Pre-Algebra, Student Edition
Pre-Algebra, Student Edition
1st Edition
ISBN: 9780078885150
Author: McGraw-Hill
Publisher: Glencoe/McGraw-Hill
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Concept explainers

Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear re…
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
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Question
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Chapter 1.1, Problem 37HP

(a)

To determine

To find:the expression for the number of centimeters in 200 inches.

(a)

Expert Solution
Check Mark

Answer to Problem 37HP

The expression for number of centimeters in 200 inches is 200(2.54)

There are 508 cm in 200 inches.

Explanation of Solution

Given:

One package contains 350 centimeters of trim.

The second package contains 200 inches of trim.

Calculation:

Now, 1 inch ≈ 2.54 cm

Then, to find number of cm in 200 inches, multiply 200 by the number of cm in 1 inch.

That is, 200(2.54)

  200 inch = 200(2.54) cm=508 cm

Thus the expression for number of centimeters in 200 inches is 200(2.54)

And there are 508 cm in 200 inches.

Conclusion:

Thus the expression for number of centimeters in 200 inches is 200(2.54)

There are 508 cm in 200 inches.

(b)

To determine

To find: The total number of centimeters of trim in two packages.

(b)

Expert Solution
Check Mark

Answer to Problem 37HP

Thus, total number of centimeters in the two packages 858cm

Explanation of Solution

Given:

One package contains 350 centimeters of trim. The second package contains 200 inches of trim.

Calculation:

Total number of centimeters in the two packages is equal to the sum of number of centimeters in the first package (given in question) and number of centimeters in the second package (obtained in part (a))

Thus, total number of centimeters in the two packages = 350+508=858cm

Conclusion:

Therefore, total number of centimeters in the two packages = 350+508=858cm

(c)

To determine

To find: the number of packages of trim that have thesame amount of trim from part b

(c)

Expert Solution
Check Mark

Answer to Problem 37HP

Thus, he needs to buy about 4 packages of 90 inches trim.

Explanation of Solution

Given:

One package contains 350 centimeters of trim. The second package contains 200 inches of trim.

Calculation:

Leah wants to buy 858 cm of trim in total.

If he buyspackages which contains 90 inches of trims each, then find total number of such packages that he needs to buy to have total 858 cm of trim.

Since, 1 inch = 2.54 cm

Then, number of cm in 90 inches is.

90 inch = 90(2.54) cm

≈ 229 cm

That is, 1 package contains nearly 229 cm of trim.

To find the number of packages that he needs to buy to have 858 cm of trim, divide 858 by 229.

Total number of packages he needs to buy is given by

  858÷229≈3.75

Thus, he needs to buy about 4 packages of 90 inches trim.

Conclusion:

Therefore, he needs to buy about 4 packages of 90 inches trim

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Chapter 1.1, Problem 36HP
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Chapter 1.1, Problem 38HP

