a) Interpretation: The IUPAC name of the alkyl halide is to be given. Concept introduction: The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference. To give: The IUPAC name of the alkyl halide shown.

Question

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Answer 1

Question

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

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Answer 2

Question

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

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Answer 3

Question

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

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Answer 4

Question

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

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Answer 5

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

Answer 6

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Answer 7

Chapter 10.SE, Problem 14VC

Interpretation Introduction

a)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Answer 8

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 2

Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The compound has a cyclohexane ring with a Cl atom on C₁ and a methyl on C₃ both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.

Answer 13

Conclusion

The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.

Answer 14

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

Answer 15

Interpretation Introduction

b)

Interpretation:

The IUPAC name of the alkyl halide is to be given.

Concept introduction:

The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.

To give:

The IUPAC name of the alkyl halide shown.

Answer 16

Expert Solution

Answer to Problem 14VC

The alkyl halide given is

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 10.SE, Problem 14VC , additional homework tip 4

Its IUPAC name is 4-chloro-2-methyl-2-heptene.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

The compound has a seven carbon straight chain with a double bond between C₂ & C₃, a Cl atom on C₄ and a methyl on C₃. Hence its name is 4-chloro-2-methyl-2-heptene.

Answer 21

Conclusion

The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.

Answer 22

Ch. 10.1 - Prob. 1P Ch. 10.1 - Draw structures corresponding to the following...Ch. 10.2 - Prob. 3P Ch. 10.2 - Taking the relative reactivities of 1Â°, 2Â°, and...Ch. 10.4 - Prob. 5P Ch. 10.4 - The major product of the reaction of...Ch. 10.4 - Prob. 7P Ch. 10.5 - Prob. 8P Ch. 10.6 - Prob. 9P Ch. 10.6 - How might you replace a halogen substituent by a...

Concept explainers

Answer to Problem 14VC

Explanation of Solution

Answer to Problem 14VC

Explanation of Solution

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Chapter 10 Solutions