Nonlinear Dynamics and Chaos
2nd Edition
ISBN: 9780813349107
Author: Steven H. Strogatz
Publisher: PERSEUS D
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Question
Chapter 10.1, Problem 14E
Interpretation Introduction
Interpretation:
To prove that
Concept Introduction:
➢ Determine the fixed points for the given equation and its stability.
➢ Plot the graph for the equation and compute numerical values.
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Students have asked these similar questions
For the Big-M tableau (of a maximization LP and row0 at bottom and M=1000),
Z
Ꮖ 1
x2
x3
81
82
83
e4
a4
RHS
0
7
0
0
1
0 4
3
-3
20
0
-4.5
0
0
0
1
-8 -2.5
2.5
6
0
7
0
1
0
0 8
3
-3
4
0
-1
50
1
0
0
0-2
-1
1
4
0000
0
30 970 200
If the original value of c₁ is increased by 60, what is the updated value of c₁ (meaning keeping the same set for BV. -10?
Having made that change, what is the new optimal value for ž?
Here is the optimal tableau for a standard Max problem.
zx1
x2
x3
24
81
82
83
rhs
1
0
5
3
0
6
0
1
.3
7.5 0
-
.1
.2
0 0
28
360
0
-8
522
0
2700
0
6
12
1
60
0
0
-1/15-3
1
1/15 -1/10 0
2
Using that the dual solution y = CBy B-1 and finding B = (B-¹)-¹
we find the original CBV and rhs b.
The allowable increase for b₂ is
If b₂ is increased by 3 then, using Dual Theorem, the new value for * is
If c₂ is increased by 10, then the new value for optimal > is
i.e. if no change to BV, then just a change to profit on selling product 2.
The original coefficients c₁ =
=☐ a
and c4 = 5
If c4 is changed to 512, then (first adjusting other columns of row0 by adding Delta times row belonging to x4
or using B-matrix method to update row0)
the new optimal value, after doing more simplex algorithm, for > is
Please show in mathematical form.
Chapter 10 Solutions
Nonlinear Dynamics and Chaos
Ch. 10.1 - Prob. 1ECh. 10.1 - Prob. 2ECh. 10.1 - Prob. 3ECh. 10.1 - Prob. 4ECh. 10.1 - Prob. 5ECh. 10.1 - Prob. 6ECh. 10.1 - Prob. 7ECh. 10.1 - Prob. 8ECh. 10.1 - Prob. 9ECh. 10.1 - Prob. 10E
Ch. 10.1 - Prob. 11ECh. 10.1 - Prob. 12ECh. 10.1 - Prob. 13ECh. 10.1 - Prob. 14ECh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.3 - Prob. 1ECh. 10.3 - Prob. 2ECh. 10.3 - Prob. 3ECh. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Prob. 6ECh. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Prob. 9ECh. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Prob. 12ECh. 10.3 - Prob. 13ECh. 10.4 - Prob. 1ECh. 10.4 - Prob. 2ECh. 10.4 - Prob. 3ECh. 10.4 - Prob. 4ECh. 10.4 - Prob. 5ECh. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Prob. 10ECh. 10.4 - Prob. 11ECh. 10.5 - Prob. 1ECh. 10.5 - Prob. 2ECh. 10.5 - Prob. 3ECh. 10.5 - Prob. 4ECh. 10.5 - Prob. 5ECh. 10.5 - Prob. 6ECh. 10.5 - Prob. 7ECh. 10.6 - Prob. 1ECh. 10.6 - Prob. 2ECh. 10.6 - Prob. 3ECh. 10.6 - Prob. 4ECh. 10.6 - Prob. 5ECh. 10.6 - Prob. 6ECh. 10.7 - Prob. 1ECh. 10.7 - Prob. 2ECh. 10.7 - Prob. 3ECh. 10.7 - Prob. 4ECh. 10.7 - Prob. 5ECh. 10.7 - Prob. 6ECh. 10.7 - Prob. 7ECh. 10.7 - Prob. 8ECh. 10.7 - Prob. 9ECh. 10.7 - Prob. 10ECh. 10.7 - Prob. 11E
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