Statics and Mechanics of Materials, Student Value Edition (5th Edition)
5th Edition
ISBN: 9780134382890
Author: Russell C. Hibbeler
Publisher: PEARSON
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Chapter 10.3, Problem 33P
To determine
Find the maximum shear stress in the region CF and BC of the shaft.
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Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to find
Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of the
Chapter 10 Solutions
Statics and Mechanics of Materials, Student Value Edition (5th Edition)
Ch. 10.3 - Determine the internal torque at each section and...Ch. 10.3 - Determine the internal torque at each section and...Ch. 10.3 - Prob. 3PPCh. 10.3 - Prob. 4PPCh. 10.3 - Prob. 1FPCh. 10.3 - The hollow circular shaft is subjected to an...Ch. 10.3 - Prob. 3FPCh. 10.3 - Prob. 4FPCh. 10.3 - Determine the maximum shear stress in the shaft at...Ch. 10.3 - Prob. 6FP
Ch. 10.3 - The solid 50-mm-diameter shaft is subjected to the...Ch. 10.3 - Prob. 8FPCh. 10.3 - Prob. 1PCh. 10.3 - Prob. 2PCh. 10.3 - A shaft is made of an aluminum alloy having an...Ch. 10.3 - The copper pipe has an outer diameter of 40 mm and...Ch. 10.3 - The copper pipe has an outer diameter of 2.50 in....Ch. 10.3 - The solid aluminum shaft has a diameter of 50 mm...Ch. 10.3 - The solid aluminum shaft has a diameter of 50 mm....Ch. 10.3 - The solid 30-mm-diameter shaft is used to transmit...Ch. 10.3 - The solid shaft is fixed to the support at C and...Ch. 10.3 - The link acts as part of the elevator control for...Ch. 10.3 - The assembly consists of two sections of...Ch. 10.3 - The shaft has an outer diameter of 100 mm and an...Ch. 10.3 - Prob. 13PCh. 10.3 - Prob. 14PCh. 10.3 - Prob. 15PCh. 10.3 - Prob. 16PCh. 10.3 - The rod has a diameter of 1 in. and a weight of 10...Ch. 10.3 - Prob. 18PCh. 10.3 - Prob. 19PCh. 10.3 - Prob. 20PCh. 10.3 - Prob. 21PCh. 10.3 - The 60-mm-diametcr solid shaft is subjected to the...Ch. 10.3 - Prob. 23PCh. 10.3 - The 60-mm-diameter solid shaft is subjected to the...Ch. 10.3 - Prob. 25PCh. 10.3 - The pump operates using the motor that has a power...Ch. 10.3 - Prob. 27PCh. 10.3 - Prob. 28PCh. 10.3 - Prob. 29PCh. 10.3 - The gear motor can develop 2 hp when it turns at...Ch. 10.3 - Prob. 31PCh. 10.3 - The 6-hp reducer motor can turn at 1200 rev/min....Ch. 10.3 - Prob. 33PCh. 10.3 - Prob. 34PCh. 10.4 - The 60-mm-diameter steel shaft is subjected to the...Ch. 10.4 - Prob. 10FPCh. 10.4 - The hollow 6061-T6 aluminum shaft has an outer and...Ch. 10.4 - A series of gears are mounted on the...Ch. 10.4 - Prob. 13FPCh. 10.4 - The 80-mm-diameter shaft is made of steel. If it...Ch. 10.4 - The propellers of a ship are connected to an A-36...Ch. 10.4 - Prob. 36PCh. 10.4 - The splined ends and gears attached to the A992...Ch. 10.4 - Prob. 38PCh. 10.4 - The 60-mm-diameter shaft is made of 6061-T6...Ch. 10.4 - The 60-mm-diameter shaft is made of 6061-T6...Ch. 10.4 - Prob. 41PCh. 10.4 - Prob. 42PCh. 10.4 - Gear B supplies 15 kW of power, while gears A, C,...Ch. 10.4 - Prob. 44PCh. 10.4 - The turbine develops 150 kW of power, which is...Ch. 10.4 - Prob. 46PCh. 10.4 - Prob. 47PCh. 10.4 - Prob. 48PCh. 10.4 - The A 992 steel shaft has a diameter of 50 mm and...Ch. 10.4 - The turbine develops 300 kW of power, which is...Ch. 10.4 - Prob. 51PCh. 10.4 - The device shown is used to mix soils in order to...Ch. 10.4 - The 6-in.