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Concept explainers
A pet food company has a business objective of expending its product line beyond its current kidney and shrimp-based cat foods. The company developed two new products, one based on chicken liver and the other based on salmon. The company conducted an experiment to compare the two new products with its two existing ones, as well as a generic beef-based product sold at a supermarket chain.
For the experiment, a sample of 50 cats from the population at a local animal shelter was selected. Ten cats were randomly assigned to each of the five products being tested. Each of the cats was then presented with 3 ounces of the selected food in a dish at feeding time. The researchers defined the variable to be measured as the number of ounces of food that the cat consumed within a 10-minute time interval that began when the filled dish was presented. The results for this experiment are summarized in the table on page 414 and stored in CatFood.
a. At the 0.05 of significance, is there evidence of a difference in the
b. If appropriate, determine which products appear to differ significantly in the mean amount of food eaten.
c. At the 0.05 level of significance, is there evidence of a difference in the variation in the amount of food eaten.
d. What should the pet food company conclude? Fully describe the pet food company’s options with respect to the products.
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Chapter 11 Solutions
Basic Business Statistics
- Clint, obviously not in college, sleeps an average of 8 hours per night with a standard deviation of 15 minutes. What's the chance of him sleeping between 7.5 and 8.5 hours on any given night? 0-(7-0) 200 91109s and doiw $20 (8-0) mol 8520 slang $199 galbrog seam side pide & D (newid se od poyesvig as PELEO PER AFTE editiw noudab temand van Czarrow_forwardTimes to complete a statistics exam have a normal distribution with a mean of 40 minutes and standard deviation of 6 minutes. Deshawn's time comes in at the 90th percentile. What percentage of the students are still working on their exams when Deshawn leaves?arrow_forwardSuppose that the weights of cereal boxes have a normal distribution with a mean of 20 ounces and standard deviation of half an ounce. A box that has a standard score of o weighs how much? syed by ilog ni 21arrow_forward
- Bob scores 80 on both his math exam (which has a mean of 70 and standard deviation of 10) and his English exam (which has a mean of 85 and standard deviation of 5). Find and interpret Bob's Z-scores on both exams to let him know which exam (if either) he did bet- ter on. Don't, however, let his parents know; let them think he's just as good at both subjects. algas 70) sering digarrow_forwardSue's math class exam has a mean of 70 with a standard deviation of 5. Her standard score is-2. What's her original exam score?arrow_forwardClint sleeps an average of 8 hours per night with a standard deviation of 15 minutes. What's the chance he will sleep less than 7.5 hours tonight? nut bow visarrow_forward
- Suppose that your score on an exam is directly at the mean. What's your standard score?arrow_forwardOne state's annual rainfall has a normal dis- tribution with a mean of 100 inches and standard deviation of 25 inches. Suppose that corn grows best when the annual rainfall is between 100 and 150 inches. What's the chance of achieving this amount of rainfall? wved now of sociarrow_forward13 Suppose that your exam score has a standard score of 0.90. Does this mean that 90 percent of the other exam scores are lower than yours?arrow_forward
- Bob's commuting times to work have a nor- mal distribution with a mean of 45 minutes and standard deviation of 10 minutes. How often does Bob get to work in 30 to 45 minutes?arrow_forwardBob's commuting times to work have a nor- mal distribution with a mean of 45 minutes and standard deviation of 10 minutes. a. What percentage of the time does Bob get to work in 30 minutes or less? b. Bob's workday starts at 9 a.m. If he leaves at 8 a.m., how often is he late?arrow_forwardSuppose that you want to put fat Fido on a weight-loss program. Before the program, his weight had a standard score of +2 com- pared to dogs of his breed/age, and after the program, his weight has a standard score of -2. His weight before the program was 150 pounds, and the standard deviation for the breed is 5 pounds. a. What's the mean weight for Fido's breed/ age? b. What's his weight after the weight-loss program?arrow_forward
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