Chapter 10.4, Problem 26STQ

Explanation of Solution

 Exception thrown when opening a binary file for output:

 When opening a binary file for output, the “FileNotFoundException” and “IOException” will be thrown.

• A “FileNotFoundException” would be thrown if the file could not be opened because, there is already a folder named which was given by the user.
  • This exception can be thrown when an application tries to open a file for writing, but that file only for read, or the permissions of the file don’t allow the file to be read by any application.
• An “IOException” is thrown when there is any input/ output file operation issues while application performing particular tasks accessing the files.
  • A “FileNotFoundException” is one of the sub class of an “IOException”.

 Example:

 Consider an example for the above snippet,

//include requried header files

import java.io.FileInputStream;

import java.io.FileNotFoundException;

import java.io.ObjectInputStream;

import java.io.IOException;

import java.util.Scanner;

//definition of "ReadFile" class

public class ReadFile

{

    //definition of main method

public static void main(String[] args)throws Exception

    {

        //declare and set the value to the variable

        String filename = null;

        //try block

        try

        {

            //create an object for scanner class

            Scanner x = new Scanner (System.in);

            //get the file name from the user

System.out.println("Enter the file name: ");

            filename = x.next();

/*create an object for "ObjectInputStream" stream class*/

ObjectInputStream inputStream = new ObjectInputStream(new FileInputStream(filename));

            //display the statement

System.out.println("The first thing in the file " + filename + " is");

            //read the input string

            String f = inputStream...