Given that (S)-3-methylhexane undergoes radical bromination to yield optically inactive 3-bromo-3-methylhexane as the major product. Whether the product and the radical intermediate are chiral or not is to be stated. Concept introduction: In the free radicals produced from chiral molecules the carbon bearing the odd electron is in sp 2 - hybridized state. It has only three bonds around it with the odd electron in the unhydridized p orbital. So it is achiral in nature. When it further reacts, the other radical can attack this radical from both above and below of its plane leading to two different stereoisomers in equal proportions. The product thus will be a racemic mixture. To state: The product and the radical intermediate formed when (S)-3-methylhexane undergoes radical bromination to yield optically inactive 3-bromo-3-methylhexane are chiral or not.

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Learning Goal: This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this: 35 Cl 17 In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is: It is also correct to write symbols by leaving off the atomic number, as in the following form: atomic number mass number Symbol 35 Cl or mass number Symbol This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written. Watch this video to review the format for written symbols. In the following table each column…

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Chapter 10.SE, Problem 38AP

Interpretation Introduction

Interpretation:

Given that (S)-3-methylhexane undergoes radical bromination to yield optically inactive 3-bromo-3-methylhexane as the major product. Whether the product and the radical intermediate are chiral or not is to be stated.

Concept introduction:

In the free radicals produced from chiral molecules the carbon bearing the odd electron is in sp²- hybridized state. It has only three bonds around it with the odd electron in the unhydridized p orbital. So it is achiral in nature. When it further reacts, the other radical can attack this radical from both above and below of its plane leading to two different stereoisomers in equal proportions. The product thus will be a racemic mixture.

To state:

The product and the radical intermediate formed when (S)-3-methylhexane undergoes radical bromination to yield optically inactive 3-bromo-3-methylhexane are chiral or not.

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Learning Goal: This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this: 35 Cl 17 In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is: It is also correct to write symbols by leaving off the atomic number, as in the following form: atomic number mass number Symbol 35 Cl or mass number Symbol This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written. Watch this video to review the format for written symbols. In the following table each column…

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