Explanation Given: According to the study 38% of US employees reports being very satisfied with their jobs and in the same study 51% indicated they are satisfied but to a lesser degree. Formula Used: For the binomial distribution, the mean is as follows: μ = n p For the binomial distribution, the standard deviation is: σ = n p ( 1 − p ) Here, n is the number of trials and p is the probability of success on a single trial. Calculation: Consider X be the random variable defined by: Represents that the Employee is very satisfied as: X = 1 Represents that the Employee is not satisfied as: X = 0 Therefore the random variable is binomially distributed: According to the study 38% of US employees reports being very satisfied is: P ( X = 1 ) = 38 % p = 38 ( 1 100 ) p = 0

Pearson eText for Mathematics with Applications In the Management, Natural, and Social Sciences -- Instant Access (Pearson+)

12th Edition

ISBN: 9780137504381

Author: Margaret Lial, Thomas Hungerford

Publisher: PEARSON+

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Chapter 10.4, Problem 51E

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To calculate: The mean and standard deviation for the number of very satisfied employees if 200 employees are randomly selected.

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Chapter 10.4, Problem 50E

Chapter 10.4, Problem 52E

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Chapter 10 Solutions

Pearson eText for Mathematics with Applications In the Management, Natural, and Social Sciences -- Instant Access (Pearson+)

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Using Chebyshev’s theorem and the normal...Ch. 10.4 - Prob. 21E Ch. 10.4 - Prob. 22E Ch. 10.4 - Prob. 23E Ch. 10.4 - Prob. 24E Ch. 10.4 - Prob. 25E Ch. 10.4 - Prob. 26E Ch. 10.4 - Prob. 27E Ch. 10.4 - Prob. 28E Ch. 10.4 - Prob. 29E Ch. 10.4 - Prob. 30E Ch. 10.4 - Prob. 31E Ch. 10.4 - Prob. 32E Ch. 10.4 - Prob. 33E Ch. 10.4 - Prob. 34E Ch. 10.4 - Prob. 35E Ch. 10.4 - Prob. 36E Ch. 10.4 - Prob. 37E Ch. 10.4 - Prob. 38E Ch. 10.4 - Prob. 39E Ch. 10.4 - Prob. 40E Ch. 10.4 - Prob. 41E Ch. 10.4 - Prob. 42E Ch. 10.4 - Prob. 43E Ch. 10.4 - Prob. 44E Ch. 10.4 - Prob. 45E Ch. 10.4 - Prob. 46E Ch. 10.4 - Prob. 47E Ch. 10.4 - Prob. 48E Ch. 10.4 - Prob. 49E Ch. 10.4 - Education The mean performance score of a large...Ch. 10.4 - Prob. 51E Ch. 10.4 - Prob. 52E Ch. 10.4 - Job Satisfaction According to a 2016 study...Ch. 10.4 - Prob. 54E Ch. 10.4 - Prob. 55E Ch. 10.4 - Prob. 56E Ch. 10.4 - Prob. 57E Ch. 10.4 - Prob. 58E Ch. 10.4 - Student Loan Debt According to a report from the...Ch. 10.4 - Prob. 60E Ch. 10.4 - Prob. 61E Ch. 10.4 - Prob. 62E Ch. 10 - NASDAQ 100 Stocks For Exercises 1-10, the data...Ch. 10 - Prob. 2RE Ch. 10 - Prob. 3RE Ch. 10 - Prob. 4RE Ch. 10 - Prob. 5RE Ch. 10 - Prob. 6RE Ch. 10 - NASDAQ 100 Stocks For Exercises 1-10, the data...Ch. 10 - Prob. 8RE Ch. 10 - Prob. 9RE Ch. 10 - Prob. 10RE Ch. 10 - Prob. 11RE Ch. 10 - Prob. 12RE Ch. 10 - Prob. 13RE Ch. 10 - Prob. 14RE Ch. 10 - Prob. 15RE Ch. 10 - Prob. 16RE Ch. 10 - Prob. 17RE Ch. 10 - Prob. 18RE Ch. 10 - Prob. 19RE Ch. 10 - Prob. 20RE Ch. 10 - Prob. 21RE Ch. 10 - Prob. 22RE Ch. 10 - Prob. 23RE Ch. 10 - Prob. 24RE Ch. 10 - Find the standard deviation for each of the given...Ch. 10 - Prob. 26RE Ch. 10 - Prob. 27RE Ch. 10 - Prob. 28RE Ch. 10 - Prob. 29RE Ch. 10 - Prob. 30RE Ch. 10 - Prob. 31RE Ch. 10 - Prob. 32RE Ch. 10 - Prob. 33RE Ch. 10 - Prob. 34RE Ch. 10 - Prob. 35RE Ch. 10 - Prob. 36RE Ch. 10 - Arm Circumference Data from a recent National...Ch. 10 - Prob. 38RE Ch. 10 - Prob. 39RE Ch. 10 - Prob. 40RE Ch. 10 - Prob. 41RE Ch. 10 - Prob. 42RE Ch. 10 - Prob. 43RE Ch. 10 - Prob. 44RE Ch. 10 - Prob. 45RE Ch. 10 - Prob. 46RE Ch. 10 - Prob. 47RE Ch. 10 - College or University Education A recent...Ch. 10 - College or University Education A recent...Ch. 10 - Prob. 50RE Ch. 10 - Prob. 51RE Ch. 10 - Prob. 52RE Ch. 10 - Prob. 53RE Ch. 10 - Prob. 54RE Ch. 10 - Prob. 1CE Ch. 10 - Prob. 2CE Ch. 10 - Prob. 3CE Ch. 10 - Prob. 4CE Ch. 10 - Prob. 5CE Ch. 10 - Prob. 6CE Ch. 10 - Prob. 7CE Ch. 10 - Prob. 8CE Ch. 10 - Prob. 9CE Ch. 10 - Prob. 10CE

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The mean and standard deviation for the number of very satisfied employees if 200 employees are randomly selected.

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Chapter 10 Solutions