Computer Science: An Overview (13th Edition) (What's New in Computer Science)
13th Edition
ISBN: 9780134875460
Author: Glenn Brookshear, Dennis Brylow
Publisher: PEARSON
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Chapter 10.5, Problem 2QE
Program Plan Intro
Straight forward ray tracing:
In straight forward ray tracing, a single ray passing through the pixel at the centre of projection is traced and move forward to the light source.
Distributed ray tracing:
In distributed ray tracing, multiple rays passing from the pixel at the centre of projection extending in slightly different direction are traced.
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make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal.
Create 2 groups: marketing and research.
Add Shamir, Jose, and Kate to the marketing group.
Add Don, Liz, and Sal to the research group.
Create a shared directory for each group.
Create two files to put into each directory:
spreadsheetJanuary.txt
meetingNotes.txt
Assign access permissions to the directories:
Groups should have Read+Write access
Leave owner permissions as they are
“Everyone else” should not have any access
Submit for grade:
Screenshot of /etc/passwd contents showing your new users
Screenshot of /etc/group contents showing new groups with their members
Screenshot of shared directories you created with files and permissions
⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers,
⚫ your circuit diagrams for your extended full adder, designed in Section 1 and
⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2.
1 An Extended Full Adder
In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj,
Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit
outputs: sj, Cout and rout.
The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA
ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only
on t₁ and to in the first place:
t₁ to Description
00
Output Relationship
Ignored
Inputs
Addition Mode
2 Coutsjaj + bj + Cin, Tout= 0
Tin
0 1
Shift Left Mode
Sj = Cin,
Cout=bj, rout = 0
rin, aj
10
1 1
Shift Right…
Chapter 10 Solutions
Computer Science: An Overview (13th Edition) (What's New in Computer Science)
Ch. 10.1 - Prob. 1QECh. 10.1 - Prob. 2QECh. 10.1 - Prob. 3QECh. 10.2 - Prob. 1QECh. 10.2 - Prob. 2QECh. 10.2 - Prob. 3QECh. 10.3 - Prob. 1QECh. 10.3 - Prob. 2QECh. 10.3 - Prob. 3QECh. 10.3 - Prob. 4QE
Ch. 10.3 - Prob. 5QECh. 10.4 - Prob. 1QECh. 10.4 - Prob. 2QECh. 10.4 - Prob. 3QECh. 10.4 - Prob. 4QECh. 10.4 - Prob. 5QECh. 10.5 - Prob. 1QECh. 10.5 - Prob. 2QECh. 10.5 - Prob. 3QECh. 10.5 - Prob. 4QECh. 10.6 - Prob. 1QECh. 10.6 - What is a storyboard?Ch. 10.6 - Prob. 3QECh. 10.6 - Prob. 4QECh. 10 - Prob. 1CRPCh. 10 - Prob. 2CRPCh. 10 - Prob. 3CRPCh. 10 - Prob. 4CRPCh. 10 - Prob. 5CRPCh. 10 - Prob. 6CRPCh. 10 - Prob. 7CRPCh. 10 - Prob. 8CRPCh. 10 - Prob. 9CRPCh. 10 - Prob. 10CRPCh. 10 - Prob. 11CRPCh. 10 - Prob. 12CRPCh. 10 - Prob. 13CRPCh. 10 - Prob. 14CRPCh. 10 - Prob. 15CRPCh. 10 - Prob. 16CRPCh. 10 - Prob. 17CRPCh. 10 - Prob. 18CRPCh. 10 - Prob. 19CRPCh. 10 - Prob. 20CRPCh. 10 - Prob. 21CRPCh. 10 - Prob. 22CRPCh. 10 - Prob. 23CRPCh. 10 - Prob. 24CRPCh. 10 - Prob. 25CRPCh. 10 - Prob. 26CRPCh. 10 - Prob. 27CRPCh. 10 - Prob. 28CRPCh. 10 - Prob. 29CRPCh. 10 - Prob. 30CRPCh. 10 - Prob. 31CRPCh. 10 - Prob. 32CRPCh. 10 - Prob. 33CRPCh. 10 - In what way does the hardware in a computer...Ch. 10 - Prob. 35CRPCh. 10 - Prob. 36CRPCh. 10 - Prob. 37CRPCh. 10 - Prob. 38CRPCh. 10 - Prob. 39CRPCh. 10 - Prob. 40CRPCh. 10 - Prob. 41CRPCh. 10 - Prob. 42CRPCh. 10 - Prob. 43CRPCh. 10 - Prob. 44CRPCh. 10 - Prob. 1SICh. 10 - The following questions are intended as a guide to...Ch. 10 - Prob. 3SICh. 10 - Prob. 4SI
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