Explanation Given: Radius of the cylinder r=10 cm Length of the cylinder h=20 cm Density of liquid nitrogen is 0.807 g/ml Volume of liquid nitrogen is 25 ml Initial pressure of air in the container =760 mmhg=1 atm Temperature of the container is 298 K Here, according to the given question 25 ml of liquid nitrogen is poured into the cylindrical container, so we will calculate the volume of the cylinder using the radius and length of the cylinder. Now, when 25 ml of liquid nitrogen is poured into the cylinder, it means the volume of 25 ml air moves out of the cylinder. Now, calculate the initial volume of the air at 760 mmhg pressure and 298 K temperature before the addition of liquid nitrogen. After that we will calculate the number of moles of air using the ideal gas equation. We will also calculate the number of moles of 25 ml of liquid nitrogen that is poured into the container. Now we can calculate the total moles of gas present in the container by adding the moles of liquid nitrogen and initial moles of air present. Now using ideal gas equation, we can calculate the pressure of the gas inside the container using the volume of the cylindertemperature, and total moles of gas present in the container. After that we will calculate the surface area of the cylinder using the length and radius. Finally we will calculate the total force inside the container. Formula used: Volume of the cylinder can be calculated using the formula V=Πr 2 h where, r=radius h=length Number of moles can be calculated using the ideal gas equation n= P V R T Where n=number of moles P=Pressure of the gas V=volume of the gas T=Temperature R=universal gas constant Mass can be calculated using the formula Mass=Density ×Volume Number of moles can also be calculated as Number of moles= M a s s o f s u b s tan c e M o l a r m a s s Pressure can be calculated using the ideal gas equation PV=nRT P= n R T V Surface area of the cylinder can be calculated using the formula A=2Πr 2+2Πrh Force can be calculated using the formula Force=pressure ×Area Calculation: Volume of the cylinder V=Πr 2 h V=3.14×(10 cm) 2 ×20 cm =6280cm3 Now 1 cm 3 =0.001 L 6280cm 3 =6.28 L=6280 ml Volume of the cylinder, V=6.28 L Now, 25 ml of liquid nitrogen is poured into the cylinder Therefore,Initial volume of the air present inside the cylinder = Volume of the cylinder - Volume of liquid nitrogen =6280 ml-25 ml =6255 ml 1000 ml=1 l 6255 ml=6.255 L Initial volume of air present =6.255 L Now, Number of moles of air initially present inside the cylinder at 760 mmhg (1 atm) pressure and 298 K temperature Universal gas constant is 0...

1st Edition

ISBN: 9780133888584

Author: Tro

Publisher: VST

See similar textbooks

Concept explainers

Ideal and Real Gases

Ideal gases obey conditions of the general gas laws under all states of pressure and temperature. Ideal gases are also named perfect gases. The attributes of ideal gases are as follows,

Gas Laws

Gas laws describe the ways in which volume, temperature, pressure, and other conditions correlate when matter is in a gaseous state. The very first observations about the physical properties of gases was made by Robert Boyle in 1662. Later discoveries we…

Gaseous State

It is well known that matter exists in different forms in our surroundings. There are five known states of matter, such as solids, gases, liquids, plasma and Bose-Einstein condensate. The last two are known newly in the recent days. Thus, the detailed fo…

Question

Chapter 11, Problem 112E

Interpretation Introduction

To determine:

The total force on the interior of the container at 298 K

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 11, Problem 111E

Chapter 11, Problem 113E

Students have asked these similar questions

my ccc edu - Search X Quick Access X D2L Homepage - Spring 2025 x N Netflix X Dimensional Analysis - A x+ pp.aktiv.com Q ☆ X Question 59 of 70 The volume of 1 unit of plasma is 200.0 mL If the recommended dosage for adult patients is 10.0 mL per kg of body mass, how many units are needed for a patient with a body mass of 80.0 kg ? 80.0 kg 10.0 DAL 1 units X X 4.00 units 1 1 Jeg 200.0 DAL L 1 units X 200.0 mL = 4.00 units ADD FACTOR *( ) DELETE ANSWER RESET D 200.0 2.00 1.60 × 10³ 80.0 4.00 0.0400 0.250 10.0 8.00 & mL mL/kg kg units/mL L unit Q Search delete prt sc 111 110 19

