a.
To calculate: The tension required to produce a frequency of about 330 cycles per second.
a.
Answer to Problem 83E
The required tension is 71.55 Newtons.
Explanation of Solution
Given information:
The equation of frequency f :
The length of the E string = 0.64 meter
The mass of the string = 0.000401 kilogram per meter
The given equation of frequency is
The length of the E string is 0.64 meter.
So,
The mass of the string is 0.000401 kilogram per meter.
So,
Substitute 330 for f , 0.64 for l and 0.000401 for m in the equation
Hence, the required tension is 71.55 Newtons.
b.
To find: Whether the tension needed to create the same frequency on a string with greater mass per unit length is more or less.
b.
Answer to Problem 83E
The tension is needed to be more.
Explanation of Solution
Given information:
The equation of frequency f :
The length of the E string = 0.64 meter
The mass of the string = 0.000401 kilogram per meter
The given equation of frequency is
It is seen that in the above equation T and m are in ratio.
So, if one of the quantities increases then the other quantity will also increase so that the ratio remains constant.
Hence, the tension is needed to be more.
Chapter 10 Solutions
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