Two children are playing on stools at a restaurant counter. Their feet do not reach the footrests, and the tops of the stools are free to rotate without friction on pedestals fixed to the floor. One of the children catches a tossed ball, in a process described by the equation
(a) Solve the equation for the unknown
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EBK PHYSICS FOR SCIENTISTS AND ENGINEER
- Rank the following quantities of energy from largest to the smallest. State if any are equal. (a) the absolute value of the average potential energy of the SunEarth system (b) the average kinetic energy of the Earth in its orbital motion relative to the Sun (c) the absolute value of the total energy of the SunEarth systemarrow_forwardWhen a particle decays, it splits into two different particles and each is shot off in opposite direction. The speed of each particle is such that momentum is conserved. uranium 238 decays into thorium 234 by emitting an alpha particle (helium 4). If the alpha particle leaves with a speed of 6.8 x 10^3 m/s, what is the speed of the thorium atom? Give your answer in m/s to three significant figures. Use atomic mass units for the mass of each particle. Uranium 238 in atomic mass units is 238 to three significant figures.arrow_forward(a) 15.4 kg m^2/s (a) 18.5 kg m^2/s (a) 6.4 kg m^2/s (a) 10 kg m^2/s (b) 0.30 m (b) 3.34 m (b) 5.14 m (b) 4.11 m (c)-14.9 J (c) 14.9 J (c)-17.4 J (c) 17.4 J entum Ho of the p (b) the distance r₁1 between O and Q,arrow_forward
- A particle with kinetic energy equal to 233 J has a momentum of magnitude 22.4 kg · m/s. Calculate the speed (in m/s) and the mass (in kg) of the particle.arrow_forwardAn object has a kinetic energy of 304 J and a momentum of magnitude 24.7 kg · m/s. Answer parts a-b.arrow_forwardAn object has a kinetic energy of 312 J and a momentum of magnitude 29.3 kg · m/s. (a) Find the speed of the object. _____m/s (b) Find the mass of the object. ______kgarrow_forward
- A particle P of mass m = 0.56 kg is released from rest at a point h = 7 m above the surface of a liquid in a container. P falls through the air into the liquid. Assume there is no air resistance and there is no instantaneous change in speed of P as it enters the liquid. When P is at a distance of d = 0.71 m below the surface of the liquid, P's speed is v = 4.9 m/s. The only force acting on P due to the liquid is a constant resistance to motion of magnitude R N. Find the following: v1: The speed (in m/s) of P the moment just before it strikes the surface of the fluid.a1: The magnitude of the deceleration (in m/s2) of P while it is falling through the liquid.R: The magnitude of the resistance force (in N). The depth of the liquid in the container is dp = 3.9 m. P is taken from the container and attached to one end of a light inextensible string. P is placed at the bottom of the container and then pulled vertical upwards with a constant acceleration, a2. The resistance force to motion R N…arrow_forwardIf B→ is added to C→=7.7î+7.9ĵ, the result is a vector in the positive direction of the y axis, with a magnitude equal to that of C→. What is the magnitude of B→?arrow_forwardA satellite is floating in space. Solar wind sweeping past the satellite consists of a stream of particles, mainly hydrogen ions of mass 1.7×10−27 kg. There are about 0.5×105 ions per cubic meter, and their speed is 8.0×105 m/s. An `umbrella' attached to the satellite is slowly opened, such that the radius of the circular cross-section of the umbrella is changing with time as r(t)=bt2, where b=0.1 m/s2 is a constant (see the figure which shows the side and front views). What is the maximum change of momentum of the satellite due to the solar wind hitting this umbrella after a time of 10 seconds? Explain carefully why this is the maximum possible change. You must explain your reasoning every step of the way!arrow_forward
- In the figure, the incoming mass (m₁) is an alpha particle, with mass of 4.00 atomic mass units (4.00 amu). Target particle (m₂) is a carbon nucleus (m₂ = 12.0 amu). The alpha particle is scattered at an angle 0₁ = 56 degrees and the carbon nucleus moves off with a speed of 1.24 x 105 m/s at an angle 0₂ = 46 degrees. What is the final speed of the alpha particle (V₁f)? Your answer should be in m/s. You can use notation such as 9.99e5, where "e5" stands for "x 105" captie Mal m₁ V₁i m₂ y V2f 0₂ 81 Vif Xarrow_forwardDuring a routine flight in 1956, test pilot Tom Attridge put his jet fighter into a 20 dive for a test of the aircraft’s 20 mm machine cannons. While traveling faster than sound at 4000 m altitude, he shot a burst of rounds.Then, after allowing the cannons to cool, he shot another burst at 2000 m; his speed was then 344 m/s, the speed of the rounds relative to him was 730 m/s, and he was still in a dive. Almost immediately the canopy around him was shredded and his right air intake was damaged.With little flying capability left, the jet crashed into a wooded area, but Attridge managed to escape the resulting explosion. Explain what apparently happened just after the second burst of cannon rounds. (Attridge has been the only pilot who has managed to shoot himself down.)arrow_forwardIn an elastic collision, an object with momentum 25kg•m/s collided with another that has momentum 35kg•m/s. The first objects momentum changes to 15kg•m/s. What is the momentum of the second object after the collisionarrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning