Concept explainers
(a)
Interpretation:
The Lewis structure of
Concept introduction:
To draw the Lewis structure of the molecule there are following steps:
Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.
Step 2: Calculate the total number of valence electrons.
Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.
Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.
(b)
Interpretation:
The Lewis structure of the
Concept introduction:
To draw the Lewis structure of the molecule there are following steps:
Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.
Step 2: Calculate the total number of valence electrons
Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.
Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons
(c)
Interpretation:
The Lewis structure of the
Concept introduction:
To draw the Lewis structure of the molecule with multiple bonds electrons there are following steps:
Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.
Step 2: Calculate the total number of valence electrons
Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.
Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons
Step 5: Convert the lone pair into bond pair.
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Chapter 10 Solutions
CHEM 212:CHEMISTSRY V 2
- B 1 of 2 Additional problems in preparation to Midterm #1: 1.) How can the following compounds be prepared using Diels-Alder reaction: CH3 O CN (a) (b) CN CH3 2.) What is the missing reagent in the shown reaction? H3C + ? H3C H3C CN H3C ''CN (၁) H 3.) Write the products 1,2-addition and 1,4-addition of DBr to 1,3-cyclohexadiene. Remember, D is deuterium, a heavy isotope of hydrogen. It reacts exactly like hydrogen. 4.) In the shown reaction, which will be the kinetic product and which will be the thermodynamic product? H3C CI H3C HCI H3C + 5.) Which of the following molecules is aromatic? (a) (b) (c) H 6.) Which of the following molecules is aromatic? (a) (b) (c) 7.) Write the mechanism for the shown reaction. + Ха AICI 3 CI 8.) Suggest reagents that would convert benzene into the shown compounds. CI NO2 -8-6-6-8-a (a) (b) (c) (d) (e) (a) SO3H Brarrow_forwardThe number of 2sp^2 hybridized atoms in is: A. 8; B. 6; C.4; D.2; E.0;arrow_forwardThe highest boiling compound from among the following isA. 2-methylheptane; B. 3-methylheptane; C. 2,2-dimethylhexane;D. octane; E. 2,2,3-trimethylpentanearrow_forward
- Which of the following features are found in the most stable structure ofCH5NO that does not have a CO bond?w. a π bond, x. two NH bonds, y. one OH bond, z. 3 lone pairsA. w, x; B. x, y; C. y, z; D. x, y, z; E. all of them.arrow_forwardWhich one of the following functional groups is not present in thecompound shownA. amine; B. aldehyde, C. ether; D. amide. E. ketonearrow_forwardWhich of the following formulas correspond to at least one compound inwhich resonance is important?w. C2H5N x. C3H5Br; y. C3H4; z. C4H6.A. w, x, y; B. x, y, z; C. w, x, z; D. w, y, z; E. all of themarrow_forward
- Predict the product(s) that are formed after each step for reactions 1-4. In each case, consider formation of any chiral center(s) and draw all expected stereoisomers. 1) OH 1) HBr (SN2) 2) NaOH, heat 3) BH3, THF 4) H2O2, NaOH 2) OH 1) SOCI 2, py 2) NaOEt 3) Br2, H₂O 3) OH 1) H2SO4 conc. 2) HBr, ROOR 3) KOtBu 4) OH 1) TsCl, py 2) NaOEt 3) 03 4) DMSarrow_forwardWhich of the following rings has the least strain in its most stableconformation?A. Cyclobutane; B. Cyclopentane; C. Cyclohexane; D. Cycloheptane;E. Cyclooctanearrow_forwardThe number of different carbon skeletons that have a main chain of 9carbons and an ethyl branch isA 3; B. 4; C. 5; D. 6; E. 7arrow_forward
- Q5: Classify the following pair of molecules as constitutional isomers, enantiomers, diastereomers, the same molecule, or completely different molecules. Br O CI Br OH OH 111 Br .!!!/Br F OH and ...m Br Br OH CI Br OH ་་་་་" ། ་arrow_forwardConsidering only rotation around the 1-2 bond, how many differentstaggered conformations are there of 1,2-dibromo-1,2-dichloropropane?A: 2; B. 3; C. 4; D. 6; E. more than 6.arrow_forwardcan you help me solve thisarrow_forward
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