Concept explainers
(a)
Interpretation:
The hybrid orbitals used by the central atom bromine and the types of bonds that are formed in
Concept introduction:
The atomic orbital is the wave function that is used to find the probability to find an electron around the nucleus of an atom. It is the space around the nucleus of an atom where the electrons are supposed to be found.
Hybridization is the process of intermixing of atomic orbital of slightly different energies to form hybrid orbitals that have similar energy. These orbital have lower energy and more stability than the atomic orbital.
Hybridization of the central atom can be determined from the number of electron groups around the central atom in the Lewis structure of the molecule. Single bond, double bond, triple bond and lone pair all are considered as single electron group.
Sigma bond is formed by the end to end overlapping of atomic or hybrid orbitals. All single bonds are sigma bonds. One double bond is made up of one sigma bond and one pi bond. One triple bond is made up of one sigma bond and two pi bonds.
(b)
Interpretation:
The hybrid orbitals used by the central atom carbon and the types of bonds that are formed in propyne is to be determined.
Concept introduction:
The atomic orbital is the wave function that is used to find the probability to find an electron around the nucleus of an atom. It is the space around the nucleus of an atom where the electrons are supposed to be found.
Hybridization is the process of intermixing of atomic orbital of slightly different energies to form hybrid orbitals that have similar energy. These orbital have lower energy and more stability than the atomic orbital.
Hybridization of the central atom can be determined from the number of electron groups around the central atom in the Lewis structure of the molecule. Single bond, double bond, triple bond and lone pair all are considered as single electron group.
Sigma bond is formed by the end to end overlapping of atomic or hybrid orbitals. All single bonds are sigma bonds. One double bond is made up of one sigma bond and one pi bond. One triple bond is made up of one sigma bond and two pi bonds.
(c)
Interpretation:
The hybrid orbitals used by the central atom sulfur and the types of bonds that are formed in
Concept introduction:
The atomic orbital is the wave function that is used to find the probability to find an electron around the nucleus of an atom. It is the space around the nucleus of an atom where the electrons are supposed to be found.
Hybridization is the process of intermixing of atomic orbital of slightly different energies to form hybrid orbitals that have similar energy. These orbital have lower energy and more stability than the atomic orbital.
Hybridization of the central atom can be determined from the number of electron groups around the central atom in the Lewis structure of the molecule. Single bond, double bond, triple bond and lone pair all are considered as single electron group.
Sigma bond is formed by the end to end overlapping of atomic or hybrid orbitals. All single bonds are sigma bonds. One double bond is made up of one sigma bond and one pi bond. One triple bond is made up of one sigma bond and two pi bonds.
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Chapter 11 Solutions
MCGRAW: CHEMISTRY THE MOLECULAR NATURE
- (ME EX1) Prblm #9/10 Can you explain in detail (step by step) I'm so confused with these problems. For turmber 13 can u turn them into lewis dot structures so I can better understand because, and then as well explain the resonance structure part. Thanks for the help.arrow_forwardProblems 19 and 20: (ME EX1) Can you please explain the following in detail? I'm having trouble understanding them. Both problems are difficult for me to explain in detail, so please include the drawings and answers.arrow_forward(ME EX1) Prblm #4-11 Can you please help me and explain these I'm very confused in detail please. Prblm number 9 I don't understand at all (its soo confusing to me and redraw it so I can better depict it).arrow_forward
- ME EX1) Prblm #19-20 I'm so confused with these problems. Can you please help me solve them and explain them? Problems number 19-20, and thanks! step by step and in detail for me please helparrow_forwardCalculate the flux of oxygen between the ocean and the atmosphere, given that: Temp = 18°C Salinity = 35 ppt Density = 1025 kg/m3 Oxygen concentration measured in bulk water = 263.84 mmol/m3 Wind speed = 7.4 m/s Oxygen is observed to be about 10% initially supersaturatedarrow_forward( ME EX1) Prblm 27-28: Can you explain to me both prblms in detail and for prblm 28 what do you mean bi conjugated bi ponds and those structures I'm confused...arrow_forward
- A. Determine the number of electrons in a system of cyclic conjugation (zero if no cyclic conjugation). B. Specify whether the species is "a"-aromatic, "aa"-anti-aromatic, or "na"-non-aromatic (neither aromatic nor anti-aromatic). (Presume rings to be planar unless structure obviously prevents planarity. If there is more than one conjugated ring, count electrons in the largest.) 1. A.Electrons in a cyclic conjugated system. 18 B.The compound is (a, aa, or na) a 2. A.Electrons in a cyclic conjugated system. 10 B.The compound is (a, aa, or na) naarrow_forwardWater is boiling at 1 atm pressure in a stainless steel pan on an electric range. It is observed that 2 kg of liquid water evaporates in 30 min. Find the rate of heat transfer to the water (kW).arrow_forwardCould you please turn this into a complete Lewis dot structure formula for me so I can visualize it more clearly? and then do the explaining for the resonance structures that were given please.arrow_forward
- Could you please turn this into a complete Lewis dot structure formula for me so I can visualize it more clearly? and then do the explaining for the question.arrow_forwardplease solve. If the answer is "no error" and it asks me to type something, and i typed a-helix, its always wrong.arrow_forwardCan you please solve and explain this for me in a simple way? I cant seem to comprehend this problem.arrow_forward
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