BIG IDEAS MATH Integrated Math 1: Student Edition 2016
16th Edition
ISBN: 9781680331127
Author: HOUGHTON MIFFLIN HARCOURT
Publisher: Houghton Mifflin Harcourt
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 10.5, Problem 21E
To determine
To describe and correct the error in finding the distance between
Expert Solution & Answer
Explanation of Solution
Given:
Distance
The distance between
Calculation:
Error- Here, error is in finding the distance.
The given equations are the set of parallel line and the distance between the parallel lines can’t be found like the above.
The distance between two parallel lines is the length of a perpendicular segment joining the two lines.
Correction:
Find the length of perpendicular segment joining the two lines.
Chapter 10 Solutions
BIG IDEAS MATH Integrated Math 1: Student Edition 2016
Ch. 10.1 - Prob. 1ECh. 10.1 - Prob. 2ECh. 10.1 - Prob. 3ECh. 10.1 - Prob. 4ECh. 10.1 - Prob. 5ECh. 10.1 - Prob. 6ECh. 10.1 - Prob. 7ECh. 10.1 - Prob. 8ECh. 10.1 - Prob. 9ECh. 10.1 - Prob. 10E
Ch. 10.1 - Prob. 11ECh. 10.1 - Prob. 12ECh. 10.1 - Prob. 13ECh. 10.1 - Prob. 14ECh. 10.1 - Prob. 15ECh. 10.1 - Prob. 16ECh. 10.1 - Prob. 17ECh. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 22ECh. 10.1 - Prob. 23ECh. 10.1 - Prob. 24ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.1 - Prob. 29ECh. 10.1 - Prob. 30ECh. 10.1 - Prob. 31ECh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.3 - Prob. 1ECh. 10.3 - Prob. 2ECh. 10.3 - Prob. 3ECh. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Prob. 6ECh. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Prob. 9ECh. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Prob. 12ECh. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Prob. 24ECh. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - Prob. 28ECh. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - Prob. 31ECh. 10.3 - Prob. 32ECh. 10.3 - Prob. 33ECh. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 41ECh. 10.3 - Prob. 42ECh. 10.3 - Prob. 43ECh. 10.3 - Prob. 44ECh. 10.3 - Prob. 1QCh. 10.3 - Prob. 2QCh. 10.3 - Prob. 3QCh. 10.3 - Prob. 4QCh. 10.3 - Prob. 5QCh. 10.3 - Prob. 6QCh. 10.3 - Prob. 7QCh. 10.3 - Prob. 8QCh. 10.3 - Prob. 9QCh. 10.3 - Prob. 10QCh. 10.3 - Prob. 11QCh. 10.3 - Prob. 12QCh. 10.3 - Prob. 13QCh. 10.3 - Prob. 14QCh. 10.3 - Prob. 15QCh. 10.3 - Prob. 16QCh. 10.4 - Prob. 1ECh. 10.4 - Prob. 2ECh. 10.4 - Prob. 3ECh. 10.4 - Prob. 4ECh. 10.4 - Prob. 5ECh. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Prob. 10ECh. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - Prob. 16ECh. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - Prob. 27ECh. 10.4 - Prob. 28ECh. 10.4 - Prob. 29ECh. 10.4 - Prob. 30ECh. 10.4 - Prob. 31ECh. 10.4 - Prob. 32ECh. 10.4 - Prob. 33ECh. 10.4 - Prob. 34ECh. 10.4 - Prob. 35ECh. 10.4 - Prob. 36ECh. 10.4 - Prob. 37ECh. 10.4 - Prob. 38ECh. 10.4 - Prob. 39ECh. 10.4 - Prob. 40ECh. 10.4 - Prob. 41ECh. 10.5 - Prob. 1ECh. 10.5 - Prob. 2ECh. 10.5 - Prob. 3ECh. 10.5 - Prob. 4ECh. 10.5 - Prob. 5ECh. 10.5 - Prob. 6ECh. 10.5 - Prob. 7ECh. 10.5 - Prob. 8ECh. 10.5 - Prob. 9ECh. 10.5 - Prob. 10ECh. 10.5 - Prob. 11ECh. 10.5 - Prob. 12ECh. 10.5 - Prob. 13ECh. 10.5 - Prob. 14ECh. 10.5 - Prob. 15ECh. 10.5 - Prob. 16ECh. 10.5 - Prob. 17ECh. 10.5 - Prob. 18ECh. 10.5 - Prob. 19ECh. 10.5 - Prob. 20ECh. 10.5 - Prob. 21ECh. 10.5 - Prob. 22ECh. 10.5 - Prob. 23ECh. 10.5 - Prob. 24ECh. 10.5 - Prob. 25ECh. 10.5 - Prob. 26ECh. 10.5 - Prob. 27ECh. 10.5 - Prob. 28ECh. 10.5 - Prob. 29ECh. 10.5 - Prob. 30ECh. 10.5 - Prob. 31ECh. 10.5 - Prob. 32ECh. 10.5 - Prob. 33ECh. 10.5 - Prob. 34ECh. 10.5 - Prob. 35ECh. 10.5 - Prob. 36ECh. 10 - Prob. 1CRCh. 10 - Prob. 2CRCh. 10 - Prob. 3CRCh. 10 - Prob. 4CRCh. 10 - Prob. 5CRCh. 10 - Prob. 6CRCh. 10 - Prob. 7CRCh. 10 - Prob. 8CRCh. 10 - Prob. 9CRCh. 10 - Prob. 10CRCh. 10 - Prob. 11CRCh. 10 - Prob. 12CRCh. 10 - Prob. 13CRCh. 10 - Prob. 14CRCh. 10 - Prob. 15CRCh. 10 - Prob. 16CRCh. 10 - Prob. 17CRCh. 10 - Prob. 18CRCh. 10 - Prob. 19CRCh. 10 - Prob. 20CRCh. 10 - Prob. 1CTCh. 10 - Prob. 2CTCh. 10 - Prob. 3CTCh. 10 - Prob. 4CTCh. 10 - Prob. 5CTCh. 10 - Prob. 6CTCh. 10 - Prob. 7CTCh. 10 - Prob. 8CTCh. 10 - Prob. 9CTCh. 10 - Prob. 10CTCh. 10 - Prob. 11CTCh. 10 - Prob. 12CTCh. 10 - Prob. 13CTCh. 10 - Prob. 1CACh. 10 - Prob. 2CACh. 10 - Prob. 3CACh. 10 - Prob. 4CACh. 10 - Prob. 5CACh. 10 - Prob. 6CACh. 10 - Prob. 7CACh. 10 - Prob. 8CACh. 10 - Prob. 9CA
