EBK ENHANCED DISCOVERING COMPUTERS & MI
1st Edition
ISBN: 8220100606922
Author: Vermaat
Publisher: YUZU
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Chapter 11, Problem 4PS
Program Plan Intro
Given information:
- Users have got a free copy of credit report and notices that many companies accessed credit report without user’s permission and knowledge and this may occur due to some soft inquiries.
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1.[30 pts] Computers generate color pictures on a video screen or liquid crystal display by
mixing three different colors of light: red, green, and blue. Imagine a simple scheme, with
three different lights, each of which can be turned on or off, projecting onto a glass screen:
We can create eight different colors based on the absence (0) or presence (1) of light
sources R,G and B:
R
G
B
Color
0
0
0
Black
0
0
1
Blue
0
1
0
Green
0
1
1
Cyan
1
0
0
Red
1
0
1
Magenta
1
1
1
0
Yellow
1
White
1
Each of these colors can be represented as a bit vector of length 3, and we can apply
Boolean operations to them.
a. The complement of a color is formed by turning off the lights that are on and turning
on the lights that are off. What would be the complement of each of the eight colors
listed above?
b. Describe the effect of applying Boolean operations on the following colors:
Λ
1. Red(100) ^ Magenta(101)= Blue(001)
2. Bue(001) | Green(010)=
3. Yellow(100) & Cyan(011)=
2.[30 pts] Perform the following…
D. S. Malik, Data Structures Using C++, 2nd Edition, 2010
Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
method #2, which calculates the square root of positive doubles (also works for integers).
public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
Program-it-Yourself: In the main method, create a program that…
Chapter 11 Solutions
EBK ENHANCED DISCOVERING COMPUTERS & MI
Ch. 11 - Define the terms, database and database software....Ch. 11 - Prob. 2SGCh. 11 - Prob. 3SGCh. 11 - Prob. 4SGCh. 11 - Prob. 5SGCh. 11 - Explain how a DBMS might manage deleted or...Ch. 11 - Prob. 7SGCh. 11 - Prob. 8SGCh. 11 - Prob. 9SGCh. 11 - Prob. 10SG
Ch. 11 - Prob. 11SGCh. 11 - Prob. 12SGCh. 11 - Prob. 13SGCh. 11 - Prob. 14SGCh. 11 - Prob. 15SGCh. 11 - Prob. 16SGCh. 11 - Prob. 17SGCh. 11 - A(n) _____ is a request for specific information...Ch. 11 - Prob. 19SGCh. 11 - Prob. 20SGCh. 11 - Prob. 21SGCh. 11 - Prob. 22SGCh. 11 - Prob. 23SGCh. 11 - Prob. 24SGCh. 11 - Prob. 25SGCh. 11 - Prob. 26SGCh. 11 - Prob. 27SGCh. 11 - Prob. 28SGCh. 11 - Prob. 29SGCh. 11 - Prob. 30SGCh. 11 - Prob. 31SGCh. 11 - Prob. 32SGCh. 11 - Prob. 33SGCh. 11 - Prob. 34SGCh. 11 - Prob. 35SGCh. 11 - Prob. 36SGCh. 11 - Prob. 37SGCh. 11 - Prob. 38SGCh. 11 - Prob. 39SGCh. 11 - Prob. 40SGCh. 11 - Prob. 41SGCh. 11 - Prob. 42SGCh. 11 - Prob. 43SGCh. 11 - Define the following terms: programming language,...Ch. 11 - Prob. 45SGCh. 11 - Define the terms, procedural language, compiler,...Ch. 11 - Prob. 47SGCh. 11 - Prob. 48SGCh. 11 - Prob. 49SGCh. 11 - Prob. 1TFCh. 11 - Prob. 2TFCh. 11 - Prob. 3TFCh. 11 - Prob. 4TFCh. 11 - Prob. 5TFCh. 11 - Prob. 6TFCh. 11 - Prob. 7TFCh. 11 - Prob. 8TFCh. 11 - One way to secure a database is to allow only...Ch. 11 - In a rollforward, the DBMS uses the log to undo...Ch. 11 - Prob. 11TFCh. 11 - Prob. 12TFCh. 11 - Prob. 1MCCh. 11 - Prob. 2MCCh. 11 - Prob. 3MCCh. 11 - Prob. 4MCCh. 11 - Prob. 5MCCh. 11 - Prob. 6MCCh. 11 - _____ feasibility measures whether an organization...Ch. 11 - Prob. 8MCCh. 11 - Prob. 1MCh. 11 - Prob. 2MCh. 11 - Prob. 3MCh. 11 - Prob. 4MCh. 11 - Prob. 5MCh. 11 - Prob. 6MCh. 11 - Prob. 7MCh. 11 - Prob. 8MCh. 11 - Prob. 9MCh. 11 - Prob. 10MCh. 11 - Prob. 2CTCh. 11 - Prob. 3CTCh. 11 - What is function creep?Ch. 11 - Prob. 5CTCh. 11 - Prob. 6CTCh. 11 - Prob. 7CTCh. 11 - Prob. 8CTCh. 11 - Prob. 9CTCh. 11 - Prob. 10CTCh. 11 - Prob. 11CTCh. 11 - Prob. 12CTCh. 11 - Prob. 13CTCh. 11 - Prob. 14CTCh. 11 - Prob. 15CTCh. 11 - Prob. 16CTCh. 11 - Prob. 17CTCh. 11 - Prob. 18CTCh. 11 - Prob. 19CTCh. 11 - Prob. 20CTCh. 11 - Prob. 21CTCh. 11 - Prob. 22CTCh. 11 - Prob. 23CTCh. 11 - Prob. 24CTCh. 11 - Prob. 25CTCh. 11 - Prob. 26CTCh. 11 - Prob. 27CTCh. 11 - Prob. 28CTCh. 11 - Prob. 1PSCh. 11 - Prob. 2PSCh. 11 - Prob. 3PSCh. 11 - Prob. 4PSCh. 11 - Prob. 5PSCh. 11 - Prob. 6PSCh. 11 - Prob. 7PSCh. 11 - Prob. 8PSCh. 11 - Database Recovery Your boss has informed you that...Ch. 11 - Prob. 10PSCh. 11 - Prob. 11PSCh. 11 - Prob. 1.1ECh. 11 - Prob. 1.2ECh. 11 - Prob. 1.3ECh. 11 - Prob. 2.1ECh. 11 - Prob. 2.2ECh. 11 - Prob. 2.3ECh. 11 - Prob. 3.1ECh. 11 - Prob. 3.2ECh. 11 - Prob. 3.3ECh. 11 - Prob. 4.1E
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