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Comparison tests Use the Comparison Test or the Limit Comparison Test to determine whether the following series converge.
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Calculus: Early Transcendentals (3rd Edition)
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- We want to use the Basic Comparison Test (sometimes called the Direct Comparison Test or just the Comparison Test) to determine if the series: k5 16 - converges or diverges by comparing it with: k We can conclude that: The first series diverges by comparison with the second series. The Basic Comparison Test is inconclusive in this situation. O The first series converges by comparison with the second series.arrow_forwardA FINAL EXAM TO BE COMPLETED INDEPENDENTLY. 13. Consider the four p-series listed below. Briefly explain whether each series converges or diverges. (a) 2n-1 no3 (b) 1n-4 1 (c) En 1 (d) E -1arrow_forwardselect the correct answer and explain step by steparrow_forward
- n3 Use the limit comparison test with the p-series to determine whether S 2n5 – 4n – 1 converges or diverges. n=2 The limit comparison test cannot be applied to these two series. S converges. S diverges. The test is inconclusive.arrow_forwardn3 + 2 1. (15 p) Determine if the series converges or diverges. +3 n=1 Give reason for your answer.arrow_forwardchoices: a. true b. false c. others (specify) 1. Stationary series are series with roughly horizontal with constant variance. 2.A non-stationary series the ACF drops to zero quickly. 3. The PACF of the stationary series is decaying exponentially,arrow_forward
- determine if series is convergence or divergent and identify which test you usearrow_forward00 Does the seriesE(- 1n+12+n° n4 converge absolutely, converge conditionally, or diverge? n= 1 Choose the correct answer below and, if necessary, fill in the answer box to complete your choice. O A. The series converges absolutely per the Comparison Test with > 00 n4 n= 1 B. The series diverges because the limit used in the Ratio Test is not less than or equal to 1. OC. The series converges conditionally per the Alternating Series Test and the Comparison Test with n= 1 D. The series converges absolutely because the limit used in the nth-Term Test is E. The series diverges because the limit used in the nth-Term Test does not exist. O F. The series converges conditionally per the Alternating Series Test and because the limit used in the Ratio Test isarrow_forward5. Does the series n=1 n+2n+1 converge? Explain. Upload Choose a File Question 6 6. Does the series n=1 nn converge? Explain. m%3D1 Upload Choose a Filearrow_forward
- Find the interval of convergence for the given power series. (x - 4)" Σ n(- 9)" n=1 The series is convergent from x = left end included (enter Y or N): to x = right end included (enter Y or N): M C ㅈ # $ A de L % 5 6 D 8 7 8 9 #arrow_forwarddevsi subject-Accountingarrow_forwardDetermine the lonvergence or divergence ofeach Series. Jushify your Ansuar (a) 2nt1 Inn n=2 2N (e) n? +4arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
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