Chapter 1 Solutions

Pre-Algebra, Student Edition

Ch. 1.1 - Prob. 1ACYPCh. 1.1 - Prob. 1BCYPCh. 1.1 - Prob. 2ACYPCh. 1.1 - Prob. 2BCYPCh. 1.1 - Prob. 2CCYPCh. 1.1 - Prob. 2DCYPCh. 1.1 - Prob. 3CYPCh. 1.1 - Prob. 1CYUCh. 1.1 - Prob. 2CYUCh. 1.1 - Prob. 3CYU
Ch. 1.1 - Prob. 4CYUCh. 1.1 - Prob. 5CYUCh. 1.1 - Prob. 6CYUCh. 1.1 - Prob. 7CYUCh. 1.1 - Prob. 8CYUCh. 1.1 - Prob. 9CYUCh. 1.1 - Prob. 10CYUCh. 1.1 - Prob. 11CYUCh. 1.1 - Prob. 12PPSCh. 1.1 - Prob. 13PPSCh. 1.1 - Prob. 14PPSCh. 1.1 - Prob. 15PPSCh. 1.1 - Prob. 16PPSCh. 1.1 - Prob. 17PPSCh. 1.1 - Prob. 18PPSCh. 1.1 - Prob. 19PPSCh. 1.1 - Prob. 20PPSCh. 1.1 - Prob. 21PPSCh. 1.1 - Prob. 22PPSCh. 1.1 - Prob. 23PPSCh. 1.1 - Prob. 24PPSCh. 1.1 - Prob. 25PPSCh. 1.1 - Prob. 26PPSCh. 1.1 - Prob. 27PPSCh. 1.1 - Prob. 28PPSCh. 1.1 - Prob. 29PPSCh. 1.1 - Prob. 30PPSCh. 1.1 - Prob. 31PPSCh. 1.1 - Prob. 32PPSCh. 1.1 - Prob. 33PPSCh. 1.1 - Prob. 34HPCh. 1.1 - Prob. 35HPCh. 1.1 - Prob. 36HPCh. 1.1 - Prob. 37HPCh. 1.1 - Prob. 38HPCh. 1.1 - Prob. 39STPCh. 1.1 - Prob. 40STPCh. 1.1 - Prob. 41STPCh. 1.1 - Prob. 42STPCh. 1.2 - Prob. 1ACYPCh. 1.2 - Prob. 1BCYPCh. 1.2 - Prob. 2ACYPCh. 1.2 - Prob. 2BCYPCh. 1.2 - Prob. 3ACYPCh. 1.2 - Prob. 3BCYPCh. 1.2 - Prob. 3CCYPCh. 1.2 - Prob. 4CYPCh. 1.2 - Prob. 1CYUCh. 1.2 - Prob. 2CYUCh. 1.2 - Prob. 3CYUCh. 1.2 - Prob. 4CYUCh. 1.2 - Prob. 5CYUCh. 1.2 - Prob. 6CYUCh. 1.2 - Prob. 7CYUCh. 1.2 - Prob. 8CYUCh. 1.2 - Prob. 9CYUCh. 1.2 - Prob. 10CYUCh. 1.2 - Prob. 11CYUCh. 1.2 - Prob. 12PPSCh. 1.2 - Prob. 13PPSCh. 1.2 - Prob. 14PPSCh. 1.2 - Prob. 15PPSCh. 1.2 - Prob. 16PPSCh. 1.2 - Prob. 17PPSCh. 1.2 - Prob. 18PPSCh. 1.2 - Prob. 19PPSCh. 1.2 - Prob. 20PPSCh. 1.2 - Prob. 21PPSCh. 1.2 - Prob. 22PPSCh. 1.2 - Prob. 23PPSCh. 1.2 - Prob. 24PPSCh. 1.2 - Prob. 25PPSCh. 1.2 - Prob. 26PPSCh. 1.2 - Prob. 27PPSCh. 1.2 - Prob. 28PPSCh. 1.2 - Prob. 29PPSCh. 1.2 - Prob. 30PPSCh. 1.2 - Prob. 31PPSCh. 1.2 - Prob. 32PPSCh. 1.2 - Prob. 33PPSCh. 1.2 - Prob. 34PPSCh. 1.2 - Prob. 35PPSCh. 1.2 - Prob. 36PPSCh. 1.2 - Prob. 37PPSCh. 1.2 - Prob. 38PPSCh. 1.2 - Prob. 39PPSCh. 1.2 - Prob. 40PPSCh. 1.2 - Prob. 41HPCh. 1.2 - Prob. 42HPCh. 1.2 - Prob. 43HPCh. 1.2 - Prob. 44HPCh. 1.2 - Prob. 45STPCh. 1.2 - Prob. 46STPCh. 1.2 - Prob. 47STPCh. 1.2 - Prob. 48STPCh. 