Management training. Each year a company selects 5 employees for a management training program at a university. On average, 40 % of those sent complete the course in the top 10 % of their class. If we consider an employee finishing in the top 10 % of the class a success in a binomial experiment, then for the 5 employees entering the program, there exists a binomial distribution involving P ( x successes out of 5 ).For the binomial distribution, (A) Write the probability function. (B) Construct a table. (C) Draw a histogram. (D) Compute the mean and standard deviation
Management training. Each year a company selects 5 employees for a management training program at a university. On average, 40 % of those sent complete the course in the top 10 % of their class. If we consider an employee finishing in the top 10 % of the class a success in a binomial experiment, then for the 5 employees entering the program, there exists a binomial distribution involving P ( x successes out of 5 ).For the binomial distribution, (A) Write the probability function. (B) Construct a table. (C) Draw a histogram. (D) Compute the mean and standard deviation
Solution Summary: The author analyzes the probability function of a company selecting 5 employees for management training out of every batch.
Management training. Each year a company selects
5
employees for a management training program at a university. On average,
40
%
of those sent complete the course in the top
10
%
of their class. If we consider an employee finishing in the top
10
%
of the class a success in a binomial experiment, then for the
5
employees entering the program, there exists a binomial distribution involving
P
(
x
successes out of
5
).For the binomial distribution,
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.