The Essentials of Computer Organization and Architecture
4th Edition
ISBN: 9781284045611
Author: Linda Null, Julia Lobur
Publisher: Jones & Bartlett Learning
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Chapter 11, Problem 14E
Explanation of Solution
Suggestions that could reformulate the SPEC benchmarks:
- The main problem with the benchmarks that are obtained is that are very simple in such a way the manufactures are able to optimize their products in a way it is capable to meet their requirements based on the benchmarks derived.
- Thus it would be difficult for its user to obtain a decision because product will be available in the market without any differentiation.
- Thus to make the benchmarks being more meaningful and comprehensive the consortium of computer manufactures created a magazine where the technology are being brought together in the form of SPEC(Standard Performance Evaluation Corporation) in 1988.
- Performance will be major criteria for the end user of the CPU’s and the performance measures are being benefited through the benchmarks that are constructed by the SPEC.
- Another class of end user whose major area of concern could be the software that are wide applied in server that are used in processing multiple transactions at a particular amount of time by different users...
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Students have asked these similar questions
7. See the code below and solve the following.
public class Test {
public static void main(String[] args) {
int result = 0;
}
result = fn(2,3);
System.out.println("The result is:
+ result);
// fn(x, 1) = x
// fn(x, y)
=
fn(x, y-1) + 2, when y>1
public static int fn(int x, int y) {
if (x <= 1)
return x;
else
return fn(x, y-1) + 2;
}
}
7-1. This program has a bug that leads to infinite recursion. Modify fn(int x, int y) method to fix
the problem. (2 point)
7-2. Manually trace the recursive call, fn(2,3) and show the output (step by step). (2 point)
7-3. Can you identify the Base Case in recursive method fn(int x, int y)? (1 point)
6. See the code below and solve the following.
import java.io.*;
public class DataStream {
}
public static void main(String[] args)
}
DataOutputStream output = new DataOutputStream(new FileOutputStream("temp.dat"));
output.writeUTF("Book1");
output.writeInt(85);
output.writeUTF("Book2");
output.writeInt(125);
output.writeUTF("Book3");
output.writeInt(70);
output.close();
// ToDo: Read all data from temp.dat and print the data to the standard output (monitor)
6-1. This program has a compile error, and the message is “Unhandled exception type
FileNotFoundException". How do you fix this error? (1 point)
6-2. Is FileNotFoundException a checked exception or an unchecked exception? (1 point)
6-3. What is the difference between checked exception and unchecked exception? (1 point)
6-4. Please complete the above program by reading all data from temp.dat and print the data
to the standard output (monitor) by using System.out.print, System.out.println or
System.out.printf method. (2 points)
Write a program that reads a list of integers from input and determines if the list is a palindrome (values are identical from first to last and last to first). The input begins with an integer indicating the length of the list that follows. Assume the list will contain a maximum of 20 integers. Output "yes" if the list is a palindrome and "no" otherwise. The output ends with a newline.
Hints: - use a for loop to populate the array based on the specified size (the first number entered)
- use a for loop to check first value with last value, second value with second from end, etc.
- if the values do not match, set a Boolean variable to flag which statement to output (yes or no)
Ex: If the input is (remember to include spaces between the numbers):
6 1 5 9 9 5 1
the output is:
yes
Ex: If the input is:
5 1 2 3 4 5
the output is: C++ coding
Chapter 11 Solutions
The Essentials of Computer Organization and Architecture
Ch. 11 - Prob. 1RETCCh. 11 - Prob. 2RETCCh. 11 - Prob. 3RETCCh. 11 - Prob. 4RETCCh. 11 - Prob. 5RETCCh. 11 - Prob. 6RETCCh. 11 - Prob. 7RETCCh. 11 - Prob. 8RETCCh. 11 - Prob. 9RETCCh. 11 - Prob. 10RETC
Ch. 11 - Prob. 11RETCCh. 11 - Prob. 12RETCCh. 11 - Prob. 13RETCCh. 11 - Prob. 14RETCCh. 11 - Prob. 15RETCCh. 11 - Prob. 16RETCCh. 11 - Prob. 17RETCCh. 11 - Prob. 18RETCCh. 11 - Prob. 19RETCCh. 11 - Prob. 20RETCCh. 11 - Prob. 1ECh. 11 - Prob. 2ECh. 11 - Prob. 3ECh. 11 - Prob. 4ECh. 11 - Prob. 5ECh. 11 - Prob. 6ECh. 11 - Prob. 7ECh. 11 - Prob. 8ECh. 11 - Prob. 10ECh. 11 - Prob. 11ECh. 11 - Prob. 12ECh. 11 - Prob. 13ECh. 11 - Prob. 14ECh. 11 - Prob. 15ECh. 11 - Prob. 16ECh. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 - Prob. 19ECh. 11 - Prob. 20ECh. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - Prob. 23ECh. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26E
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