a . Show that the function f ( x ) = x 2 has the Fourier series, on − π < x < π , f ( x ) ∼ π 2 3 + 4 ∑ n = 1 ∞ ( − 1 ) n n 2 cos n x . b . Use the result of part (a) and Theorem 2 to show that ∑ n = 1 ∞ ( − 1 ) n + 1 n 2 = π 2 12 . c . Use the result of part (a) and Theorem 2 to show that ∑ n = 1 ∞ 1 n 2 = π 2 6 .
a . Show that the function f ( x ) = x 2 has the Fourier series, on − π < x < π , f ( x ) ∼ π 2 3 + 4 ∑ n = 1 ∞ ( − 1 ) n n 2 cos n x . b . Use the result of part (a) and Theorem 2 to show that ∑ n = 1 ∞ ( − 1 ) n + 1 n 2 = π 2 12 . c . Use the result of part (a) and Theorem 2 to show that ∑ n = 1 ∞ 1 n 2 = π 2 6 .
Solution Summary: The author explains the Fourier series formula: f(x)=a_02+displaystyle
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