Concept explainers
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(a)
Interpretation:
The hybrid orbitals used by the central atom bromine and the types of bonds that are formed in
Concept introduction:
The atomic orbital is the wave function that is used to find the probability to find an electron around the nucleus of an atom. It is the space around the nucleus of an atom where the electrons are supposed to be found.
Hybridization is the process of intermixing of atomic orbital of slightly different energies to form hybrid orbitals that have similar energy. These orbital have lower energy and more stability than the atomic orbital.
Hybridization of the central atom can be determined from the number of electron groups around the central atom in the Lewis structure of the molecule. Single bond, double bond, triple bond and lone pair all are considered as single electron group.
Sigma bond is formed by the end to end overlapping of atomic or hybrid orbitals. All single bonds are sigma bonds. One double bond is made up of one sigma bond and one pi bond. One triple bond is made up of one sigma bond and two pi bonds.
(b)
Interpretation:
The hybrid orbitals used by the central atom carbon and the types of bonds that are formed in propyne is to be determined.
Concept introduction:
The atomic orbital is the wave function that is used to find the probability to find an electron around the nucleus of an atom. It is the space around the nucleus of an atom where the electrons are supposed to be found.
Hybridization is the process of intermixing of atomic orbital of slightly different energies to form hybrid orbitals that have similar energy. These orbital have lower energy and more stability than the atomic orbital.
Hybridization of the central atom can be determined from the number of electron groups around the central atom in the Lewis structure of the molecule. Single bond, double bond, triple bond and lone pair all are considered as single electron group.
Sigma bond is formed by the end to end overlapping of atomic or hybrid orbitals. All single bonds are sigma bonds. One double bond is made up of one sigma bond and one pi bond. One triple bond is made up of one sigma bond and two pi bonds.
(c)
Interpretation:
The hybrid orbitals used by the central atom sulfur and the types of bonds that are formed in
Concept introduction:
The atomic orbital is the wave function that is used to find the probability to find an electron around the nucleus of an atom. It is the space around the nucleus of an atom where the electrons are supposed to be found.
Hybridization is the process of intermixing of atomic orbital of slightly different energies to form hybrid orbitals that have similar energy. These orbital have lower energy and more stability than the atomic orbital.
Hybridization of the central atom can be determined from the number of electron groups around the central atom in the Lewis structure of the molecule. Single bond, double bond, triple bond and lone pair all are considered as single electron group.
Sigma bond is formed by the end to end overlapping of atomic or hybrid orbitals. All single bonds are sigma bonds. One double bond is made up of one sigma bond and one pi bond. One triple bond is made up of one sigma bond and two pi bonds.
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Chapter 11 Solutions
CHEMISTRY: MOLECULAR NATURE ALEKS ACCESS
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- The sum of the numbers in the name of isA. 11; B. 13; C. 10; D. 12; E. none of the other answers iscorrect. I believe the awnser should be E to this problem but the solution to this problem is D 12. I'm honestly unsure how that's the solution. If you can please explain the steps to this type of problem and how to approach a problem like this it would be greatly appreciated!arrow_forwardConsider the following data for phosphorus: g atomic mass 30.974 mol electronegativity 2.19 kJ electron affinity 72. mol kJ ionization energy 1011.8 mol kJ heat of fusion 0.64 mol You may find additional useful data in the ALEKS Data tab. Does the following reaction absorb or release energy? 2+ + (1) P (g) + e → P (g) Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): Does the following reaction absorb or release energy? 00 release absorb Can't be decided with the data given. yes no ☐ kJ/mol (²) P* (8) + + + e →>> P (g) Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): ☐ release absorb Can't be decided with the data given. yes no kJ/mol аarrow_forwardThe number of hydrogens in an alkyne that has a main chain of 14carbons to which are attached a cyclobutyl ring, a benzene ring, an–OH group, and a Br is A. 34; B. 35; C. 36; D. 24; E. 43arrow_forward
- Hello! I have a 500 Hz H-NMR for 1,5-bis-(4-methoxyphenyl)-penta-1,4-dien-3-one. I need to label the signals with the corresponding H's. Then, find out if the two alkenes are cis or trans by calculating the J values. I believe that I have the H-NMR labeled correctly, but not sure if I got the J values correct to determine if the two alkenes in the compound will make the compound cis or trans.arrow_forwardWhat is the only possible H-Sb-H bond angle in SbH3?arrow_forwardpls helparrow_forward
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