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(a)
Interpretation:
Interpret total number of valence electrons in H-NO2.
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with other atom.
The bonds formed between two atoms by sharing of electrons are known as covalent bond. A single
Total number of valence electron for a molecule can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule such as:
For HxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
(b)
Interpretation:
Interpret total number of valence electron in CH3CHO.
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with other atom.
The bonds formed between two atoms by sharing of electrons are known as covalent bond. A single chemical bond is formed by sharing of 2 electrons while double bond is formed by sharing of 4 and triple bond is formed by sharing of 6 electrons.
Total number of valence electron for a molecule can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule such as:
For HxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
(c)
Interpretation:
Interpret total number of valence electron in PH4+ .
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with other atom.
The bonds formed between two atoms by sharing of electrons are known as covalent bond. A single chemical bond is formed by sharing of 2 electrons while double bond is formed by sharing of 4 and triple bond is formed by sharing of 6 electrons.
Total number of valence electron for a molecule can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule such as:
For HxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
(d)
Interpretation:
Interpret total number of valence electron in SO32-.
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with other atom.
The bonds formed between two atoms by sharing of electrons are known as covalent bond. A single chemical bond is formed by sharing of 2 electrons while double bond is formed by sharing of 4 and triple bond is formed by sharing of 6 electrons.
Total number of valence electron for a molecule can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule such as:
For HxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
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Chapter 10 Solutions
EBK BASIC CHEMISTRY
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- 1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forward
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