Explanation Given: According to the study 38% of US employees reports being very satisfied with their jobs and in the same study 51% indicated they are satisfied but to a lesser degree. Formula Used: For the binomial distribution, the mean is as follows: μ = n p For the binomial distribution, the standard deviation is: σ = n p ( 1 − p ) Here, n is the number of trials and p is the probability of success on a single trial. Calculation: Consider X be the random variable defined by: Represents that the Employee is satisfied but to a lesser degree. X = 1 Represents that the Employee is satisfied but with higher degree or not satisfied. X = 0 Therefore the random variable is binomially distributed. According to the study 51% of US employees is satisfied but to a lesser degree hence P ( X = 1 ) = 51 % p = 51 ( 1 100 ) p = 0

Pearson eText for Mathematics with Applications In the Management, Natural, and Social Sciences -- Instant Access (Pearson+)

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Author: Margaret Lial, Thomas Hungerford

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Chapter 10.4, Problem 52E

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Chapter 10.4, Problem 51E

Chapter 10.4, Problem 53E

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Pearson eText for Mathematics with Applications In the Management, Natural, and Social Sciences -- Instant Access (Pearson+)

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The mean and standard deviation for the number of people those are satisfied to a lesser degree.

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Chapter 10 Solutions