Fluid Mechanics
8th Edition
ISBN: 9780073398273
Author: Frank M. White
Publisher: McGraw-Hill Education
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Chapter 11, Problem 11.27P
To determine
(a)
The impeller diameter.
To determine
(b)
Speed in
To determine
(c)
The horsepower required.
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USE MATLAB ONLY
provide typed code
solve for velocity triangle and dont provide copied answer
Turbomachienery .
GIven:
vx = 185 m/s, flow angle = 60 degrees, (leaving a stator in axial flow) R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3
Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram
Use this code for plot
% plots Velocity Tri. in Ch4
function plotveltri(al1,al2,al3,b2,b3)
S1L = [0 1];
V1x = [0 0];
V1s = [0 1*tand(al3)];
S2L = [2 3];
V2x = [0 0];
V2s = [0 1*tand(al2)];
W2s = [0 1*tand(b2)];
U2x = [3 3];
U2y = [1*tand(b2) 1*tand(al2)];
S3L = [4 5];
V3x = [0 0];
V3r = [0 1*tand(al3)];
W3r = [0 1*tand(b3)];
U3x = [5 5];
U3y = [1*tand(b3) 1*tand(al3)];
plot(S1L,V1x,'k',S1L,V1s,'r',...
S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',...
S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',......
'LineWidth',2,'MarkerSize',10),...…
Chapter 11 Solutions
Fluid Mechanics
Ch. 11 - Prob. 11.1PCh. 11 - Prob. 11.2PCh. 11 - Prob. 11.3PCh. 11 - Prob. 11.4PCh. 11 - Pl 1.5 What type of pump is shown in Fig. Pl 1.5?...Ch. 11 - Prob. 11.6PCh. 11 - A piston PDP has a 5-in diameter and a 2-in stroke...Ch. 11 - Pl 1.8 A Bell and Gossett pump at best efficiency,...Ch. 11 - Prob. 11.9PCh. 11 - Prob. 11.10P
Ch. 11 - Prob. 11.11PCh. 11 - Prob. 11.12PCh. 11 - Pl 1.13 A 3.5 hp pump delivers 1140 lbf of...Ch. 11 - Prob. 11.14PCh. 11 - Prob. 11.15PCh. 11 - Prob. 11.16PCh. 11 - Prob. 11.17PCh. 11 - Prob. 11.18PCh. 11 - Pl 1.19 A centrifugal pump has r2 = 9 in, b2 = 2...Ch. 11 - Prob. 11.20PCh. 11 - Prob. 11.21PCh. 11 - Prob. 11.22PCh. 11 - P11.23 When pumping water, (a) at what speed...Ch. 11 - Prob. 11.24PCh. 11 - Prob. 11.25PCh. 11 - Prob. 11.26PCh. 11 - Prob. 11.27PCh. 11 - Prob. 11.28PCh. 11 - Tests by the Byron Jackson Co. of a...Ch. 11 - A pump, geometrically similar to the 12.95-in...Ch. 11 - Prob. 11.31PCh. 11 - Prob. 11.32PCh. 11 - Prob. 11.33PCh. 11 - You are asked to consider a pump geometrically...Ch. 11 - Prob. 11.35PCh. 11 - Prob. 11.36PCh. 11 - Prob. 11.37PCh. 11 - Prob. 11.38PCh. 11 - Prob. 11.39PCh. 11 - Prob. 11.40PCh. 11 - Prob. 11.41PCh. 11 - Prob. 11.42PCh. 11 - The 28-in-diameter pump in Fig. 11.7a at 1170...Ch. 11 - Prob. 11.44PCh. 11 - Prob. 11.45PCh. 11 - Prob. 11.46PCh. 11 - PI 1.47 A pump must be designed to deliver 6 m /s...Ch. 11 - Pl 1.48 Using the data for the pump in Prob. Pl...Ch. 11 - Prob. 11.49PCh. 11 - Prob. 11.50PCh. 11 - Prob. 11.51PCh. 11 - Prob. 