(a)
Interpretation:
The detailed mechanism for the reaction of the given compound with HCl is to be drawn. The major product of the reaction is to be predicted.
Concept introduction:
In an addition of a Bronsted acid across a double bond, the proton can bond to one of the two possible carbon atoms. The major product of an electrophilic addition of a Bronsted acid to an
(b)
Interpretation:
The detailed mechanism for the reaction of the given compound with HCl is to be drawn. The major product of the reaction is to be predicted.
Concept introduction:
In an addition of a Bronsted acid across a double bond, the proton can bond to one of the two possible carbon atoms. The major product of an electrophilic addition of a Bronsted acid to an alkene is the one that proceeds through the more stable carbocation intermediate. If alkene is symmetrical, then it results in only one product. If an alkene is unsymmetrical, then two constitutional isomers can be produced. The major product is the one in which a more stable carbocation intermediate is produced. Tertiary carbocation is the most stable, followed by secondary and then primary. Methyl carbocations are least stable.
(c)
Interpretation:
The detailed mechanism for the reaction of the given compound with HCl is to be drawn. The major product of the reaction is to be predicted.
Concept introduction:
In an addition of a Bronsted acid across a double bond, the proton can bond to one of the two possible carbon atoms. The major product of an electrophilic addition of a Bronsted acid to an alkene is the one that proceeds through the more stable carbocation intermediate. If alkene is symmetrical, then it results in only one product. If an alkene is unsymmetrical, then two constitutional isomers can be produced. The major product is the one in which a more stable carbocation intermediate is produced. Tertiary carbocation is the most stable, followed by secondary and then primary. Methyl carbocations are least stable.
(d)
Interpretation:
The detailed mechanism for the reaction of the given compound with HCl is to be drawn. The major product of the reaction is to be predicted.
Concept introduction:
In an addition of a Bronsted acid across a double bond, the proton can bond to one of the two possible carbon atoms. The major product of an electrophilic addition of a Bronsted acid to an alkene is the one that proceeds through the more stable carbocation intermediate. If alkene is symmetrical, then it results in only one product. If an alkene is unsymmetrical, then two constitutional isomers can be produced. The major product is the one in which a more stable carbocation intermediate is produced. Tertiary carbocation is the most stable, followed by secondary and then primary. Methyl carbocations are least stable.
Want to see the full answer?
Check out a sample textbook solution
Chapter 11 Solutions
Get Ready for Organic Chemistry
- > For each pair of substrates below, choose the one that will react faster in a substitution reaction, assuming that: 1. the rate of substitution doesn't depend on nucleophile concentration and 2. the products are a roughly 50/50 mixture of enantiomers. Substrate A Substrate B Faster Rate X CI (Choose one) (Choose one) CI Br Explanation Check Br (Choose one) C 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy A F10arrow_forwardHow to draw this mechanism for the foloowing reaction in the foto. thank youarrow_forwardPredict the major products of the following organic reaction: Some important notes: CN A? • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. No reaction. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Centerarrow_forward
- Draw the major product of the following reaction. Do not draw inorganic byproducts. H3PO4 OHarrow_forwardPredict the major products of this organic reaction: HBr (1 equiv) Δ ? Some important notes: • Draw the major product, or products, of this reaction in the drawing area below. • You can draw the products in any arrangement you like. • Pay careful attention to the reaction conditions, and only include the major products. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. • Note that there is only 1 equivalent of HBr reactant, so you need not consider the case of multiple additions. Explanation Check X ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacyarrow_forwardFor the structure below, draw the resonance structure that is indicated by the curved arrow(s). Be sure to include formal charges. :ÖH Modify the second structure given to draw the new resonance structure. Include lone pairs and charges in your structure. Use the + and - tools to add/remove charges to an atom, and use the single bond tool to add/remove double bonds.arrow_forward
- Using the table of Reactants and Products provided in the Hints section, provide the major product (with the correct stereochemistry when applicable) for questions below by selecting the letter that corresponds to the exact chemical structures for the possible product. OH conc Hydrochloric acid 40°C Temp A/arrow_forwardUsing arrows to designate the flow of electrons, complete the reaction below and provide a detailed mechanism for the formation of the product OH conc Hydrochloric acid 40°C Temp All chemical structures should be hand drawn on a piece of paper Paragraph BI UAE +varrow_forwarddraw out the following structures plesearrow_forward
- Draw everything on a piece of paper outlining the synthesis from acetaldehyde to 2 cyclopentene carboxaldehyde using carbon based reagants with 3 carbons or fewers. Here is the attached image.arrow_forwardManoharan Mariappan, FR.D., 34) Complete the following reaction starting from hex-1-yne proceeding via different substitution reactions forming 2-heptanone. (25 pts). A Sia₂BH H₂O₂ NaOH Br D Mechanism for reaction D - ether-cleavage: 10 B Ph-MgCI, THF H₁₂O+ D HBr (XS) C TsCl, Py CH3-CH2-CH2-ONaarrow_forwardIn the table below, the correct structure for (2R)-3-methylpentan-2-ol (IUPAC name) can be represented by the letter OH OH HE > ' ÕH C B OH D A/ E OHarrow_forward
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY