For the PDE in Problem 27 , assume that the following boundary conditions are imposed: u ( r , 0 ) = u ( r , π ) = 0 u ( r , θ ) remains bounded as r → 0 + . Show that a nontrivial solution of the form u ( r , θ ) = R ( r ) θ ( θ ) must satisfy the boundary conditions θ ( 0 ) = θ ( π ) = 0 , R ( r ) remains bounded as r → 0 + . ∂ 2 u ∂ r 2 + 1 r ∂ u ∂ r + 1 r 2 ∂ 2 u ∂ θ 2 = 0 With u ( r , θ ) = R ( r ) θ ( θ ) yields r 2 R ″ ( r ) + r R ′ ( r ) − λ R ( r ) = 0 , θ ″ ( θ ) + λ θ ( θ ) = 0 , Where λ is a constant.
For the PDE in Problem 27 , assume that the following boundary conditions are imposed: u ( r , 0 ) = u ( r , π ) = 0 u ( r , θ ) remains bounded as r → 0 + . Show that a nontrivial solution of the form u ( r , θ ) = R ( r ) θ ( θ ) must satisfy the boundary conditions θ ( 0 ) = θ ( π ) = 0 , R ( r ) remains bounded as r → 0 + . ∂ 2 u ∂ r 2 + 1 r ∂ u ∂ r + 1 r 2 ∂ 2 u ∂ θ 2 = 0 With u ( r , θ ) = R ( r ) θ ( θ ) yields r 2 R ″ ( r ) + r R ′ ( r ) − λ R ( r ) = 0 , θ ″ ( θ ) + λ θ ( θ ) = 0 , Where λ is a constant.
Solution Summary: The author explains that the nontrivial solution of the form u(r,theta )=R left (r ) thet
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