Identify the starting material in the following reaction. Click the "draw structure" button to launch the drawing utility. draw structure ... [1] 0 3 C10H18 [2] CH3SCH3 H

In an equilibrium mixture of the formation of ammonia from nitrogen and hydrogen, it is found that PNH3 = 0.147 atm, PN2 = 1.41 atm and Pн2 = 6.00 atm. Evaluate Kp and Kc at 500 °C. 2 NH3 (g) N2 (g) + 3 H₂ (g) K₂ = (PN2)(PH2)³ = (1.41) (6.00)³ = 1.41 x 104

Chapter 11 Solutions

EBK CHEMISTRY

Ch. 11 - Prob. 1SAQ Ch. 11 - Prob. 2SAQ Ch. 11 - Prob. 3SAQ Ch. 11 - Prob. 4SAQ Ch. 11 - Prob. 5SAQ Ch. 11 - Prob. 6SAQ Ch. 11 - Prob. 7SAQ Ch. 11 - A gas mixture is a 1.55-L container at 298 K...Ch. 11 - Prob. 9SAQ Ch. 11 - Prob. 10SAQ

Ch. 11 - Prob. 11SAQ Ch. 11 - Prob. 12SAQ Ch. 11 - Prob. 13SAQ Ch. 11 - Prob. 14SAQ Ch. 11 - Prob. 15SAQ Ch. 11 - Prob. 1E Ch. 11 - Prob. 2E Ch. 11 - Prob. 3E Ch. 11 - Prob. 4E Ch. 11 - Prob. 5E Ch. 11 - Prob. 6E Ch. 11 - Prob. 7E Ch. 11 - Prob. 8E Ch. 11 - Prob. 9E Ch. 11 - Prob. 10E Ch. 11 - Prob. 11E Ch. 11 - Prob. 12E Ch. 11 - Prob. 13E Ch. 11 - Prob. 14E Ch. 11 - Prob. 15E Ch. 11 - Prob. 16E Ch. 11 - Prob. 17E Ch. 11 - Prob. 18E Ch. 11 - Prob. 19E Ch. 11 - Prob. 20E Ch. 11 - Prob. 21E Ch. 11 - Prob. 22E Ch. 11 - If a reaction occurs in the gas phase at STP, the...Ch. 11 - Prob. 24E Ch. 11 - Prob. 25E Ch. 11 - Prob. 26E Ch. 11 - Prob. 27E Ch. 11 - Prob. 28E Ch. 11 - Prob. 29E Ch. 11 - Prob. 30E Ch. 11 - Prob. 31E Ch. 11 - Prob. 32E Ch. 11 - A 48.3-mL sample of gas in a cylinder is warmed...Ch. 11 - A syringe containing 1.55 mL of oxygen gas is...Ch. 11 - A balloon contains 0.158 mol of gas and has a...Ch. 11 - Prob. 36E Ch. 11 - Prob. 37E Ch. 11 - Prob. 38E Ch. 11 - Prob. 39E Ch. 11 - Prob. 40E Ch. 11 - Prob. 41E Ch. 11 - Prob. 42E Ch. 11 - Prob. 43E Ch. 11 - Prob. 44E Ch. 11 - Prob. 45E Ch. 11 - Prob. 46E Ch. 11 - A wine-dispensing system uses argon canisters to...Ch. 11 - Prob. 48E Ch. 11 - Prob. 49E Ch. 11 - Prob. 50E Ch. 11 - Aerosol cans carry clear warnings against...Ch. 11 - Prob. 52E Ch. 11 - Prob. 53E Ch. 11 - Use the molar volume of a gas at STP to calculate...Ch. 11 - What is the density (in g/L) of hydrogen gas at...Ch. 11 - Prob. 56E Ch. 11 - Prob. 57E Ch. 11 - A 113-mL gas sample has a mass of 0.171 g at a...Ch. 11 - A sample of gas has a mass of 38.8 mg. Its volume...Ch. 11 - Prob. 60E Ch. 11 - A gas mixture contains each of these gases at the...Ch. 11 - A gas mixture with a total pressure of 745 mmHg...Ch. 11 - We add a 1.20-g sample of dry ice to a 755-mL...Ch. 11 - A 275-mL flask contains pure helium at a pressure...Ch. 11 - A gas mixture contains 1.25 g N2 and 0.85 g O2 in...Ch. 11 - Prob. 66E Ch. 11 - The hydrogen gas formed in a chemical reaction is...Ch. 11 - Prob. 68E Ch. 11 - Prob. 69E Ch. 