1.2 - Prob. 49SRCh. 1.2 - Prob. 50SRCh. 1.2 - Prob. 51SRCh. 1.2 - Prob. 52SRCh. 1.2 - Prob. 53SRCh. 1.2 - Prob. 54SRCh. 1.2 - Prob. 55SRCh. 1.2 - Prob. 56SRCh. 1.2 - Prob. 57SRCh. 1.2 - Prob. 58SRCh. 1.2 - Prob. 59SRCh. 1.2 - Prob. 60SRCh. 1.2 - Prob. 61SCh. 1.2 - Prob. 62SCh. 1.2 - Prob. 63SCh. 1.2 - Prob. 64SCh. 1.3 - Prob. 1CYPCh. 1.3 - Prob. 2ACYPCh. 1.3 - Prob. 2BCYPCh. 1.3 - Prob. 2CCYPCh. 1.3 - Prob. 2DCYPCh. 1.3 - Prob. 3ACYPCh. 1.3 - Prob. 3BCYPCh. 1.3 - Prob. 4CYPCh. 1.3 - Prob. 1CYUCh. 1.3 - Prob. 2CYUCh. 1.3 - Prob. 3CYUCh. 1.3 - Prob. 4CYUCh. 1.3 - Prob. 5CYUCh. 1.3 - Prob. 6CYUCh. 1.3 - Prob. 7CYUCh. 1.3 - Prob. 8CYUCh. 1.3 - Prob. 9CYUCh. 1.3 - Prob. 10CYUCh. 1.3 - Prob. 11CYUCh. 1.3 - Prob. 12CYUCh. 1.3 - Prob. 13CYUCh. 1.3 - Prob. 14CYUCh. 1.3 - Prob. 15PPSCh. 1.3 - Prob. 16PPSCh. 1.3 - Prob. 17PPSCh. 1.3 - Prob. 18PPSCh. 1.3 - Prob. 19PPSCh. 1.3 - Prob. 20PPSCh. 1.3 - Prob. 21PPSCh. 1.3 - Prob. 22PPSCh. 1.3 - Prob. 23PPSCh. 1.3 - Prob. 24PPSCh. 1.3 - Prob. 25PPSCh. 1.3 - Prob. 26PPSCh. 1.3 - Prob. 27PPSCh. 1.3 - Prob. 28PPSCh. 1.3 - Prob. 29PPSCh. 1.3 - Prob. 30PPSCh. 1.3 - Prob. 31PPSCh. 1.3 - Prob. 32PPSCh. 1.3 - Prob. 33PPSCh. 1.3 - Prob. 34PPSCh. 1.3 - Prob. 35PPSCh. 1.3 - Prob. 36PPSCh. 1.3 - Prob. 37PPSCh. 1.3 - Prob. 38PPSCh. 1.3 - Prob. 39PPSCh. 1.3 - Prob. 40PPSCh. 1.3 - Prob. 41PPSCh. 1.3 - Prob. 42PPSCh. 1.3 - Prob. 43PPSCh. 1.3 - Prob. 44HPCh. 1.3 - Prob. 45HPCh. 1.3 - Prob. 46HPCh. 1.3 - Prob. 47HPCh. 1.3 - Prob. 48HPCh. 1.3 - Prob. 49STPCh. 1.3 - Prob. 50STPCh. 1.3 - Prob. 51STPCh. 1.3 - Prob. 52STPCh. 1.3 - Prob. 53SRCh. 1.3 - Prob. 54SRCh. 1.3 - Prob. 55SRCh. 1.3 - Prob. 56SRCh. 1.3 - Prob. 57SRCh. 1.3 - Prob. 58SRCh. 1.3 - Prob. 59SRCh. 1.3 - Prob. 60SRCh. 1.3 - Prob. 61SRCh. 1.3 - Prob. 62SRCh. 1.3 - Prob. 63SRCh. 1.3 - Prob. 64SCh. 1.3 - Prob. 65SCh. 1.3 - Prob. 66SCh. 1.3 - Prob. 67SCh. 1.3 - Prob. 68SCh. 1.3 - Prob. 69SCh. 1.3 - Prob. 70SCh. 1.3 - Prob. 71SCh. 1.4 - Prob. 1ACYPCh. 1.4 - Prob. 1BCYPCh. 1.4 - Prob. 1CCYPCh. 1.4 - Prob. 1DCYPCh. 1.4 - Prob. 2ACYPCh. 1.4 - Prob. 2BCYPCh. 1.4 - Prob. 3CYPCh. 1.4 - Prob. 4ACYPCh. 1.4 - Prob. 4BCYPCh. 1.4 - Prob. 1CYUCh. 1.4 - Prob. 2CYUCh. 1.4 - Prob. 3CYUCh. 1.4 - Prob. 4CYUCh. 1.4 - Prob. 5CYUCh. 1.4 - Prob. 6CYUCh. 1.4 - Prob. 7CYUCh. 1.4 - Prob. 8CYUCh. 1.4 - Prob. 9CYUCh. 1.4 - Prob. 10CYUCh. 1.4 - Prob. 11CYUCh. 1.4 - Prob. 12PPSCh. 1.4 - Prob. 13PPSCh. 1.4 - Prob. 14PPSCh. 