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.Similar questions
- 7. From a point 20 m away on a level ground, the angle of elevation to the bottom of a the top of the window is 32°. Calculate the window is 27° and the angle of elevatim height of the window. (3 marks) 32 SOUCAHTOA Rom Coso-Adj opponite 1270 H X Hyp Tant=OPP Adj 20 # Zom Adjacent CoS2E 20 XHX Tanz 20 20 K -0.0445503261 -1.764201788 0-044550326 60044550320 (1 mark) 3960 8. All odd numbers from 1 to 10 are arranged in descending order to form a number. (i) Write the number. 35798. 97531 31 (ii) Write the total value of the second digit of the number formed in (a) (i) FA 7X1000-7000 이 (1 mark) 9. A cylinder has a diameter of 28 cm and the height is 18 cm. Calculate its volume. 2 22 × 14 × 14 × 18 -110880m 3 (3 marks) 10. The figure below shows a right pyramid with AB = 3 cm, BC = 5 cm, and AV VC = VD = 4 cm. Draw its net. V 3+ 12 7/18 (2/20 2105 SSS 20arrow_forwardNo chatgpt pls will upvotearrow_forwardFind an nfa that accepts the language L(aa (a + b)). Create and test the NFA in Jflap. Test the strings: aab, ab, aaaa, aaaab, baab, aa, abbbb, a, b, 1. Submit the Jflap diagram and the Jflap test cases. 4. Find an nfa that accepts the language L (aa* (a+b)).arrow_forward
- CVE, AVM, AC, ¬SA¬ME A Fitch Style proof for this argumentarrow_forward13:26 ... ← Robert F. Blitzer - Thinkin... 0,04 61 KB/d 目 polygons to create a fraudulent tessellation with discrepancies that are too subtle for the eye to notice. In Exercises 45-46, you will use mathematics, not your eyes, to observe the irregularities. B A 45. Find the sum of the angle measures at vertex A. Then explain why the tessellation is a fake. 46. Find the sum of the angle measures at vertex B. Then explain why the tessellation is a fake. =et at If se Fic SECTION 10.3 Polygons, Perimeter, and Tessellations 645 61. I find it helpful to think of a polygon's perimeter as the length of its boundary. 62. If a polygon is not regular, I can determine the sum of the measures of its angles, but not the measure of any one of its angles. 63. I used floor tiles in the shape of regular pentagons to completely cover my kitchen floor. In Exercises 64-65, write an algebraic expression that represents the perimeter of the figure shown. is be 64. le a b C 2/ If se nyarrow_forwardnot use ai please don'tarrow_forward
- pls helparrow_forwardUse the formulas developed in this section to find the area of the figure. A= (Simplify your answer.) 8.5 m 7 T 13 m 7.7 m m 21 marrow_forwardFind the circumference and area of the circle. Express answers in terms of and then round to the nearest tenth. Find the circumference in terms of C = (Type an exact answer in terms of л.) 9 cmarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Discrete Mathematics and Its Applications ( 8th I...MathISBN:9781259676512Author:Kenneth H RosenPublisher:McGraw-Hill Education
Mathematics for Elementary Teachers with Activiti...MathISBN:9780134392790Author:Beckmann, SybillaPublisher:PEARSON
Thinking Mathematically (7th Edition)MathISBN:9780134683713Author:Robert F. BlitzerPublisher:PEARSON
Discrete Mathematics With ApplicationsMathISBN:9781337694193Author:EPP, Susanna S.Publisher:Cengage Learning,
Pathways To Math Literacy (looseleaf)MathISBN:9781259985607Author:David Sobecki Professor, Brian A. MercerPublisher:McGraw-Hill Education
Discrete Mathematics and Its Applications ( 8th I...
Math
ISBN:9781259676512
Author:Kenneth H Rosen
Publisher:McGraw-Hill Education
Mathematics for Elementary Teachers with Activiti...
Math
ISBN:9780134392790
Author:Beckmann, Sybilla
Publisher:PEARSON
Thinking Mathematically (7th Edition)
Math
ISBN:9780134683713
Author:Robert F. Blitzer
Publisher:PEARSON
Discrete Mathematics With Applications
Math
ISBN:9781337694193
Author:EPP, Susanna S.
Publisher:Cengage Learning,
Pathways To Math Literacy (looseleaf)
Math
ISBN:9781259985607
Author:David Sobecki Professor, Brian A. Mercer
Publisher:McGraw-Hill Education
What is a Linear Equation in One Variable?; Author: Don't Memorise;https://www.youtube.com/watch?v=lDOYdBgtnjY;License: Standard YouTube License, CC-BY
Linear Equation | Solving Linear Equations | What is Linear Equation in one variable ?; Author: Najam Academy;https://www.youtube.com/watch?v=tHm3X_Ta_iE;License: Standard YouTube License, CC-BY