. So increase in resistance AR = Ra.AT Where R, is the resistance at 0°C For steel a, 0.003 °C The coefficient of linear expansion a- gives the fractional increase in length per °C temperature rise. So increase in Length AL La-AT Where L, is the length at 0°C For steel a₁ = 12 x 10 °C-1 The resistivity of steel at 0°C = 1.2 x 10 Qmarrow_forward1. F E 6V 10 1.1. B a 6V b C C Apply Kirchoff's 1st law to point C for the circuit above Apply Kirchoff's 2nd Law to loops: a. ABCFA b. ABDEA C. FCDEF d. Find values for currents a,b and c Darrow_forward2. The results of the Rutherford experiment can be categorized in 3 statements. Fill in the missing words Most 11. Some III. A few State which result gives evidence that the nucleus is a. heavier than an alpha particle b. very small compared to the size of the atom c. positively charged 3. Using values in the diagram derive an expression for r .0 e marrow_forward
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