1.4 - Prob. 15PPSCh. 1.4 - Prob. 16PPSCh. 1.4 - Prob. 17PPSCh. 1.4 - Prob. 18PPSCh. 1.4 - Prob. 19PPSCh. 1.4 - Prob. 20PPSCh. 1.4 - Prob. 21PPSCh. 1.4 - Prob. 22PPSCh. 1.4 - Prob. 23PPSCh. 1.4 - Prob. 24PPSCh. 1.4 - Prob. 25PPSCh. 1.4 - Prob. 26PPSCh. 1.4 - Prob. 27PPSCh. 1.4 - Prob. 28PPSCh. 1.4 - Prob. 29PPSCh. 1.4 - Prob. 30PPSCh. 1.4 - Prob. 31PPSCh. 1.4 - Prob. 32PPSCh. 1.4 - Prob. 33PPSCh. 1.4 - Prob. 34PPSCh. 1.4 - Prob. 35PPSCh. 1.4 - Prob. 36HPCh. 1.4 - Prob. 37HPCh. 1.4 - Prob. 38HPCh. 1.4 - Prob. 39HPCh. 1.4 - Prob. 40HPCh. 1.4 - Prob. 41STPCh. 1.4 - Prob. 42STPCh. 1.4 - Prob. 43STPCh. 1.4 - Prob. 44STPCh. 1.4 - Prob. 45SRCh. 1.4 - Prob. 46SRCh. 1.4 - Prob. 47SRCh. 1.4 - Prob. 48SRCh. 1.4 - Prob. 49SRCh. 1.4 - Prob. 50SRCh. 1.4 - Prob. 51SRCh. 1.4 - Prob. 52SCh. 1.4 - Prob. 53SCh. 1.4 - Prob. 54SCh. 1.4 - Prob. 55SCh. 1.4 - Prob. 56SCh. 1.4 - Prob. 57SCh. 1.5 - Prob. 1CYPCh. 1.5 - Prob. 2ACYPCh. 1.5 - Prob. 2BCYPCh. 1.5 - Prob. 1CYUCh. 1.5 - Prob. 2CYUCh. 1.5 - Prob. 3CYUCh. 1.5 - Prob. 4PPSCh. 1.5 - Prob. 5PPSCh. 1.5 - Prob. 6PPSCh. 1.5 - Prob. 7PPSCh. 1.5 - Prob. 8PPSCh. 1.5 - Prob. 9PPSCh. 1.5 - Prob. 10PPSCh. 1.5 - Prob. 11PPSCh. 1.5 - Prob. 12HPCh. 1.5 - Prob. 13HPCh. 1.5 - Prob. 14HPCh. 1.5 - Prob. 15STPCh. 1.5 - Prob. 16STPCh. 1.5 - Prob. 17STPCh. 1.5 - Prob. 18STPCh. 1.5 - Prob. 19SRCh. 1.5 - Prob. 20SRCh. 1.5 - Prob. 21SRCh. 1.5 - Prob. 22SRCh. 1.5 - Prob. 23SRCh. 1.5 - Prob. 24SRCh. 1.5 - Prob. 25SRCh. 1.5 - Prob. 26SRCh. 1.5 - Prob. 27SRCh. 1.5 - Prob. 28SRCh. 1.5 - Prob. 29SRCh. 1.5 - Prob. 30SRCh. 1.5 - Prob. 31SRCh. 1.5 - Prob. 32SCh. 1.5 - Prob. 33SCh. 1.5 - Prob. 34SCh. 1.5 - Prob. 35SCh. 1.6 - Prob. 1CYPCh. 1.6 - Prob. 2CYPCh. 1.6 - Prob. 3ACYPCh. 1.6 - Prob. 3BCYPCh. 1.6 - Prob. 3CCYPCh. 1.6 - Prob. 1CYUCh. 1.6 - Prob. 2PPSCh. 1.6 - Prob. 3PPSCh. 1.6 - Prob. 4PPSCh. 1.6 - Prob. 5PPSCh. 1.6 - Prob. 6PPSCh. 1.6 - Prob. 7PPSCh. 1.6 - Prob. 8PPSCh. 1.6 - Prob. 9PPSCh. 1.6 - Prob. 10PPSCh. 1.6 - Prob. 11PPSCh. 1.6 - Prob. 12PPSCh. 1.6 - Prob. 13PPSCh. 1.6 - Prob. 14PPSCh. 1.6 - Prob. 15PPSCh. 1.6 - Prob. 16HPCh. 1.6 - Prob. 17HPCh. 1.6 - Prob. 18HPCh. 1.6 - Prob. 19HPCh. 1.6 - Prob. 20HPCh. 1.6 - Prob. 21HPCh. 1.6 - Prob. 22HPCh. 1.6 - Prob. 23STPCh. 1.6 - Prob. 24STPCh. 1.6 - Prob. 25STPCh. 1.6 - Prob. 26STPCh. 