Explanation Formula used: “The probability density function for the exponential random variable X is f ( x ) = { ( 1 λ ) e − x λ if x ≥ 0 0 otherwise and the associated cumulative distribution function F ( x ) = { 1 − e − x λ if x ≥ 0 0 otherwise ”. Calculation: Given that X is an exponential random variable with λ = 1 5 . Substitute the value λ = 1 5 in the above mentioned formula to compute the probability density function. f ( x ) = { ( 1 ( 1 5 ) ) e − x 1 5 if x ≥ 0 0 otherwise = { 5 e − 5 x if

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Chapter 11, Problem 10RE

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To find: The probability density function f and the associated cumulative distribution function F for the exponential random variable X with λ=15.

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Chapter 11, Problem 9RE

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Chapter 11 Solutions

EP CALCULUS FOR BUSINESS..-MYLAB ACCESS

Ch. 11.1 - Evaluate the following, if it converges: 3dx(x1)2.Ch. 11.1 - Prob. 2MP Ch. 11.1 - Prob. 3MP Ch. 11.1 - Prob. 4MP Ch. 11.1 - Prob. 5MP Ch. 11.1 - Prob. 6MP Ch. 11.1 - Prob. 1ED Ch. 11.1 - Prob. 2ED Ch. 11.1 - Prob. 1E Ch. 11.1 - Prob. 2E

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The probability density function f and the associated cumulative distribution function F for the exponential random variable X with λ = 1 5 .

Solution Summary: The author describes the probability density function f and the associated cumulative distribution function F for the exponential random variable X with lambda =15.

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To find: The probability density function f and the associated cumulative distribution function F for the exponential random variable X with λ=15.

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