-diameter L-2 steel shaft on the turbine...Ch. 10.4 - The A-36 hollow steel shaft is 2 m long and has an...Ch. 10.4 - The A-36 solid steel shaft is 3 m long and has a...Ch. 10.4 - Prob. 56PCh. 10.4 - Prob. 57PCh. 10.4 - Prob. 58PCh. 10.4 - The tubular drive shaft for the propeller of a...Ch. 10.4 - The 60-mm diameter solid shaft is made of 2014-T6...Ch. 10.4 - Prob. 61PCh. 10.5 - The steel shaft has a diameter of 40 mm and is...Ch. 10.5 - The A992 steel shaft has a diameter of 60 mm and...Ch. 10.5 - The steel shaft is made from two segments: AC has...Ch. 10.5 - The bronze C86100 pipe has an outer diameter of...Ch. 10.5 - The bronze C86100 pipe has an outer diameter of...Ch. 10.5 - Prob. 67PCh. 10.5 - Prob. 68PCh. 10.5 - The Am1004-T61 magnesium tube is bonded to the...Ch. 10.5 - The Am1004-T61 magnesium tube is bonded to the...Ch. 10.5 - The two shafts are made of A-36 steel. Each has a...Ch. 10.5 - Prob. 72PCh. 10.5 - Prob. 73PCh. 10.5 - Prob. 74PCh. 10.5 - Prob. 75PCh. 10.5 - The composite shaft consists of a mid-section that...Ch. 10.5 - Prob. 77PCh. 10.5 - The tapered shaft is confined by the fixed...Ch. 10.5 - Prob. 79PCh. 10 - The shaft is made of A992 steel and has an...Ch. 10 - The shaft is made of A992 steel and has an...Ch. 10 - The A-36 steel circular tube is subjected to a...Ch. 10 - Prob. 4RPCh. 10 - Prob. 5RPCh. 10 - Prob. 6RPCh. 10 - Prob. 7RPCh. 10 - Prob. 8RPCh. 10 - The 60-mm-diameter shaft rotates at 300 rev/min....
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- Procedure: 1- Cartesian system, 2D3D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D ∑Fx=0 ∑Fy=0 ∑Fz=0 ∑Mx=0 ∑My=0 ΣMz=0 2D ΣFx=0 ΣFy=0 ΣMz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of thearrow_forwardProcedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
- Procedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardFor each system below with transfer function G(s), plot the pole(s) on the s-plane. and indicate whether the system is: (a) "stable" (i.e., a bounded input will always result in a bounded output), (b) "marginally stable," or (c) "unstable" Sketch a rough graph of the time response to a step input. 8 a) G(s) = 5-5 8 b) G(s) = c) G(s) = = s+5 3s + 8 s² - 2s +2 3s +8 d) G(s): = s²+2s+2 3s+8 e) G(s): = s² +9 f) G(s): 8 00 == Sarrow_forwardPlease answer the following question. Include all work and plase explain. Graphs are provided below. "Consider the Mg (Magnesium) - Ni (Nickel) phase diagram shown below. This phase diagram contains two eutectic reactions and two intermediate phases (Mg2Ni and MgNi2). At a temperature of 505oC, determine what the composition of an alloy would need to be to contain a mass fraction of 0.20 Mg and 0.80 Mg2Ni."arrow_forward
- The triangular plate, having a 90∘∘ angle at AA, supports the load PP = 370 lblb as shown in (Figure 1).arrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, ß2 = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. φ 1.236 P2 147.5° 210° 2.138 P1 Figure 1 Xarrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, B₂ = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. 1.236 P2 147.5° 210° P1 Figure 1 2.138 Xarrow_forward
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