Explanation Compare the given equation to the standard linear equation form and use the integrating factor to determine the solution of the given equation. Given: y ' − y = e 2 x , y ( 0 ) = 1 Calculation: Given, y ' − y = e 2 x which is of the form y ' + A ( x ) y = B ( x ) with A ( x ) = − 1 , B ( x ) = e 2 x The integrating factor is thus, α ( x ) = e ∫ A ( x ) d x = e − x Multiplying by the integrating factor, we get

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ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 10.5, Problem 4E

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The solution of $y' - y = e^{2 x}, y (0) = 1$

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Chapter 10.5, Problem 3E

Chapter 10.5, Problem 5E

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The solution of y ' − y = e 2 x , y ( 0 ) = 1

Solution Summary: The author compares the given equation to the standard linear equation form and uses the integrating factor to determine the solution.

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The solution of $y' - y = e^{2 x}, y (0) = 1$

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Chapter 10 Solutions

The solution of y ' − y = e 2 x , y ( 0 ) = 1

Solution Summary: The author compares the given equation to the standard linear equation form and uses the integrating factor to determine the solution.

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The solution of y'−y=e2x,y(0)=1

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Chapter 10 Solutions

The solution of $y' - y = e^{2 x}, y (0) = 1$