Concept explainers
In an Ames test using
a. What is the reason for the different experimental results described?
b. Is the test compound still considered to be a potential mutagen? Explain why or why not.
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Genetic Analysis: An Integrated Approach (3rd Edition)
- Mutation analysis of GCK gene in patients with diabetes revealed a c.114 T->A (shown in bold and underlined) substitution in heterozygote state. In order to check the mutation in healthy individuals, restriction enzyme analysis will be used. a) which enzyme can we use to differentiate wild type and mutant sequence? Please indicate which allele (wild type or mutant allele) will be cut with the restriction enzyme. Use table 1 shown below. b) ATGAGGCTCTTTGCCACCAGTCCCAGTTTTATGCATGGCAGCTCTAATGACAGGATGGTCACCCCTG СTGAGGCCACTCCTGGTCACCATGACAАССАCAGGCCCTCTТСAGTATCACAGTAAGCCCTGGCAGG AGAATCCCCCACTCCACACCTGGCTGGAGCACGAAATGCCGAGCGGCGCCTGAGCCCCAGGGAAG CAGGCTAGGATGTGA Figure 1. GCK gene sequence. Length of the fragment is 213bp. Table1. The restriction enzymes and their recognition sequences. Bestriction enzyme Recognition sequence Nari GG/CGCC Ddel C/TOAG Hae II DGCGC/n Hpal cc/GG Alul AG/CT Smal ccc/GGG Mbol /GATC Mae II IGTDAC Bsp 1286 I GNGCn/c Hind II A/AGCTT ECOR I G/AATTC D: any Ducleotide 1:…arrow_forwardCancer cells must be able to proliferate indefinitely. Therefore, many inappropriately express telomerase. a. What is the function of telomerase? b. Why does telomerase enable cells to proliferate indefinitely?arrow_forwardMutation analysis of GCK gene in patients with diabetes revealed a c.114 T→A (shown in bold and underlined) substitution in heterozygote state. In order to check the mutation in healthy individuals, restriction enzyme analysis will be used. a) Which enzyme can we use to differentiate wild type and mutant sequence? Please indicate which allele (wild type or mutant allele) will be cut with the restriction enzyme. Use table 1 shown below. b) Draw the expected agarose gel result of a homozygous wild type, homozygous mutant and heterozygote individual after restriction enzyme analysis. ATGAGGCTCTTTGCCACCAGTCCCAGTTTTATGCATGGCAGCTCTAATGACAGGATGGTCACCCCTGCTGAGGCC ACTCCTGGTCACCATGACAACCACAGGCCCTCTCAGTATCACAGTAAGCCCTGGCAGGAGAATCCCCCACTCCAC ACCTGGCTGGAGCACGAAATGCCGAGCGGCGCCTGAGCCCCAGGGAAGCAGGCTAGGATGTGA Figure 1. GCK gene sequence. Length of the fragment is 213bp. Table1. The restriction enzymes and their recognition sequences. Restriction enzyme Recognition seguence www wwwtw ww Nar I GG/CGCC…arrow_forward
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- The following table lists 4 bacterial strains that are partial diploids for lac operon genes. Given the activity of beta-galactosidase measured for each strain in the absence (-lac) or presence (+lac) of lactose, complete the table by choosing the appropriate symbol (+, -, C, S) to indicate the allele of the gene or site missing from the table (blue numbers). strain A BC 5 C D 7 chromosome I O 1 2 4 1 [Select] 9 3 [Select] [Select] [Select] 9 [Select] + + Z + + 6 + I +5 + 10 plasmid O 3 + 7 C Z + 8 8 2 [Select] 4 [Select] 6 [Select] B-gal act. -lac +lac 0.002 0.003 0.002 0.058 0.063 0.121 0.059 0.062 Select] 1 ✔ [ Select] + is C Sarrow_forwardThe Neurospora octad shown came from a cross between mt and m' strains. a. Is this an MI or an MIl octad or neither? Explain. b. Diagram the production of this octad. c. Is it possible to observe evidence of heteroduplex formation in a Neurospora ascus even if gene conversion did not occur during formation of the octad? Explain.arrow_forwardA sample of E.coli cells is transformed with a plasmid containing a transcriptional fusion including the promoter of an E.coli housekeeping gene and the LacZ gene. The transformed cells are plated out on selective medium containing X-gal. Which of the following best describes the likely results. a. Colonies will only be blue if lactose is also included in the growth medium. b. Colonies will only be blue if lactose and glucose are included in the growth medium c. Most of the colonies should turn blue. d. Presence of any white colonies may indicate deletion or mutation of the promoter. e. Both c. and d. are correctarrow_forward
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