11 - Prob. 70E Ch. 11 - Prob. 71E Ch. 11 - Prob. 72E Ch. 11 - Prob. 73E Ch. 11 - Prob. 74E Ch. 11 - Prob. 75E Ch. 11 - Prob. 76E Ch. 11 - Prob. 77E Ch. 11 - Prob. 78E Ch. 11 - Prob. 79E Ch. 11 - Prob. 80E Ch. 11 - Prob. 81E Ch. 11 - Prob. 82E Ch. 11 - CH3OH can be synthesized by the reaction:...Ch. 11 - Oxygen gas reacts with powered aluminum according...Ch. 11 - Automobile airbags inflate following serious...Ch. 11 - Lithium reacts with nitrogen gas according to the...Ch. 11 - Prob. 87E Ch. 11 - Prob. 88E Ch. 11 - Prob. 89E Ch. 11 - Carbon monoxide gas reacts with hydrogen gas to...Ch. 11 - Prob. 91E Ch. 11 - Prob. 92E Ch. 11 - Prob. 93E Ch. 11 - Use the vander Waals equation and the ideal gas...Ch. 11 - Pennies that are currently being minted are...Ch. 11 - A 2.85 g sample of an unknown chlorofluorocarbon...Ch. 11 - Prob. 97E Ch. 11 - A 118 mL flask is evacuated and found to have a...Ch. 11 - Prob. 99E Ch. 11 - A gaseous hydrogen- and carbon-containing compound...Ch. 11 - Prob. 101E Ch. 11 - Consider the reaction: 2Ag2O(s)4Ag(s)+O2(g) If...Ch. 11 - When hydrochloric acid is poured over potassium...Ch. 11 - Consider the reaction: 2SO2(g)+O2(g)2SO(g)3 If...Ch. 11 - Ammonium carbonate decomposes upon heating...Ch. 11 - Ammonium nitrate decomposes explosively upon...Ch. 11 - Prob. 107E Ch. 11 - Prob. 108E Ch. 11 - Gaseous ammonia is injected into the exhaust...Ch. 11 - Prob. 110E Ch. 11 - Prob. 111E Ch. 11 - Prob. 112E Ch. 11 - Prob. 113E Ch. 11 - Prob. 114E Ch. 11 - Prob. 115E Ch. 11 - Prob. 116E Ch. 11 - Prob. 117E Ch. 11 - Prob. 118E Ch. 11 - Prob. 119E Ch. 11 - Prob. 120E Ch. 11 - Prob. 121E Ch. 11 - Prob. 122E Ch. 11 - Prob. 123E Ch. 11 - Prob. 124E Ch. 11 - Prob. 125E Ch. 11 - Prob. 126E Ch. 11 - When 0.583 g of neon is added to an 800-cm3bulb...Ch. 11 - A gas mixture composed of helium and argon has a...Ch. 11 - Prob. 129E Ch. 11 - Prob. 130E Ch. 11 - Prob. 131E Ch. 11 - Prob. 132E Ch. 11 - Prob. 133E Ch. 11 - Prob. 134E Ch. 11 - The atmosphere slowly oxidizes hydrocarbons in a...Ch. 11 - Prob. 136E Ch. 11 - Prob. 137E Ch. 11 - Prob. 138E Ch. 11 - Prob. 139E Ch. 11 - Prob. 140E Ch. 11 - Prob. 141E Ch. 11 - Prob. 142E Ch. 11 - Prob. 143E Ch. 11 - Which gas would you expect to deviate most from...Ch. 11 - Prob. 145E Ch. 11 - Prob. 146E Ch. 11 - Prob. 147E

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

The total force on the interior of the container at 298 K

Solution Summary: The author calculates the total force on the interior of the container at 298 K using the ideal gas equation.

Concept explainers

To determine: The total force on the interior of the container at 298 K

Want to see the full answer?

Chapter 11 Solutions

To determine:

The total force on the interior of the container at 298 K