11.52PCh. 11 - Prob. 11.53PCh. 11 - Prob. 11.54PCh. 11 - Prob. 11.55PCh. 11 - Prob. 11.56PCh. 11 - Prob. 11.57PCh. 11 - Prob. 11.58PCh. 11 - Suppose it is desired to deliver 700 ftVmin of...Ch. 11 - Prob. 11.60PCh. 11 - Prob. 11.61PCh. 11 - Prob. 11.62PCh. 11 - Pl 1.63 A good curve-fit to the head vs. flow for...Ch. 11 - Prob. 11.64PCh. 11 - *P11.65 An 11.5-in-diameter centrifugal pump,...Ch. 11 - Pl 1.66 It is proposed to run the pump of Prob. Pl...Ch. 11 - Prob. 11.67PCh. 11 - Prob. 11.68PCh. 11 - The pump of Prob. P1138, running at 3500 r/min, is...Ch. 11 - Prob. 11.70PCh. 11 - Prob. 11.71PCh. 11 - Prob. 11.72PCh. 11 - Prob. 11.73PCh. 11 - Prob. 11.74PCh. 11 - Prob. 11.75PCh. 11 - Prob. 11.76PCh. 11 - Prob. 11.77PCh. 11 - Prob. 11.78PCh. 11 - Prob. 11.79PCh. 11 - Determine if either (a) the smallest or (b) the...Ch. 11 - Prob. 11.81PCh. 11 - Prob. 11.82PCh. 11 - Prob. 11.83PCh. 11 - Prob. 11.84PCh. 11 - Prob. 11.85PCh. 11 - Prob. 11.86PCh. 11 - Prob. 11.87PCh. 11 - Prob. 11.88PCh. 11 - A Pelton wheel of 12-ft pitch diameter operates...Ch. 11 - Prob. 11.90PCh. 11 - Prob. 11.91PCh. 11 - Prob. 11.92PCh. 11 - Prob. 11.93PCh. 11 - Prob. 11.94PCh. 11 - Prob. 11.95PCh. 11 - Prob. 11.96PCh. 11 - Prob. 11.97PCh. 11 - Prob. 11.98PCh. 11 - Prob. 11.99PCh. 11 - Prob. 11.100PCh. 11 - Prob. 11.101PCh. 11 - Prob. 11.102PCh. 11 - Prob. 11.103PCh. 11 - Prob. 11.104PCh. 11 - Prob. 11.105PCh. 11 - Prob. 11.106PCh. 11 - Prob. 11.107PCh. 11 - Prob. 11.108PCh. 11 - Prob. 11.1WPCh. 11 - Prob. 11.2WPCh. 11 - Prob. 11.3WPCh. 11 - Prob. 11.4WPCh. 11 - Prob. 11.5WPCh. 11 - Consider a dimensionless pump performance chart...Ch. 11 - Prob. 11.7WPCh. 11 - Prob. 11.8WPCh. 11 - Prob. 11.9WPCh. 11 - Prob. 11.10WPCh. 11 - Prob. 11.1CPCh. 11 - Prob. 11.2CPCh. 11 - Prob. 11.3CPCh. 11 - Prob. 11.4CPCh. 11 - Prob. 11.5CPCh. 11 - Prob. 11.6CPCh. 11 - Prob. 11.7CPCh. 11 - Prob. 11.8CPCh. 11 - Prob. 11.1DP
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- USE MATLAB ONLY provide typed code solve for velocity triangle and dont provide copied answer Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',... S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',...... 'LineWidth',2,'MarkerSize',10),... axis([-1 6 -4 4]), ...…arrow_forwardThe answer should equal to 1157. Please sent me the solution. Thank you!arrow_forwardBONUS: If the volume of the 8cm x 6.5cm x 6cm Block of Aluminum was 312cm3 before machining, find how much material was removed when the fixture below was machined. +2 2.00 cm 6.00 cm 2.50 cm 6.50 cm 1.00 cm 2.50 cm 11.00 cm 8.00 cm 30 CP 9411 FL.4) (m² 1157 Area of triangle = 1/2*B*H Area of circle = лR² Circumference of a circle = 2πR 6.00 cm 6.50 cm 1.50 cm Radius 1.50 cm 1.00 cmarrow_forward
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