Motion . An object is thrown up from the top of a building that is 320 feet high. The equation y = – 16 t 2 + 128 t + 320 gives the object s height (in feet) above the ground at any time t (in seconds) after the object is thrown. What is the height of the object after 0, 1, 2, 3, 4, 5, and 6 seconds? Sketch the graph of the equation y = − 16 t 2 + 128 t + 320 . What part of the graph represents the physical aspects of the problem? d What are the intercepts of this graph and what do they mean?
Motion . An object is thrown up from the top of a building that is 320 feet high. The equation y = – 16 t 2 + 128 t + 320 gives the object s height (in feet) above the ground at any time t (in seconds) after the object is thrown. What is the height of the object after 0, 1, 2, 3, 4, 5, and 6 seconds? Sketch the graph of the equation y = − 16 t 2 + 128 t + 320 . What part of the graph represents the physical aspects of the problem? d What are the intercepts of this graph and what do they mean?
Solution Summary: The author calculates the height of the object from ground level at various time points by performing the indicated mathematical operation.
Motion. An object is thrown up from the top of a building that is 320 feet high. The equation
y
=
–
16
t
2
+
128
t
+
320
gives the object s height (in feet) above the ground at any time t (in seconds) after the object is thrown.
What is the height of the object after 0, 1, 2, 3, 4, 5, and 6 seconds?
Sketch the graph of the equation
y
=
−
16
t
2
+
128
t
+
320
.
What part of the graph represents the physical aspects of the problem? d What are the intercepts of this graph and what do they mean?
Question
Find the open interval(s) of f(x), graph given below, where f'(x) is negative.
-3-2-1
1 2
4
5
6
Give your answer in interval notation. For example, (2, 4) U (6,∞).
Provide your answer below:
the correct answer is Ccould you please show me how to do it using the residue theorem
Use the information to find and compare Δy and dy. (Round your answers to four decimal places.)
y = x4 + 7 x = −3 Δx = dx = 0.01
Δy =
dy =
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