Chapter 11, Problem 11.26QP

Interpretation Introduction

Interpretation: The given question stated that solubility of air in water is $7.9\times {10}^{-4}\text{M}$ at $20°\text{C}$ and $1.0\text{atm}$. The Henry’s law constant for air and the $k_{\text{H}}$ value of air is equal to sum of the $k_{\text{H}}$ values for nitrogen and oxygen is to be stated.

Concept introduction: The formula to calculate solubility of gas is,

$C=k_{\text{H}}{P}_{\text{gas}}$

To determine: The Henry’s law constant for air and the $k_{\text{H}}$ value of air is equal to sum of the $k_{\text{H}}$ values for nitrogen and oxygen.