The Essentials of Computer Organization and Architecture
4th Edition
ISBN: 9781284045611
Author: Linda Null, Julia Lobur
Publisher: Jones & Bartlett Learning
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Expert Solution & Answer
Chapter 11, Problem 15E
Explanation of Solution
Identical system is discussed based on findings:
- System performance is considered as one of main factor of a processor.
- It is used to determine the speed a problem can be solved.
- It is also used to determine the factors such as number of problems that can be allocated at particular amount of time and also the number of problems that can be handled by the processor.
- The speed of the CPU is a key factor that often decides the performance of the system.
- But this factor speed is applied only to identical architecture and which will be misled at many cases.
- A detailed analysis is made to arrive at a detailed decision for different architecture.
- Ensuring reliability with the users in terms performance certain set of standards are established.
- Benchmarks are being established such that user can compare the metrics to get a clear idea about the performance.
- The main problem with the benchmarks that are obtained is that are very simple in such a way the manufactures are able to optimize their products in a way it is capable to meet their requirements based on the benchmarks derived.
- Thus it would be difficult for its user to obtain a decision because product will be available in the market without any differentiation.
- Thus to make the benchmarks being more meaningful and comprehensive the consortium of computer manufactures created a magazine where the technology are being brought together in the form of SPEC(Standard Performance Evaluation Corporation) in 1988.
- Performance will be major criteria for the end user of the CPU’s and the performance measures are being benefited through the benchmarks that are constructed by the SPEC...
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7. See the code below and solve the following.
public class Test {
public static void main(String[] args) {
int result = 0;
}
result = fn(2,3);
System.out.println("The result is:
+ result);
// fn(x, 1) = x
// fn(x, y)
=
fn(x, y-1) + 2, when y>1
public static int fn(int x, int y) {
if (x <= 1)
return x;
else
return fn(x, y-1) + 2;
}
}
7-1. This program has a bug that leads to infinite recursion. Modify fn(int x, int y) method to fix
the problem. (2 point)
7-2. Manually trace the recursive call, fn(2,3) and show the output (step by step). (2 point)
7-3. Can you identify the Base Case in recursive method fn(int x, int y)? (1 point)
Chapter 11 Solutions
The Essentials of Computer Organization and Architecture
Ch. 11 - Prob. 1RETCCh. 11 - Prob. 2RETCCh. 11 - Prob. 3RETCCh. 11 - Prob. 4RETCCh. 11 - Prob. 5RETCCh. 11 - Prob. 6RETCCh. 11 - Prob. 7RETCCh. 11 - Prob. 8RETCCh. 11 - Prob. 9RETCCh. 11 - Prob. 10RETC
Ch. 11 - Prob. 11RETCCh. 11 - Prob. 12RETCCh. 11 - Prob. 13RETCCh. 11 - Prob. 14RETCCh. 11 - Prob. 15RETCCh. 11 - Prob. 16RETCCh. 11 - Prob. 17RETCCh. 11 - Prob. 18RETCCh. 11 - Prob. 19RETCCh. 11 - Prob. 20RETCCh. 11 - Prob. 1ECh. 11 - Prob. 2ECh. 11 - Prob. 3ECh. 11 - Prob. 4ECh. 11 - Prob. 5ECh. 11 - Prob. 6ECh. 11 - Prob. 7ECh. 11 - Prob. 8ECh. 11 - Prob. 10ECh. 11 - Prob. 11ECh. 11 - Prob. 12ECh. 11 - Prob. 13ECh. 11 - Prob. 14ECh. 11 - Prob. 15ECh. 11 - Prob. 16ECh. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 - Prob. 19ECh. 11 - Prob. 20ECh. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - Prob. 23ECh. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26E
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