EBK MATERIALS FOR CIVIL AND CONSTRUCTIO
4th Edition
ISBN: 8220102719569
Author: ZANIEWSKI
Publisher: PEARSON
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Chapter 11, Problem 11.6QP
To determine
Compare the desired properties of the matrix and the fiber phases of the fiber-reinforced composite.
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Compare the desired properties of the matrix and the fiber phases of the fiber reinforced composite.
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Name three functions of the matrix phase in fiber-reinforced composites. State the reason for the need for a strong bond between the fibers and the matrix.
Chapter 11 Solutions
EBK MATERIALS FOR CIVIL AND CONSTRUCTIO
Ch. 11 - Prob. 11.1QPCh. 11 - Prob. 11.2QPCh. 11 - Prob. 11.3QPCh. 11 - Prob. 11.4QPCh. 11 - Prob. 11.5QPCh. 11 - Prob. 11.6QPCh. 11 - Prob. 11.7QPCh. 11 - Prob. 11.8QPCh. 11 - Prob. 11.9QPCh. 11 - What are the functions of aggregate used in...
Ch. 11 - Prob. 11.11QPCh. 11 - Prob. 11.12QPCh. 11 - What are the benefits of adding dispersed steel...Ch. 11 - Getting measurements from Figure 11.20, determine...Ch. 11 - Three 6 in. 12 in. concrete cylinders with...Ch. 11 - Prob. 11.16QPCh. 11 - Prob. 11.17QPCh. 11 - Prob. 11.18QPCh. 11 - Prob. 11.19QPCh. 11 - Prob. 11.20QPCh. 11 - Prob. 11.21QPCh. 11 - Prob. 11.22QPCh. 11 - Prob. 11.23QPCh. 11 - Prob. 11.24QPCh. 11 - Prob. 11.25QPCh. 11 - Prob. 11.26QPCh. 11 - Prob. 11.27QPCh. 11 - Prob. 11.28QPCh. 11 - Prob. 11.29QPCh. 11 - Prob. 11.30QPCh. 11 - A circular FRP composite rod with continuous and...
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- Estimate the transverse tensile strength of the concrete in Problem 12.6.arrow_forwardIV- It is necessary to design a continuous and aligned glass fiber-reinforced polyester having a tensile strength of at least 1400 MPa in the longitudinal direction. The maximum possible specific gravity is 1.65. Using the following data, determine whether such a composite is possible. Justify. Assume a value of 15 MPa for the stress on the matrix when the fibers fail. Material Glass fiber Polyester Specific gravity 2.5 1.35 Tensile strength (MPa) 3500 50arrow_forwardDetermine the (x, y, z) coordinates for the composite volume X 130 mm 190 mm 275 mm 220 mm 190 mm 185 mmarrow_forward
- Determine the y-bar centroid of the composite figure shown. Where: y = 18mm and x = 9 mmShow your solution and round off if possiblearrow_forwardCalculate the modulus of elasticity of fiberglass under isostrain condition if the fiberglass consists of 70% E-glass fibers and 30% epoxy by volume. Also, calculate the percentage of load carried by the glass fibers. The moduli of elasticity of the glass fibers and the epoxy are 70.5 and 6.9 GPa, respectively. If a longitudinal stress of 60 MPa is applied on the composite with a cross-sectional area of 300 mm2, what is the load carried by each of the fiber and the matrix phases?What is the strain sustained by each of the fiber and the matrix phases?arrow_forwardCompare the desired properties of the matrix and the fiber phases of the fiberreinforced composite.arrow_forward
- PROBLEM 6.56 50 mm A steel bar and an aluminum bar are bonded together as shown to form a composite beam. Knowing that the vertical shear in the beam is 18 kN and that the modulus of elasticity is 200 GPa for the steel and 73 GPa for the aluminum, determine (a) the average stress at the bonded surface, (b) the maximum stress Aluminum 25 mm Steel in the beam. 36 mmarrow_forwardA steel bar and an aluminum bar are bonded together as shown to form a composite beam. Knowing that the vertical shear in the beam is 4 kips and that the modulus of elasticity is 29 * 106 psi for the steel and 10.6 *106 psi for the aluminum, determine (a) the aver-age shearing stress at the bonded surface, (b) the maximum shearing stress in the beam.arrow_forwardThe load-strain data obtained in a tension test of a unidirectional carbon fiber/epoxy composite are given below. The specimen dimensions are length=254 mm, width=12.7 mm and thickness is 1.4 mm. Determine the tensile modulus and Poisson ration for each fiber orientation Axial strain Load (N) Transverse strain % 自 % 0° 45° 90° 0° 45° 90° 0.05 2130 130 67 -0.012 -0.113 -0.0004 0.10 4270 255 134 -0.027 -0.021 -0.001 0.15 6400 360 204 -0.041 -0.029 -0.0014 0.20 8620 485 333 -0.054 -0.038 -0.0019 0.25 565 396 -0.048 -0.0025arrow_forward
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