Chapter 10.3, Problem 60E

To determine

Solve the equation.

Answer to Problem 60E

There is no error.

Explanation of Solution

Given information: $x=\sqrt{12-4x}$

Formula Used: Factorization

Calculation:

  $x=\sqrt{12-4x}$

Now, squaring both sides

  $x^2={\left(\sqrt{12-4x}\right)}^2$

So,

  $x^2=12-4x$

Now, equate

  $x^2+4x-12=0$

Now, factorize

  $x^2+6x-2x-12=0$

So,

  $x\left(x+6\right)-2\left(x+6\right)=0$

Now,

  $\left(x+6\right)\left(x-2\right)=0$

Hence,

  $x=-6$ Or $x=2$