1.6 - Prob. 27SRCh. 1.6 - Prob. 28SRCh. 1.6 - Prob. 29SRCh. 1.6 - Prob. 30SRCh. 1.6 - Prob. 31SRCh. 1.6 - Prob. 32SRCh. 1.6 - Prob. 33SRCh. 1.6 - Prob. 34SCh. 1.6 - Prob. 35SCh. 1.6 - Prob. 36SCh. 1.6 - Prob. 37SCh. 1.6 - Prob. 38SCh. 1.6 - Prob. 39SCh. 1 - Prob. 1QCCh. 1 - Prob. 2QCCh. 1 - Prob. 3QCCh. 1 - Prob. 4QCCh. 1 - Prob. 5QCCh. 1 - Prob. 6QCCh. 1 - Prob. 7QCCh. 1 - Prob. 8QCCh. 1 - Prob. 9QCCh. 1 - Prob. 10QCCh. 1 - Prob. 11QCCh. 1 - Prob. 12QCCh. 1 - Prob. 13QCCh. 1 - Prob. 14QCCh. 1 - Prob. 15QCCh. 1 - Prob. 16QCCh. 1 - Prob. 17QCCh. 1 - Prob. 18QCCh. 1 - Prob. 19QCCh. 1 - Prob. 1MCQCh. 1 - Prob. 2MCQCh. 1 - Prob. 3MCQCh. 1 - Prob. 4MCQCh. 1 - Prob. 5MCQCh. 1 - Prob. 6MCQCh. 1 - Prob. 7MCQCh. 1 - Prob. 8MCQCh. 1 - Prob. 9MCQCh. 1 - Prob. 10MCQCh. 1 - Prob. 11MCQCh. 1 - Prob. 12MCQCh. 1 - Prob. 13MCQCh. 1 - Prob. 14MCQCh. 1 - Prob. 15MCQCh. 1 - Prob. 16MCQCh. 1 - Prob. 17MCQCh. 1 - Prob. 18MCQCh. 1 - Prob. 19MCQCh. 1 - Prob. 20MCQCh. 1 - Prob. 21MCQCh. 1 - Prob. 22MCQCh. 1 - Prob. 23MCQCh. 1 - Prob. 24MCQCh. 1 - Prob. 25MCQCh. 1 - Prob. 1SGRCh. 1 - Prob. 2SGRCh. 1 - Prob. 3SGRCh. 1 - Prob. 4SGRCh. 1 - Prob. 5SGRCh. 1 - Prob. 6SGRCh. 1 - Prob. 7SGRCh. 1 - Prob. 8SGRCh. 1 - Prob. 9SGRCh. 1 - Prob. 10SGRCh. 1 - Prob. 11SGRCh. 1 - Prob. 12SGRCh. 1 - Prob. 13SGRCh. 1 - Prob. 14SGRCh. 1 - Prob. 15SGRCh. 1 - Prob. 16SGRCh. 1 - Prob. 17SGRCh. 1 - Prob. 18SGRCh. 1 - Prob. 19SGRCh. 1 - Prob. 20SGRCh. 1 - Prob. 21SGRCh. 1 - Prob. 22SGRCh. 1 - Prob. 23SGRCh. 1 - Prob. 24SGRCh. 1 - Prob. 25SGRCh. 1 - Prob. 26SGRCh. 1 - Prob. 27SGRCh. 1 - Prob. 28SGRCh. 1 - Prob. 29SGRCh. 1 - Prob. 30SGRCh. 1 - Prob. 1PTCh. 1 - Prob. 2PTCh. 1 - Prob. 3PTCh. 1 - Prob. 4PTCh. 1 - Prob. 5PTCh. 1 - Prob. 6PTCh. 1 - Prob. 7PTCh. 1 - Prob. 8PTCh. 1 - Prob. 9PTCh. 1 - Prob. 10PTCh. 1 - Prob. 11PTCh. 1 - Prob. 12PTCh. 1 - Prob. 13PTCh. 1 - Prob. 14PTCh. 1 - Prob. 15PTCh. 1 - Prob. 16PTCh. 1 - Prob. 17PTCh. 1 - Prob. 18PTCh. 1 - Prob. 19PTCh. 1 - Prob. 20PTCh. 1 - Prob. 21PTCh. 1 - Prob. 22PTCh. 1 - Prob. 23PTCh. 1 - Prob. 24PTCh. 1 - Prob. 25PTCh. 1 - Prob. 1ECh. 1 - Prob. 2ECh. 1 - Prob. 3ECh. 1 - Prob. 4ECh. 1 - Prob. 1STPCh. 1 - Prob. 2STPCh. 1 - Prob. 3STPCh. 1 - Prob. 4STPCh. 1 - Prob. 5STPCh. 1 - Prob. 6STPCh. 1 - Prob. 7STPCh. 1 - Prob. 8STPCh. 1 - Prob. 9STPCh. 1 - Prob. 10STPCh. 1 - Prob. 11STP

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