(a)
Interpretation:
Condensed formula for 2-methyl-2-hexene has to be drawn.
Concept Introduction:
Organic compounds can be drawn from its IUPAC name. Initially, the parent chain is identified from the IUPAC name. After that the carbon chain is drawn with carbon atoms alone. Next step is to add the substituents in the respective positions as indicated in the IUPAC name. Remaining valency of carbon atom is satisfied by adding correct number of hydrogen atoms.
Condensed structural formula is a simplified form of representation of a molecule. This gives the information about all the atoms present in molecule and the atoms are placed in sequential order which gives information about which atom is bonded to other atom.
(a)
Explanation of Solution
Given IUPAC name is 2-methyl-2-hexene. From this the parent
Numbering of each carbon has to be done as shown,
From the name it is understood that a double bond is present between carbon-2 and carbon-3.
Substituent that is present is a methyl group on carbon-2.
Remaining valency of carbon atom has to be balanced by adding hydrogen atoms.
Condensed formula can be obtained as shown below,
Condensed formula for 2-methyl-2-hexene is drawn as shown.
(b)
Interpretation:
Condensed formula for trans-3-heptene has to be drawn.
Concept Introduction:
Refer part (a).
(b)
Explanation of Solution
Given IUPAC name is trans-3-heptene. From this the parent alkane is identified as heptane. Heptane contains seven carbon atoms.
Numbering of each carbon has to be done as shown,
From the name it is understood that a double bond is present between carbon-3 and carbon-4.
As the stereo information is given as trans-, the hydrogen atom that is bonded to the carbon atoms across the double bond has to be in opposite side. Remaining valency of carbon atom has to be balanced by adding hydrogen atoms.
Condensed formula can be obtained as shown below,
Condensed formula for trans-3-heptene is drawn as shown.
(c)
Interpretation:
Condensed formula for cis-1-chloro-2-pentene has to be drawn.
Concept Introduction:
Refer part (a).
(c)
Explanation of Solution
Given IUPAC name is cis-1-chloro-2-pentene. From this the parent alkane is identified as pentane. Pentane contains five carbon atoms.
Numbering of each carbon has to be done as shown,
From the name it is understood that a double bond is present between carbon-2 and carbon-3.
As the stereo information is given as cis-, the hydrogen atom that is bonded to the carbon atoms across the double bond has to be in same side. Subsituents present in the given name is a chlorine atom in on carbon-1. Remaining valency of carbon atom has to be balanced by adding hydrogen atoms.
Condensed formula can be obtained as shown below,
Condensed formula for cis-1-chloro-2-pentene is drawn as shown.
(d)
Interpretation:
Condensed formula for cis-2-chloro-2-methyl-3-heptene has to be drawn.
Concept Introduction:
Refer part (a).
(d)
Explanation of Solution
Given IUPAC name is cis-2-chloro-2-methyl-3-heptene. From this the parent alkane is identified as heptane. Heptane contains seven carbon atoms.
Numbering of each carbon has to be done as shown,
From the name it is understood that a double bond is present between carbon-3 and carbon-4.
As the stereo information is given as cis-, the hydrogen atom that is bonded to the carbon atoms across the double bond has to be in same side. Substituents present in the given name are a chlorine atom in on carbon-2 and methyl group on carbon-2. Remaining valency of carbon atom has to be balanced by adding hydrogen atoms.
Condensed formula can be obtained as shown below,
Condensed formula for cis-2-chloro-2-methyl-3-heptene is drawn as shown.
(e)
Interpretation:
Condensed formula for trans-5-bromo-2,6-dimethyl-3-octene has to be drawn.
Concept Introduction:
Refer part (a).
(e)
Explanation of Solution
Given IUPAC name is trans-5-bromo-2,6-dimethyl-3-octene. From this the parent alkane is identified as octane. Octane contains eight carbon atoms.
Numbering of each carbon has to be done as shown,
From the name it is understood that a double bond is present between carbon-3 and carbon-4.
As the stereo information is given as trans-, the hydrogen atom that is bonded to the carbon atoms across the double bond has to be in opposite side. Substituents present in the given name are a bromine atom in on carbon-5, a methyl group on carbon-2, and a methyl group on carbon-6. Remaining valency of carbon atom has to be balanced by adding hydrogen atoms.
Condensed formula can be obtained as shown below,
Condensed formula for trans-5-bromo-2,6-dimethyl-3-octene is drawn as shown.
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Chapter 11 Solutions
GENERAL,ORGANIC,+BIOCHEMISTRY
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- What are the angles a and b in the actual molecule of which this is a Lewis structure? H- :0: C=N: b Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal that might be caused by the fact that different electron groups may have slightly different sizes. a = 0° b=0 Xarrow_forwardA student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. • If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + This transformation can't be done in one step. T iarrow_forwardDetermine the structures of the missing organic molecules in the following reaction: H+ O OH H+ + H₂O ☑ ☑ Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structure of the missing organic molecule X. Molecule X shows up in multiple steps, but you only have to draw its structure once. Click and drag to start drawing a structure. X § ©arrow_forward
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